Spring - 多对一 - 将联系人分配给用户的电话簿

Question

我是java和spring的新手。我的第一个练习是模拟网络电话簿的项目。我坚持将联系人分配给特定用户，然后再显示该特定用户的联系人。任何想法或指南都表示赞赏。

用户类

@Entity
public class User implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;

private String name;
private String lastName;
private String email;
private String username;
private String password;


@Transient
private String retypePassword;

@ManyToMany(fetch = FetchType.EAGER,cascade=CascadeType.ALL)
@JoinTable(name="users_roles",
    joinColumns = {@JoinColumn(name="user_id", referencedColumnName="id")},
    inverseJoinColumns = {@JoinColumn(name="role_id", referencedColumnName="roles_id")}
)
private List<Rolee> authorities;


@OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL, mappedBy = "userForPhonebook")
@Fetch(value = FetchMode.SUBSELECT)
private Collection<Contact> allContacts;

// getters and setters

联系班级

@Entity
public class Contact implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int contactID;

private String name;
private String lastName;
private String email;
private String areaCode;
private String telNumber;
private String adress;
private String city;
private String note;
private String contactImage;

@JoinColumn(name = "users_id")
@ManyToOne(fetch = FetchType.EAGER, optional = false)
private User userForPhonebook;

// getters and setters

ContactServiceImpl 类

@Service
public class ContactServiceImpl implements ContactService {

@Autowired
private ContactDAO contactDAO;

@Autowired
private UserDAO userDAO;

@Autowired
private ServletContext context;

@Override
public void addContact(ContactModel contactModel, MultipartFile[] contactImages, User user) {

    Contact contact = new Contact();

    /*
    creating contact
    */ 

    User user2 = userDAO.userGetById(user.getId()); //<-- i cant get user id
    contact.setUserForPhonebook(user2);

    // --------------------------------

    User u = new User();                //
    u.setId(2);                         // hard coding users id... 
    contact.setUserForPhonebook(u);     // and its working fine

   //  rest of code to create contact ...

用户DAOImpl

// ...
@Override
public void addUser(User user) {

    Session s = getCurrentSession();
    Transaction trans = s.beginTransaction();
    getCurrentSession().save(user);
    trans.commit();

}
// ... 

用户服务实现

// ...
@Override
public void addUser(UserModel userModel) {

    User user = new User();

    // creating user ...

    getUserDAO().addUser(user);
}
// ...

注册控制器

// ...
@RequestMapping(value = "/addUser", method = RequestMethod.POST)
public String postRegister(@Valid @ModelAttribute("newUser") UserModel userModel, BindingResult results, ModelMap model) {

    if (results.hasErrors()) {
        return "addUser";
    }

    // checking if username, email exist in database ... 
    // password matching


    getUserService().addUser(user);

    return "index";
}
// ...

联系人控制器

// ...
@RequestMapping(value = "/addContact", method = RequestMethod.POST)
public String postAddContact(@Valid @ModelAttribute("addContact") ContactModel contactModel, BindingResult results, HttpServletRequest request, @RequestParam("contactImages") MultipartFile[] contactImages, User user)
        throws FileNotFoundException, IOException  {

    if (results.hasErrors()) {
        return "addContact";
    }

    getContactService().addContact(contactModel, contactImages, user);

    return "redirect:phoneBook";
}
//...

Answer 1

here 的答案帮助我将当前活跃的用户分配给联系人，我的 postAddContact 看起来像这样。抱歉，如果我没有正确提出问题，我希望这对其他人有帮助

@RequestMapping(value = "/addContact", method = RequestMethod.POST)
public String postAddContact(@Valid @ModelAttribute("addContact") ContactModel contactModel, BindingResult results, HttpServletRequest request, @RequestParam("contactImages") MultipartFile[] contactImages)
        throws FileNotFoundException, IOException  {

    if (results.hasErrors()) {
        return "addContact";
    }

    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
    UserDetails userDetail = (UserDetails) auth.getPrincipal();

    User u = userDAO.getUserByUsername(userDetail.getUsername());
    request.getSession().setAttribute("id", u.getId());

    int userId = (int) request.getSession().getAttribute("id");

    User user = new User();
    user.setId(userId);


    getContactService().addContact(contactModel, contactImages, user);

    return "redirect:phoneBook";
}

Answer 2

您没有指定 Spring 应该如何在您的 postAddContact 签名中绑定您的 User 对象。

@RequestMapping(value = "/addContact", method = RequestMethod.POST)
public String postAddContact(
        // Ok, this is a model retrieved from request params
        @Valid @ModelAttribute("addContact") ContactModel contactModel,

        // Ok, a BindingResult is mapped when the validation above occurs
        BindingResult results,

        // Ok, bind the internal HttlServletRequest
        HttpServletRequest request,

        // Ok, bind this to the multipart part of the request
        @RequestParam("contactImages") MultipartFile[] contactImages,

        // ... no idea how to bind this
        User user)

        throws FileNotFoundException, IOException  {
    // ...
}

您需要自己指定要获取联系人的用户。

您可以在 ContactModel 对象中添加字段，例如 userId，然后在控制器中从数据库中检索该用户，然后再添加联系人。

ContactController.java

// ...
@RequestMapping(value = "/addContact", method = RequestMethod.POST)
public String postAddContact(@Valid @ModelAttribute("addContact") ContactModel contactModel, BindingResult results, HttpServletRequest request, @RequestParam("contactImages") MultipartFile[] contactImages)
        throws FileNotFoundException, IOException  {

    if (results.hasErrors()) {
        return "addContact";
    }

    // Retrieve the user
    User user = getUserService().retrieveUser(contactModel.getUserId());

    getContactService().addContact(contactModel, contactImages, user);

    return "redirect:phoneBook";
}
//...

您还可以添加路径变量，使用已连接用户等。以上代码只是一个建议。