如何将 JSON 数据发送到瓶子服务器并将值存储在 sqlite3 中？

Question

我有 JSON 文件 data.json 我想通过 curl 发送到一个瓶子服务器，然后从文件中获取值。问题是它没有在数据库中存储任何内容。如何存储通过 JSON 文件传递​​的值？

卷曲命令

curl -X POST -i -d @data.json --header "Content-Type: application/json" http://192.168.1.12:8080/

bottle.py

@route('/', method='POST')
def index():
    n1 = request.POST.get("maclist", "").strip()
    n2 = request.POST.get("signallist", "").strip()

    conn = sqlite3.connect('db/users.db')
    c = conn.cursor()
    c.execute("INSERT INTO users (MAC,SIGNAL) VALUES(?,?)", (n1,n2))

    conn.commit()
    return "Items added."

数据.json

{
    "maclist": [
        "a1:b2:c3:d4:e5:f6"
    ],
    "signallist": [
        "-25"
    ]
}

Answer 1

试试这个方法,,,

客户端

curl -X POST -i -d @data.json --header "Content-Type: application/json" http://192.168.1.12:8080/

服务器端

@route('/', method='POST')
def index():
    body = request.body.read().decode('utf8') # read directly HTTP input
    get_dict = json.loads(body) # decode json and get native python dict
    maclist = get_dict.get('maclist', [])
    signallist = get_dict.get('signallist', [])
    data_list = list(zip(maclist, signallist)) # cast to list... You should have same number of elements in both collections (maclist, signallist). Otherwise, zip() function will take collection length which is less.
    conn = sqlite3.connect('db/users.db')
    c = conn.cursor()
    c.executemany("INSERT INTO users (MAC,SIGNAL) VALUES(?,?)", data_list)

    conn.commit()
    return "Items added."

希望对你有帮助。