【发布时间】：2023-03-19 03:36:02
【问题描述】：
让我们考虑一个简单的 Postgres 数据库，只有一张表和一列，即 DATE 类型，即：
CREATE DATABASE test;
CREATE TABLE test_table
(
date_test DATE NOT NULL DEFAULT CURRENT_DATE
);
从 Hibernate documentation 关于基本类型和 PostgresSQL documentation 关于使用 Java 8 日期和时间类，我可以清楚地看到我应该能够像这样映射该表：
@Entity
@Table(name = "test_table")
public class TestTable
{
@Column(name = "date_test")
private LocalDate dateTest;
}
很容易，不需要写@Temporal 或任何类似的东西。从 Hibernate 文档中我可以阅读：
因为Java 8 Date/Time 类和SQL 类型之间的映射是隐式的，所以不需要指定@Temporal 注解。在 java.time 类上设置它会引发以下异常：
org.hibernate.AnnotationException: @Temporal should only be set on a java.util.Date or java.util.Calendar property
但是，我遇到了一个错误
Schema-validation: wrong column type encountered in column [date_test] in table [test_table]; found [date (Types#DATE)], but expecting [bytea (Types#VARBINARY)]
在我的pom.xml 文件中，我有：
<dependency>
<groupId>org.postgresql</groupId>
<artifactId>postgresql</artifactId>
<version>9.4-1206-jdbc42</version>
</dependency>
因为我也在使用 Spring Boot，所以在 application.properties 我有
spring.jpa.database-platform=org.hibernate.dialect.PostgreSQL9Dialect
我对文档有误吗？我应该写一个转换器还是有其他方法？
编辑
目前我的pom.xml 文件如下所示：
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>groupId</groupId>
<artifactId>Invoices-desktop</artifactId>
<version>1.0-SNAPSHOT</version>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.8</source>
<target>1.8</target>
</configuration>
</plugin>
</plugins>
<resources>
<!-- copy fxml and css resources -->
<resource>
<directory>src/main/java</directory>
<includes>
<include>**/*.fxml</include>
<include>**/*.css</include>
<include>**/*.properties</include>
</includes>
</resource>
<resource>
<directory>src/CurrencyDemo/java</directory>
<includes>
<include>**/*.fxml</include>
<include>**/*.css</include>
<include>**/*.properties</include>
</includes>
</resource>
<resource>
<directory>src/main/resources</directory>
<includes>
<include>**/*.*</include>
</includes>
</resource>
</resources>
</build>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<start-class>com.Main</start-class>
<java.version>1.8</java.version>
</properties>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>1.5.3.RELEASE</version>
</parent>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
<version>1.5.6.RELEASE</version>
<exclusions>
<exclusion>
<artifactId>org.hibernate</artifactId>
<groupId>hibernate-core</groupId>
</exclusion>
</exclusions>
</dependency>
<dependency>
<groupId>org.postgresql</groupId>
<artifactId>postgresql</artifactId>
<version>9.4-1206-jdbc42</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-validator</artifactId>
<version>5.4.1.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>5.2.10.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate.javax.persistence</groupId>
<artifactId>hibernate-jpa-2.1-api</artifactId>
<version>1.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-CurrencyDemo</artifactId>
<scope>CurrencyDemo</scope>
</dependency>
<dependency>
<groupId>com.ibm.icu</groupId>
<artifactId>icu4j</artifactId>
<version>59.1</version>
</dependency>
<dependency>
<groupId>org.apache.pdfbox</groupId>
<artifactId>pdfbox</artifactId>
<version>2.0.7</version>
</dependency>
</dependencies>
</project>
现在我得到了：
java.lang.NoSuchMethodError:org.hibernate.engine.spi.SessionFactoryImplementor.getProperties()Ljava/util/Properties;
【问题讨论】：
标签： java postgresql hibernate hibernate-5.x postgres-9.6