【发布时间】:2020-06-17 09:26:27
【问题描述】:
我正在制作一个通过 POST 请求接收数据并发送包含该数据的电子邮件的函数。 当我尝试从不同的域调用我的函数时,出现以下错误:
CORS 策略已阻止从源“chrome-search://local-ntp”访问“我的函数”处的 XMLHttpRequest:请求的资源上不存在“Access-Control-Allow-Origin”标头。
我按照云文档上的说明在我的代码顶部添加了以下内容:
headers = {
'Access-Control-Allow-Origin': '*',
'Access-Control-Allow-Methods': '*',
'Access-Control-Allow-Headers': 'Authorization',
'Access-Control-Max-Age': '3600',
'Access-Control-Allow-Credentials': 'true'
}
return ('', 204, headers)
错误已解决,但我的其余代码在 return 语句之后没有运行。如何插入标题然后继续运行我的脚本?
整个代码如下:
import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from google.cloud import storage
import requests
def teste_email(request):
headers = {
'Access-Control-Allow-Origin': '*',
'Access-Control-Allow-Methods': '*',
'Access-Control-Allow-Headers': 'Authorization',
'Access-Control-Max-Age': '3600',
'Access-Control-Allow-Credentials': 'true'
}
return ('', 204, headers)
# Pega as variáveis passadas no request
request_json = request.get_json()
nome_projeto = request_json['nome_projeto']
logo_ic = request_json['logo_ic']
logo_aplicacao = request_json['logo_aplicacao']
title = request_json['title']
link = request_json['link']
descricao = request_json['descricao']
base = request_json['base']
# Lê o arquivo do template armazenado no cloud storage e o atribui a uma variável
client = storage.Client()
bucket = client.get_bucket('templates_email_icherry')
blob = bucket.get_blob("template-1.txt")
downloaded_blob = blob.download_as_string()
template = downloaded_blob.decode("utf-8")
# Substitui as variáveis no template pelos valores passados na chamada
template = template.replace("{title}", title)
template = template.replace("{logo_ic}", logo_ic)
template = template.replace("{logo_aplicacao}", logo_aplicacao)
template = template.replace("{descricao}", descricao)
template = template.replace("{link}", link)
template = template.replace("{nome_projeto}", nome_projeto)
template = template.replace("{base}", base)
# Variáveis para o envio do e-mail
email = 'email'
password = 'password'
send_to_email = 'email'
subject = 'Assunto do email'
messagePlain = 'Message Plain'
msg = MIMEMultipart('alternative')
msg['From'] = email
msg['To'] = send_to_email
msg['Subject'] = subject
msg.attach(MIMEText (messagePlain, 'plain'))
msg.attach(MIMEText (template, 'html'))
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(email, password)
text = msg.as_string()
server.sendmail(email, send_to_email, text)
server.quit()
【问题讨论】:
-
return在其他代码执行之后,而不是之前。 -
我也试过了,还是一样的错误
-
我可以使错误消失的唯一方法是使用这样的代码
-
如果没有minimal reproducible example,这个问题将很难帮助您
-
我编辑了问题,所以代码更详细
标签: python http post google-cloud-functions