如何将多个 Spring MVC 控制器添加到我的 Maven 项目

Question

我需要向我的 Spring MVC 项目中添加多个控制器，该项目现在只有一个。我当前的项目在 web.xml 中只有一个 SpringDispatcher，它映射了 / 到控制器的“/” @RequestMapping(值 = "/") 启动控制器。因为一切都在一个 web.xml 中，并且没有其他 xml 文件可以进行任何调度程序映射，所以我是否不能只添加一个新的 / 与 web.xml 不同的控制器模式？下面是 web.xml 和一个工作控制器。

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee       http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>SpringMvcJdbcTemplate</display-name>
<context-param>
    <param-name>contextClass</param-name>
    <param-value>
        org.springframework.web.context.support.AnnotationConfigWebApplicationContext
    </param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
    <servlet-name>SpringDispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextClass</param-name>
        <param-value>
            org.springframework.web.context.support.AnnotationConfigWebApplicationContext
        </param-value>
    </init-param>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>net.codejava.spring</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>SpringDispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<session-config>
    <session-timeout>30</session-timeout>
</session-config>
</web-app>

HomeController.java

package net.codejava.spring.controller;

import java.io.IOException;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.servlet.http.HttpServletRequest;

import net.codejava.spring.dao.ContactDAO;
import net.codejava.spring.dao.ContactDAODS;
import net.codejava.spring.model.Contact;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

/**
 * This controller routes accesses to the application to the appropriate
 * hanlder methods. 
 * @author www.codejava.net
 *
 */
@Controller
public class HomeController {

@Autowired
private ContactDAO contactDAO;

@Autowired
private ContactDAODS contactDAODS;

@RequestMapping(value = "/")
public ModelAndView login() {

    Contact contact = new Contact();
    ModelAndView model = new ModelAndView("login");
    model.addObject("contact", contact);

    return model;
}

@RequestMapping(value = "/loginContact", method = RequestMethod.POST)
public ModelAndView loginContact(@ModelAttribute Contact loginContact) {

    ModelAndView model;

    Contact contact = contactDAO.login(loginContact);

    if(contact != null)
    {
        model = new ModelAndView("menu");

        return model;

    }
    else
    {
        Map<String, String> message = new HashMap<String,   String>();
        message.put("message", "Login password error");
        //Message message = new Message();
        //message.MessageText = "Login Error";
        model = new ModelAndView("loginError");
        model.addObject("message", message);
        return model;

    }
}

@RequestMapping(value = "/menuContact", method = RequestMethod.GET)
public ModelAndView menu(ModelAndView model){
    model.setViewName("menu");

    return model;
}

@RequestMapping(value = "/listContact", method = RequestMethod.GET)
public ModelAndView listContact(ModelAndView model) throws IOException{
    List<Contact> listContact = contactDAO.list();
    model.addObject("listContact", listContact);
    model.setViewName("home");

    return model;
}

@RequestMapping(value = "/newContact", method = RequestMethod.GET)
public ModelAndView newContact(ModelAndView model) {
    Contact newContact = new Contact();
    model.addObject("contact", newContact);
    model.setViewName("ContactForm");
    return model;
}

@RequestMapping(value = "/saveContact", method = RequestMethod.POST)
public ModelAndView saveContact(@ModelAttribute Contact contact) {
    contactDAO.saveOrUpdate(contact);       
    return new ModelAndView("redirect:/");
}

@RequestMapping(value = "/deleteContact", method = RequestMethod.GET)
public ModelAndView deleteContact(HttpServletRequest request) {
    int contactId = Integer.parseInt(request.getParameter("id"));
    contactDAO.delete(contactId);
    return new ModelAndView("redirect:/");
}

@RequestMapping(value = "/editContact", method = RequestMethod.GET)
public ModelAndView editContact(HttpServletRequest request) {
    int contactId = Integer.parseInt(request.getParameter("id"));
    Contact contact = contactDAO.get(contactId);
    ModelAndView model = new ModelAndView("ContactForm");
    model.addObject("contact", contact);

    return model;
}
@RequestMapping(value="/showContact")
public ModelAndView getContact(ModelAndView model) throws IOException{

    Contact contact = contactDAODS.get((Integer)25);
    model.addObject("contact", contact);
    model.setViewName("ContactSP");

    return model;
}
}

Answer 1

首先，这个映射应该只适用于应用程序根。如果您想要应用程序根目录下的任何路径，请使用 /*

现在，在您的情况下，只有当您打开浏览器以指向 Web 应用程序根目录而不指定任何我可能猜到的路径不是您想要的路径时，才会调用 spring 调度程序。因此，使用 /* 将所有请求转发到 spring 调度程序并在控制器中使用任何请求映射