如何使用先前的选择而不是默认选择重新显示相同的下拉列表？

Question

我有两个下拉列表。如果用户仅从一个选择框中选择某些内容，我想重新呈现具有相同下拉列表的页面，除了选择的页面显示上一个选择而不是默认选择。

html 看起来像

<div>
<select name = "menu" value = "{{menu}}">
    <option value = "selected">select something</option>
    <option value = "a">a</option>
    <option value = "b">b</option>
    <option value = "c">c</option>
</select>
</div>

<div>
<select name = "location" value = "{{location}}">
    <option value = "selected">select something</option>
    <option value = "d">d</option>
    <option value = "e">e</option>
    <option value = "f">f</option>
</select>
</div>

蟒蛇看起来像 menu = self.request.get('menu') location = self.request.get('location')

    if menu!="selected" and location!="selected":
        d = Delivery(parent = delivery_key(),
                 menu = menu, location = location)
        d.put()
        deliverystatus = "success"
        self.render('page.html',
                     deliverystatus = deliverystatus, menu = menu, location = location)
    else:
       error = "please select something from both lists"
       self.render("page.html",
                   menu = menu, location = location, error = error)

当出现错误并重新呈现页面时，我会在两个框中将“选择某些内容”作为默认值。我该如何更改？

Answer 1

在 HTML 表单中，在选项中添加 if menu_value==this_option_value 打印 selected 的条件。所以是这样的：

<select name = "menu" value = "{{menu}}">
    <option value = "selected">select something</option>
    <option value = "a" <% if menu == 'a': %>selected<% end> >a</option>
    <option value = "b" <% if menu == 'b': %>selected<% end> >b</option>
    <option value = "c" <% if menu == 'c': %>selected<% end> >c</option>
</select>

您应该检查语法，但这应该会让您知道如何做。