【发布时间】:2015-04-07 16:02:28
【问题描述】:
我想为我尝试过多次的 .jsp 和 .xhtml 页面创建 2 个视图解析器,但过程失败了 我将 .jsp 视图解析器作为最高优先级的视图解析器 它适用于 .jsp 页面,但是当涉及 .xhtml 页面时,它给了我一个错误:找不到资源 因此,如果找不到“.jsp”视图,它不会处理“.xhtml”视图解析器 这是错误的屏幕截图和项目架构: http://postimg.org/image/5cz5iulwd/
下面是 web.xml servle-context.xml 和 applicationContext.xml 代码 我该怎么办?
web.xml -->
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>FORWARD</dispatcher>
<dispatcher>REQUEST</dispatcher>
</filter-mapping>
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:applicationContext.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- xhtml mapping -->
<servlet>
<servlet-name>FacesServlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>FacesServlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
applicationContext.xml --->
enter code here <!-- datasource -->
<bean id="datasource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost:3306/primefaces"/>
<property name="username" value="root"/>
<property name="password" value=""/>
</bean>
<!-- persistenceUnitManager -->
<bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
<property name="defaultDataSource" ref="datasource"/>
<property name="persistenceXmlLocations">
<list>
<value>classpath*:META-INF/persistence.xml</value>
</list>
</property>
</bean>
<!-- entityManagerFactory -->
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitManager" ref="persistenceUnitManager"/>
<property name="persistenceUnitName" value="UP_TEST"/>
</bean>
<!-- transactionManager -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<context:annotation-config/>
<bean id="dao" class="com.test.app.dao.DaoIml"></bean>
<bean id="metier" class="com.test.app.metier.MetierIml">
<property name="dao" ref="dao"></property>
</bean>
<s:http use-expressions="true">
<s:intercept-url pattern="/admin/**" access="ROLE_ADMIN"/>
<s:form-login login-page="/login" default-target-url="/default" authentication-failure-url="/login" />
<s:logout logout-success-url="/login" />
</s:http>
<s:authentication-manager>
<s:authentication-provider>
<s:password-encoder hash="md5"></s:password-encoder>
<s:jdbc-user-service data-source-ref="datasource" users-by-username-query="select user_name,password, actived from users where user_name=?" authorities-by-username-query="select u.user_name, r.roleName from users u, role r where u.user_id = r.user_id and u.user_name =? " />
</s:authentication-provider>
</s:authentication-manager>
这里是 servlet-context.xml
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<beans:bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<beans:property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></beans:property>
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
<beans:property name="order" value="0" />
</beans:bean>
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".xhtml" />
<beans:property name="order" value="1" />
</beans:bean>
<context:component-scan base-package="com.test.app" />
【问题讨论】:
-
一个问题,为什么不将您的 xhtml 文件作为静态资源提供?
标签: spring jsp spring-mvc spring-security xhtml