【发布时间】:2019-05-17 00:22:27
【问题描述】:
当尝试将双精度值映射/设置为 0.0 时,ObjectMapper 将其视为等效于 null,从而在比较相等性时将其排除。
我有以下测试用例:
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.util.Map;
import lombok.Getter;
import lombok.Setter;
import net.javacrumbs.jsonunit.JsonAssert;
import org.junit.Test;
public class ValidJson {
@Getter
@Setter
static class Temp {
Double dblValue;
Integer intVal;
boolean valid = false;
}
@Test
public void validJson() throws Exception {
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setSerializationInclusion(Include.NON_NULL);
objectMapper.setSerializationInclusion(Include.NON_DEFAULT);
String json = "{\"dblValue\":0.0}";
Temp generatedObj = objectMapper.readValue(json, Temp.class);
Map<?, ?> originalJsonMap = objectMapper.readValue(json, Map.class);
JsonNode generatedObjMap = objectMapper.valueToTree(generatedObj);
JsonNode originalObjMap = objectMapper.valueToTree(originalJsonMap);
Assert.assertSame(originalObjMap, generatedObjMap);
}
}
上述测试用例失败,断言错误为java.lang.AssertionError: JSON documents are different: Different keys found in node "". Expected [dblValue], got []. Missing: "dblValue"
但是当我将String json = "{\"dblValue\":0.0}"; 更改为String json = "{\"dblValue\":1.0}"; 时,测试通过了。
我认为 Double 的默认值行为与 Jackson 一起出现了一些问题,我无法弄清楚并解决我的上述问题。杰克逊 v2.8.10。
【问题讨论】:
标签: java json jackson-databind