【发布时间】:2017-11-24 11:25:08
【问题描述】:
我在我的应用程序中使用 MEAN 堆栈,并将 AngularJS 作为我的前端。如何total sum 列值,如果在表中过滤了某些值,实际上我得到了total sum value,但如果我在表中像| filter:{status: 'pending'} 这样过滤,总和会得到整体数据值...My Plunker 例如:- 在没有filter 的表中amt 值总和答案我得到5775.30,然后在表中如果我使用像| filter:{status: 'pending'} 这样的过滤器@amt 值总和显示为总值5775.30,期待3850.2 之类的答案,如果有人知道解决方案,请帮助我们,谢谢......
在没有过滤器的表格列中,我们也得到了准确的答案和总和。
1234563喜欢3850.2...请看my plunker
我的控制器:-
.filter('sumOfValue', function () {
return function (data, key) {
debugger;
if (angular.isUndefined(data) && angular.isUndefined(key))
return 0;
var sum = 0;
angular.forEach(data,function(v,k){
var keyval;
if(isNaN(parseFloat(v[key])))
keyval=0;
else
keyval=parseFloat(v[key]);
sum = sum + keyval;
});
return sum.toFixed(2);
}
})
我的 HTML:-
<td >{{mani.amt}}</td>
<td >{{mani.amount_payment }}</td>
<td >{{mani.status }}</td>
我的过滤器:-
| filter:{status: 'pending'}
我的数据:-
{
"_id": "5816f4fad0be79f809519f98",
"user": {
"_id": "57400c32bd07906c1308e2cf",
"displayName": "mani selvam"
},
"__v": 0,
"created": "2016-10-31T07:38:34.999Z",
"remarks": "-",
"status": "pending",
"amt": "1925.10",
"cheque_currency": "Rs",
"cheque_value": "300",
"amount_payment": "100",
"debitnote_no_payment": "3",
"supplier_name": "karikalan",
"status": "pending",
"buyer_name": "Manidesigns"
},
{
"_id": "5816f4fad0be79f809519f98",
"user": {
"_id": "57400c32bd07906c1308e2cf",
"displayName": "mani selvam"
},
"__v": 0,
"created": "2016-10-31T07:38:34.999Z",
"remarks": "-",
"status": "pending",
"amt": "1925.10",
"cheque_currency": "Rs",
"cheque_value": "300",
"amount_payment": "100",
"debitnote_no_payment": "3",
"supplier_name": "karikalan",
"status": "received",
"buyer_name": "Manidesigns"
},
{
"_id": "5816f4fad0be79f809519f98",
"user": {
"_id": "57400c32bd07906c1308e2cf",
"displayName": "mani selvam"
},
"__v": 0,
"created": "2016-10-31T07:38:34.999Z",
"remarks": "-",
"status": "pending",
"amt": "1925.10",
"cheque_currency": "Rs",
"cheque_value": "300",
"amount_payment": "",
"debitnote_no_payment": "3",
"supplier_name": "karikalan",
"status": "pending",
"buyer_name": "Manidesigns"
},
我创建了以下给出的答案更新:- Plunker
【问题讨论】: