SQL Count No of Mondays tuesdays etc from year

Question

我想创建一个表格，如下表所示，按月份显示本年度每周日的计数。

我知道我需要使用 with 语句，但还没有设法破解它。

我正在使用 MS SQL Server 2008 r2，我也是 SQL 的初级人员，因此我们将不胜感激任何帮助

预期输出：

Month       Mon Tue Wed Thu Fri Sat Sun Sum
-------------------------------------------
January     4   5   5   5   4   4   4   31
February    4   4   4   4   4   4   4   28
March       4   4   4   4   5   5   5   31
April       5   5   4   4   4   4   4   30
May         4   4   5   5   5   4   4   31
June        4   4   4   4   4   5   5   30
July        5   5   5   4   4   4   4   31
August      4   4   4   5   5   5   4   31
September   5   4   4   4   4   4   5   30
October     4   5   5   5   4   4   4   31
November    4   4   4   4   5   5   4   30
December    5   5   4   4   4   4   5   31

Answer 1

-- count weekdays in a year
declare @y int = 2013
declare @d datetime = dateadd(year, @y - 1900, 0)

;with cte
as
(
    select 1 a, 
      left(datename(weekday, @d), 3) b,
      datename(month, 0) Month,
      1 sort
    union all
    select a + 1 a, 
      left(datename(weekday, @d + a), 3) b, 
      datename(month, @d + a) Month, 
      datepart(month, @d + a) sort
    from cte where a < datepart(dayofyear, dateadd(year, 1, @d)-1)
)
select month, [Mon],[Tue],[Wed],[Thu],[Fri],[Sat],[Sun], 
     [Mon]+[Tue]+[Wed]+[Thu]+[Fri]+[Sat]+[Sun] [Sum] 
from cte
pivot (count(a) FOR [b] IN ([Mon],[Tue],[Wed],[Thu],[Fri],[Sat],[Sun],[Sum])) AS pvt
order by sort 
option (maxrecursion 366)