【发布时间】:2014-12-02 00:01:33
【问题描述】:
我正在尝试实现一个系统,因为应用程序需要跨多个节点的相同用户 ID,我们在一个小的 mysql 表上进行查找,该表具有存储在自动递增表中的应用程序名称和相应的 ID。如果用户 ID 不存在,我们创建它然后返回它。由于我在使用“数据库”食谱时遇到的问题,我决定在 bash 脚本中实现 Mysql 查询,该脚本将 UID 返回到 Stdout 并让 Chef 在用户创建中使用它。作为 Mysql 脚本的参数,我们为我们正在发布的应用程序名称提供节点属性,这是在数据库中搜索的条目。
我遇到的问题是我正在尝试通过 ruby_block 设置变量,但这似乎没有被处理。 Chef 日志显示该变量没有被设置,当我从等式中完全删除 mysql 脚本时,它仍然没有被设置。据我了解,它的语法相当简单,因此可以看出为什么会失败。代码如下:
define :create_application_ids do
# Assign variable names to the parameters passed.
application = params[:application_name]
# Set the fail flag to zero.
node.default[:deploy][application][:fail] = 0
# Deploy our mysql query script to get (or create, if required) a user ID for the application
template "query_mysql.bash" do
path "/root/query_mysql.bash"
source "query_mysql.bash.erb"
owner "root"
group "root"
mode "0750"
end
ruby_block "set_app_id" do
block do
id = `/root/query_mysql.bash #{node[:deploy][application]}`
end
action :create
end
Chef::Log.info "MY-DEPLOY: The ID variable is #{id}"
# If a user and group ID has been specified in the JSON string for the
# application, then create them both.
if (defined?(id))
directory node[:deploy][application][:home_dir] do
owner "root"
group "root"
mode 0777
recursive true
action :create
end
group "#{node[:deploy][application][:group_name]}" do
gid id
only_if { `cat /etc/group | grep -E '^#{node[:deploy][application][:group_name]}:'` }
end
user "#{node[:deploy][application][:user_name]}" do
uid id
gid node[:deploy][application][:group_name]
home "#{node[:deploy][application][:home_dir]}"
shell "/sbin/nologin"
only_if { `cat /etc/passwd | grep -E '^#{node[:deploy][application][:user_name]}:'` }
end
# Create any standard directories for the user.
create_application_dirs do
application_name application
end
else
Chef::Log.info "MY: #{node[:deploy][application]}"
# Since this failed, set the fail flag to 1.
node.default[:deploy][application][:fail] = 1
log "message" do
message "MY-DEPLOY: Cannot deploy application without unique user and group ID"
level :fatal
end
end
end
我在 Chef 输出中看到了这一点:
Recipe Compile Error in /var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/recipes/repository.rb
================================================================================
NameError
---------
No resource, method, or local variable named `id' for `Chef::Recipe "repository"'
Cookbook Trace:
---------------
/var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/definitions/create_application_ids.rb:25:in `block in from_file'
/var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/recipes/repository.rb:15:in `block in from_file'
/var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/recipes/repository.rb:2:in `each'
/var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/recipes/repository.rb:2:in `from_file'
Relevant File Content:
----------------------
/var/lib/aws/opsworks/cache.stage2/cookbooks/my-deploy/definitions/create_application_ids.rb:
18: ruby_block "set_app_id" do
19: block do
20: id = `/root/query_mysql.bash #{node[:deploy][application]}`
21: end
22: action :create
23: end
24:
25>> Chef::Log.info "MY-DEPLOY: The ID variable is #{id}"
26:
27: # If a user and group ID has been specified in the JSON string for the
28: # application, then create them both.
29:
30: if (defined?(id))
31: directory node[:deploy][application][:home_dir] do
32: owner "root"
33: group "root"
34: mode 0777
[2014-10-08T00:55:49+11:00] ERROR: Running exception handlers
[2014-10-08T00:55:49+11:00] ERROR: Exception handlers complete
[2014-10-08T00:55:49+11:00] FATAL: Stacktrace dumped to /var/lib/aws/opsworks/cache.stage2/chef-stacktrace.out
[2014-10-08T00:55:50+11:00] ERROR: No resource, method, or local variable named `id' for `Chef::Recipe "repository"'
[2014-10-08T00:55:50+11:00] FATAL: Chef::Exceptions::ChildConvergeError: Chef run process exited unsuccessfully (exit code 1)
【问题讨论】:
-
如果您在配方基础范围内创建
id变量并通过ruby_block分配它会发生什么?不能在日志中使用,因为离开ruby_block后就不存在了 -
@arco444 它将存在于资源之外,
ruby_block的内容与父级在同一上下文中运行,因此我们有一个作用域变量可用于厨师运行的其余部分。
标签: mysql ruby bash chef-infra