【问题标题】:How to send two variables in one message using Socket.io?如何使用 Socket.io 在一条消息中发送两个变量?
【发布时间】:2014-01-05 02:40:53
【问题描述】:
我有一个客户端 ID 和用户名,我希望它们都通过套接字发送。
client.userid = userid;
client.username = username;
client.emit('onconnected', { id: client.userid, name: client.username });
我试过这个,但它似乎不起作用
【问题讨论】:
标签:
javascript
node.js
express
socket.io
【解决方案1】:
你可以试试这个
io.sockets.on('connection', function (socket) {
socket.on('event_name', function(data) {
// you can try one of these three options
// this is used to send to all connecting sockets
io.sockets.emit('eventToClient', { id: userid, name: username });
// this is used to send to all connecting sockets except the sending one
socket.broadcast.emit('eventToClient',{ id: userid, name: username });
// this is used to the sending one
socket.emit('eventToClient',{ id: userid, name: username });
}
}
在客户端
socket.on('eventToClient',function(data) {
// do something with data
var id = data.id
var name = data.name // here, it should be data.name instead of data.username
});
【解决方案2】:
尝试将对象作为一个整体发送:
$('form').submit(function(){
var loginDetails={
userid : userid,
username : username
};
client.emit('sentMsg',loginDetails);
}
【解决方案3】:
您应该将一个对象传递给套接字事件。
在服务器端:
socket.emit('your-event', { name: 'Whatever', age: 18 })
在客户端:
socket.on('your-event', ({ name, age }) => {
// name: Whatever
// age: 18
})