通过另一个指标数据框评估一个数据框答案

【问题标题】：Evaluating a data frame through another Indicator data frame通过另一个指标数据框评估一个数据框
【发布时间】：2021-11-23 13:43:17
【问题描述】：

我有一个源数据框input_df：

患者 ID KPI_Key1 KPI_Key2 KPI_Key3 0 1 (C602+C603) C601 NaN 1 2 (C605+C606) C602 NaN 2 3 75 L239+C602 NaN 3 4 (32*(C603+234)) 75 南 4 5 L239 南 C601

我有另一个指标数据框indicator_df

99 75 C604 C602 C601 C603 C605 C606 44 L239 32 患者 ID 1 1 0 1 0 1 0 0 0 1 0 1 2 0 0 0 0 0 0 1 1 0 0 0 3 1 1 1 1 0 1 1 1 1 1 1 4 0 0 0 0 0 1 0 1 0 1 0 5 1 0 1 1 1 1 0 1 1 1 1 6 0 1 0 0 0 0 0 0 0 0 0 7 1 1 1 1 1 1 1 1 1 1 1 8 0 0 0 0 0 0 0 0 0 0 0

现在，我需要生成这样的输出 output_df

患者 ID KPI_Key1 KPI_Key2 KPI_Key3 0 1 0 1 0 1 2 1 0 0 2 3 1 1 0 3 4 0 0 0 4 5 1 0 1

output_df 是通过将 input_df 中的输入公式与 indicator_df 进行“评估”得到的。
+ 表示 OR 条件 1 + 1 = 1 ; 1 + 0 = 1 ; 0 + 0 = 0
* 表示 AND 条件。 1 * 1 = 1 ; 0 * 0 = 0 ; 1 * 0 = 0

来源：

input_df = pd.DataFrame({'PatientID': [1,2,3,4,5], 'KPI_Key1': ['(C602+C603)','(C605+C606)','75','( 32*(C603+234))','L239'] , 'KPI_Key2' : ['C601','C602','L239+C602','75',''] , 'KPI_Key3' : ['', '','','','C601']}) indicator_df = pd.DataFrame({'PatientID': [1,2,3,4,5,6,7,8],'99' : ['1','0','1','0', '1','0','1','0'],'75' : ['0','0','1','0','0','1','1', '0'],'C604' : ['1','0','1','0','1','0','1','0'],'C602' : ['0 ','0','1','0','1','0','1','0'],'C601' : ['1','0','0','0 ','1','0','1','0'],'C603' : ['0','0','1','1','1','0','1 ','0'],'C605' : ['0','1','1','0','0','0','1','0'],'C606' : [ '0','1','1','1','1','0','1','0'],'44' : ['1','0','1', '0','1','0','1','0'],'L239' : ['0','0','1','1','1','0', '1','0'], '32' : ['1','0','1','0','1','0','1','0'],}）。 set_index('病人 ID') output_df = pd.DataFrame({'PatientID': [1,2,3,4,5], 'KPI_Key1': ['0','1','1','0','1'] , ' KPI_Key2' : ['1','0','1','0','0'] ,'KPI_Key3' : ['0','0','0','0','1'] })

【问题讨论】：

标签： python pandas date-range

【解决方案1】：

终于解决了：

final_out_df = pd.DataFrame()
for i in range(len(input_df)):
    for j in ['KPI_Key1','KPI_Key2','KPI_Key3']:
      exp = input_df[j].iloc[i]
      #checking for NaN values
      if exp == exp:
        temp_out_df=indicator_df.eval(re.sub(r'(\w+)', r'`\1`', exp)).reset_index(name=j)
        out_df['KPI_Key'] =  input_df['KPI_Id'].iloc[i]
        out_df = out_df.merge(temp_out_df, on='PateintID', how='left')
    final_out_df= final_out_df.append(out_df)
    out_df = pd.DataFrame(index=indicator_df.index)
    out_df.reset_index(level=0, inplace=True)
final_out_df.index = range(len(final_out_df))
#filling NAN values to 0 and converting everything to int
final_out_df.fillna(0,inplace=True)
final_out_df[["KPI_Key1", "KPI_Key2", "KPI_Key3"]] = final_out_df[["KPI_Key1", "KPI_Key2", "KPI_Key3"]].astype(int)
#columns >1 = 1 
final_out_df.loc[final_out_df['KPI_Key1'] >= 1, 'KPI_Key1'] = 1 
final_out_df.loc[final_out_df['KPI_Key2'] >= 1, 'KPI_Key2'] = 1 
final_out_df.loc[final_out_df['KPI_Key3'] >= 1, 'KPI_Key3'] = 1

【讨论】：