sequelize.import 上的错误：defineCall 不是函数

Question

我得到的错误是：

C:\Users\brend\project\server\node_modules\sequelize\lib\sequelize.js:392
      this.importCache[path] = defineCall(this, DataTypes);
                               ^
TypeError: defineCall is not a function
    at Sequelize.import (C:\Users\brend\project\server\node_modules\sequelize\lib\sequelize.js:392:32)
    at fs.readdirSync.filter.forEach (C:\Users\brend\project\server\src\models\index.js:20:35)

我正在学习 node、vue 和一堆库，但我一直无法弄清楚这一点。

index.js 如下：

const fs = require('fs')
const path = require('path')
const Sequelize = require('sequelize')
const config = require('../config/config')
const db = {}

const sequelize = new Sequelize(
  config.db.database,
  config.db.user,
  config.db.password,
  config.db.options
)

fs
  .readdirSync(__dirname)
  .filter((file) =>
    file !== 'index.js'
  )
  .forEach((file) => {
    const model = sequelize.import(path.join(__dirname), file)
    db[model.name] = model
  })

db.sequelize = sequelize
db.Sequelize = Sequelize

module.exports = db

这是我的 User.js，这是我目前唯一的模型：

module.exports = (sequelize, DataTypes) =>
  sequelize.define('User', {
    email: {
      type: DataTypes.STRING,
      unique: true
    },
    password: DataTypes.STRING
  })

如果需要，我的文件夹结构：

-src
--app.js
--routes.js

--config
----config.js

--controllers
----AuthenticationController.js

--models
----index.js
----User.js

还有一点，在我的 app.js sequelize.sync() 中没有定义，至少我的 IDE 是这样表示的。

Answer 1

我在github上找到了这个sequelize github，替换

const model = sequelize.import(path.join(__dirname, file));

与

var model = require(path.join(__dirname, file))(sequelize, Sequelize.DataTypes);

它适用于我的续集 6.3.0

Answer 2

sequelize.import 在 sequelize v6+ 中已被弃用。它在那里 直到 v5

https://sequelize.org/master/manual/upgrade-to-v6.html#sequelize https://sequelize.org/master/manual/models-definition.html

之前的models/index.js 一直有效，直到续集v5：

const fs = require('fs')
const path = require('path')
const Sequelize = require('sequelize')
const config = require('../config/config')
const db = {}

const sequelize = new Sequelize(
  config.db.database,
  config.db.user,
  config.db.password,
  config.db.options
)

fs
  .readdirSync(__dirname)
  .filter((file) =>
    file !== 'index.js'
  )
  .forEach((file) => {
    const model = sequelize.import(path.join(__dirname), file) // error occurs here
    db[model.name] = model
  })

db.sequelize = sequelize
db.Sequelize = Sequelize

module.exports = db

现在sequelize v6+ 以上sequelize.import 将不可用。

所以在 models/index.js 的 forEach 部分进行以下更改

const fs = require('fs')
const path = require('path')
const Sequelize = require('sequelize')
const config = require('../config/config')
const db = {}

const sequelize = new Sequelize(
  config.db.database,
  config.db.user,
  config.db.password,
  config.db.options
)

fs
  .readdirSync(__dirname)
  .filter((file) =>
    file !== 'index.js'
  )
  .forEach((file) => {
    //-----------------------THIS PART HERE-----------------------
    /**
     * Choose any one of the below definition for model variable 
     */
    // for individual model files having `export default (sequelize, DataTypes) => {`    
    const model = require(path.join(__dirname, file)).default(sequelize, Sequelize.DataTypes); 
    // for individual model files having `module.exports = (sequelize, DataTypes) => {`    
    const model = require(path.join(__dirname, file))(sequelize, Sequelize.DataTypes);

    db[model.name] = model;
    //----------------------------------------------------------
  })

db.sequelize = sequelize
db.Sequelize = Sequelize

module.exports = db

注意事项：

• 如果在模型文件和 babel 中使用export default ... -> 我们使用的是require(...).default

• require(...) 不返回函数，而是将对象返回为：{ default: [Function] }，因此使用它的“默认”属性

Answer 3

“sequelize.import”已被弃用。你应该改用“require”。

参见上面的 artfulbeest 解决方案。它对我有用。

进一步阅读请转到官方文档 (https://sequelize.org/master/manual/models-definition.html)

Answer 4

检查您正在使用的 sequelize 版本。当我使用sequelize@6.0.0-beta.6 并发现import 从续集对象/客户端中丢失时，我遇到了一个持续错误：

npm 卸载续集

npm 安装续集

Answer 5

这里是关于sequelize的解决方案": "^6.3.4 替换

const model = sequelize.import(path.join(__dirname, file));

有

const model = require(path.join(__dirname, file))(sequelize, Sequelize);

Answer 6

试试：

models/index.js：

...

fs
    .readdirSync(__dirname)
    .filter((file) => {
        return (file.indexOf(".") !== 0) && (file !== "index.js");
    })
    .forEach((file) => {
        const model = sequelize.import(path.join(__dirname, file));
        db[model.name] = model;
    });

    Object.keys(db).forEach((modelName) => {
        if (db[modelName].associate) {
            db[modelName].associate(db);
        }
    });
...

models/user.js:（我用的是小写）

module.exports = (sequelize, Sequelize) => {
  var User = sequelize.define('user', {
    email: {
      type: Sequelize.STRING,
      unique: true
    },
    password: Sequelize.STRING
  })

  return User;
}

调用model.user：

const model = require('./models'); // Change path if is necesary
model.user.create({ ...