【发布时间】：2013-07-30 15:44:15
【问题描述】：
我发现实际上是 Spring，我能够设置一些工作。现在，我想使用 Hibernate/JPA 将导入的数据保存在数据库中，但我不断收到此错误：
14:46:43.500 [main] ERROR o.s.b.core.step.AbstractStep - Encountered an error executing the step javax.persistence.TransactionRequiredException: no transaction is in progress
我发现问题出在交易上。这是entityManager 和transactionManager 的spring java 配置：
@Configuration
public class PersistenceSpringConfig implements EnvironmentAware
{
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() throws Exception
{
// Initializes the entity manager
LocalContainerEntityManagerFactoryBean factoryBean = new LocalContainerEntityManagerFactoryBean();
factoryBean.setPersistenceUnitName(PERSISTENCE_UNIT_NAME);
factoryBean.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
factoryBean.setDataSource(dataSource());
// Scans the database model
factoryBean.setPackagesToScan(EntiteJuridiqueJPA.class.getPackage().getName());
// Defines the Hibernate properties
Properties jpaProperties = new Properties();
jpaProperties.setProperty("hibernate.show_sql", "false");
jpaProperties.setProperty("hibernate.format_sql", "false");
String connectionURL = "jdbc:h2:file:" + getDatabaseLocation();
jpaProperties.setProperty("hibernate.connection.url", connectionURL);
jpaProperties.setProperty("hibernate.connection.username", "sa");
jpaProperties.setProperty("hibernate.connection.driver_class", "org.h2.Driver");
jpaProperties.setProperty("hibernate.dialect", H2Dialect.class.getName());
jpaProperties.setProperty("hibernate.hbm2ddl.auto", "create");
jpaProperties.setProperty("hibernate.hbm2ddl.import_files_sql_extractor", "org.hibernate.tool.hbm2ddl.MultipleLinesSqlCommandExtractor");
jpaProperties.setProperty("hibernate.hbm2ddl.import_files",
"org/springframework/batch/core/schema-drop-h2.sql,org/springframework/batch/core/schema-h2.sql");
factoryBean.setJpaProperties(jpaProperties);
return factoryBean;
}
@Bean
public PlatformTransactionManager transactionManager2() throws Exception
{
EntityManagerFactory object = entityManagerFactory().getObject();
JpaTransactionManager jpaTransactionManager = new JpaTransactionManager(object);
return jpaTransactionManager;
}
我正在使用JpaItemWriter 将数据存储在数据库中：
@Bean
public ItemWriter<EntiteJuridiqueJPA> writer()
{
JpaItemWriter<EntiteJuridiqueJPA> writer = new JpaItemWriter<EntiteJuridiqueJPA>();
writer.setEntityManagerFactory(entityManagerFactory.getObject());
return writer;
}
这是导致异常的代码：javax.persistence.TransactionRequiredException: no transaction is in progress
知道如何解决这个问题吗？
[编辑] 我也把作业定义和步骤定义。我所有的 Spring 配置都是用 Java 编写的。
@Configuration
@EnableBatchProcessing
@Import(PersistenceSpringConfig.class)
public class BatchSpringConfig
{
@Autowired
private JobBuilderFactory jobBuilders;
@Autowired
private StepBuilderFactory stepBuilders;
@Autowired
private DataSource dataSource;
@Autowired
private LocalContainerEntityManagerFactoryBean entityManagerFactory;
@Bean
public Step step()
{
return stepBuilders.get("step").<EntiteJuridique, EntiteJuridiqueJPA> chunk(5).reader(cvsReader(null))
.processor(processor()).writer(writer()).listener(processListener()).build();
}
@Bean
@StepScope
public FlatFileItemReader<EntiteJuridique> cvsReader(@Value("#{jobParameters[input]}") String input)
{
FlatFileItemReader<EntiteJuridique> flatFileReader = new FlatFileItemReader<EntiteJuridique>();
flatFileReader.setLineMapper(lineMapper());
flatFileReader.setResource(new ClassPathResource(input));
return flatFileReader;
}
@Bean
public LineMapper<EntiteJuridique> lineMapper()
{
DefaultLineMapper<EntiteJuridique> lineMapper = new DefaultLineMapper<EntiteJuridique>();
DelimitedLineTokenizer lineTokenizer = new DelimitedLineTokenizer();
lineTokenizer.setDelimiter(";");
lineTokenizer.setNames(new String[] { "MEGA_ENTITE", "PORTEFEUILLE", "MEGA_ENTITE", "Libellé" });
BeanWrapperFieldSetMapper<EntiteJuridique> fieldSetMapper = new BeanWrapperFieldSetMapper<EntiteJuridique>();
fieldSetMapper.setTargetType(EntiteJuridique.class);
lineMapper.setLineTokenizer(lineTokenizer);
lineMapper.setFieldSetMapper(fieldSetMapper);
return lineMapper;
}
@Bean
public Job dataInitializer()
{
return jobBuilders.get("dataInitializer").listener(protocolListener()).start(step()).build();
}
@Bean
public ItemProcessor<EntiteJuridique, EntiteJuridiqueJPA> processor()
{
return new EntiteJuridiqueProcessor();
}
@Bean
public ItemWriter<EntiteJuridiqueJPA> writer()
{
JpaItemWriter<EntiteJuridiqueJPA> writer = new JpaItemWriter<EntiteJuridiqueJPA>();
writer.setEntityManagerFactory(entityManagerFactory.getObject());
return writer;
// return new EntiteJuridiqueWriter();
}
@Bean
public ProtocolListener protocolListener()
{
return new ProtocolListener();
}
@Bean
public CSVProcessListener processListener()
{
return new CSVProcessListener();
}
@Bean
public PlatformTransactionManager transactionManager2() throws Exception
{
EntityManagerFactory object = entityManagerFactory.getObject();
JpaTransactionManager jpaTransactionManager = new JpaTransactionManager(object);
return jpaTransactionManager;
}
[编辑]我仍然被这个问题困扰。我遵循了@Sean Patrick Floyd 和@bellabax 的建议，为stepBuilders 设置了一个事务管理器，但我仍然遇到同样的异常。我已经独立于 spring-batch 测试了我的 entityManager，并且我能够将任何数据存储在数据库中。
但是，当使用与 spring 批处理相同的实体管理器时，我有这个异常。
任何人都可以提供更多关于如何在 Spring Batch 中管理事务的见解？谢谢你的帮助？
【问题讨论】：
标签： java spring jpa spring-batch spring-transactions