【发布时间】:2020-09-04 10:44:19
【问题描述】:
我想为 Flask-restful API 定义自定义错误处理
烧瓶自定义错误(FlaskGenericException)被引发,但不由 restplus 错误处理程序处理。它只是抛出一个 500 内部服务器错误。
不确定为什么在 exceptions.py 中定义的 dict 没有作为 api 响应抛出。
预期结果
{'user': 'Lionel Messi', 'company': 'Soccer Brazil','message': 'A generic error'}
这是我用来测试的文件:
app.py
import json,os
import logging
import sys
import requests
import config
from os import environ
from flask import Flask, request, jsonify, Response
from flask_jwt_extended import (JWTManager, jwt_required)
from flask_restplus import Api, Resource, reqparse, fields, inputs
from cal_Test import calTest
from exceptions import FlaskGenericException
# Setup Flask Server
app = Flask(__name__,root_path=os.path.join(os.getcwd(), './'))
app.config.from_object(config.Config)
api = Api(app=app,
version='0.1',
title="Test Cal API",
doc="/swagger/",
description='TestCal = Cal Test')
ns = api.namespace('/', description='Cal Test Api')
@api.errorhandler(FlaskGenericException)
def handle_error(error):
response = jsonify(error.to_dict())
response.status_code = error.status_code
return response
resource_parser = reqparse.RequestParser()
resource_parser.add_argument('test', type=str, required=True)
resource_flds = api.model('Resource', {
'test': fields.String(required = True),
})
@ns.route('/test', methods=['POST'])
class TestCal(Resource):
# @jwt_required
@ns.doc(body=resource_flds)
@ns.expect(resource_flds, validate=True)
def post(self):
request_data = resource_parser.parse_args()
caltst = calTest()
result = caltst.cal_test(request_data)
response = app.response_class(
response=json.dumps(result),
status=200,
mimetype='application/json'
)
return response
if __name__ == "__main__":
app.run(debug=True)
cal_Test.py
import pandas as pd
import pyodbc
import scipy.stats as st
import numpy as np
import pandas as pd
from scipy.stats import norm
from flask import Flask, request, jsonify
import os
from exceptions import FlaskGenericException
class calTest:
def __init__(self):
self.test_name = 'Hi! I am test'
def cal_test(self,reqdata):
if self.test_name == reqdata['test']:
return "Successfull"
else:
raise FlaskGenericException('A generic error', status_code=404, payload={'user': 'Lionel Messi', 'company': 'Soccer Brazil'})
exceptions.py
class FlaskGenericException(Exception):
status_code = 500 # default unless overridden
def __init__(self, message, status_code=None, payload=None):
Exception.__init__(self)
self.message = message
if status_code is not None:
self.status_code = status_code
self.payload = payload
def to_dict(self):
rv = dict(self.payload or ())
rv['message'] = self.message
return rv
【问题讨论】:
-
这是 flask-restplus 中的一个现有错误:github.com/noirbizarre/flask-restplus/issues/744,将在 0.14.0 版本中修复。还没有发布日期。
标签: python flask flask-restful flask-restplus