如何在第二个 Spring Boot 中传递只有 ID 的嵌套 JSON答案

【问题标题】：How to pass nested JSON with only ID in the second Spring Boot如何在第二个 Spring Boot 中传递只有 ID 的嵌套 JSON
【发布时间】：2020-11-17 19:24:36
【问题描述】：

我有这个 JSON 来创建一个具有现有帐户的新用户（我只传递属性 accountId）：

{
    "account": {
            "accountId":"06xxxx-5fxx-4xxx-xxxx-xxxxxx"
    },
    "userName":"user3",
    "emailAddress":"user3@gmail.com",
  "password":"123",
    "enabled":"1",
    "lastLogin":"2020-07-28"
}

我的用户模型如下：

public class User implements Serializable {

    @Id
    @GeneratedValue(generator = "uuid")
    @GenericGenerator(name = "uuid", strategy = "uuid2")
    @Size(max = 36)
    @Column(name = "userId")
    private String userId;

    @JoinColumn(name = "accountId", referencedColumnName = "accountId", nullable = false)
    @ManyToOne
    private Account account;

    @NaturalId
    @Column(name = "userName")
    private String userName;

    @Column(name = "emailAddress")
    private String emailAddress;

    @Column(name = "password")
    private String password;

    @Column(name = "enabled")
    private Integer enabled;

    @Column(name = "lastLogin")
    private String lastLogin;

    @OneToMany(
            mappedBy = "user",
            cascade = CascadeType.ALL,
            orphanRemoval = true
    )
    private List<UserGroupUser> userGroups = new ArrayList<>();

//Constructor, Getters and setters

}

类 Account 是在 User 之前创建的第一个实例：

public class Account implements Serializable {

    @Id
    @GeneratedValue(generator = "uuid")
    @GenericGenerator(name = "uuid", strategy = "uuid2")
    @Size(max = 36)
    @Column(name = "accountId")
    private String accountId;

    @Column(name = "accountName")
    private String accountName;

    @Column(name = "company")
    private String company;

    @Column(name = "address")
    private String address;

    @Column(name = "emailAddress")
    private String emailAddress;

    @Column(name = "dicomId")
    private String dicomId;

    @Column(name = "enabled")
    private Integer enabled;

    @OneToMany (mappedBy = "account",
                cascade = CascadeType.ALL,
                orphanRemoval = true)
    Set<User> users = new HashSet<>();

    @OneToMany (mappedBy = "account",
                cascade = CascadeType.ALL,
                orphanRemoval = true)
    Set<UserGroup> userGroups = new HashSet<>();

    //Constructor, Getters and setters
}

我必须使用 Spring Boot 来做到这一点。请问对于这些情况，什么是最真实的？

这是我的异常消息，如下所示：

{
  "timestamp": "2020-07-29T08:00:05.608+0000",
  "message": "The given id must not be null!; nested exception is java.lang.IllegalArgumentException: The given id must not be null!",
  "details": "uri=/api/v1/addUser"
}

Spring Boot 控制台生成：

2020-07-29 11:38:43.141  INFO 14172 --- [  restartedMain] o.s.b.w.embedded.tomcat.TomcatWebServer  : Tomcat started on port(s): 9898 (http) with context path ''
2020-07-29 11:38:43.144  INFO 14172 --- [  restartedMain] c.p.conexiona.ConexionaApplication       : Started ConexionaApplication in 6.526 seconds (JVM running for 8.967)
2020-07-29 11:38:43.146 DEBUG 14172 --- [  restartedMain] o.s.boot.devtools.restart.Restarter      : Creating new Restarter for thread Thread[main,5,main]
2020-07-29 11:38:43.147 DEBUG 14172 --- [  restartedMain] o.s.boot.devtools.restart.Restarter      : Immediately restarting application
2020-07-29 11:38:43.147 DEBUG 14172 --- [  restartedMain] o.s.boot.devtools.restart.Restarter      : Created RestartClassLoader org.springframework.boot.devtools.restart.classloader.RestartClassLoader@10c515a9
2020-07-29 11:38:43.147 DEBUG 14172 --- [  restartedMain] o.s.boot.devtools.restart.Restarter      : Starting application com.practicas.conexiona.ConexionaApplication with URLs [file:/C:/Users/canro/IdeaProjects/project_example/target/classes/]
2020-07-29 11:38:56.911  INFO 14172 --- [nio-9898-exec-1] o.a.c.c.C.[Tomcat].[localhost].[/]       : Initializing Spring DispatcherServlet 'dispatcherServlet'
2020-07-29 11:38:56.912  INFO 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : Initializing Servlet 'dispatcherServlet'
2020-07-29 11:38:56.912 DEBUG 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : Detected StandardServletMultipartResolver
2020-07-29 11:38:56.920 DEBUG 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : enableLoggingRequestDetails='false': request parameters and headers will be masked to prevent unsafe logging of potentially sensitive data
2020-07-29 11:38:56.920  INFO 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : Completed initialization in 8 ms
2020-07-29 11:38:56.930 DEBUG 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : POST "/api/v1/addUser", parameters={}
2020-07-29 11:38:56.933 DEBUG 14172 --- [nio-9898-exec-1] s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped to com.example.rest.UserController#createUser(User)
2020-07-29 11:38:57.030 DEBUG 14172 --- [nio-9898-exec-1] m.m.a.RequestResponseBodyMethodProcessor : Read "application/json;charset=UTF-8" to [com.example.model.User@2802b333]
null
2020-07-29 11:38:57.427 DEBUG 14172 --- [nio-9898-exec-1] .m.m.a.ExceptionHandlerExceptionResolver : Using @ExceptionHandler com.example.exception.GlobalExceptionHandler#globleExcpetionHandler(Exception, WebRequest)
2020-07-29 11:38:57.446 DEBUG 14172 --- [nio-9898-exec-1] o.s.w.s.m.m.a.HttpEntityMethodProcessor  : Using 'application/json', given [*/*] and supported [application/json, application/*+json, application/json, application/*+json]
2020-07-29 11:38:57.447 DEBUG 14172 --- [nio-9898-exec-1] o.s.w.s.m.m.a.HttpEntityMethodProcessor  : Writing [com.example.exception.ErrorDetails@4ddbc615]
2020-07-29 11:38:57.466  WARN 14172 --- [nio-9898-exec-1] .m.m.a.ExceptionHandlerExceptionResolver : Resolved [org.springframework.dao.InvalidDataAccessApiUsageException: The given id must not be null!; nested exception is java.lang.IllegalArgumentException: The given id must not be null!]
2020-07-29 11:38:57.466 DEBUG 14172 --- [nio-9898-exec-1] o.s.web.servlet.DispatcherServlet        : Completed 500 INTERNAL_SERVER_ERROR

用户控制器：

@RestController
@RequestMapping("/api/v1")
public class UserController {

    @Autowired
    private UserService userService;

    @GetMapping("/users")
    public List<User> getAllUsers() {
        return userService.findAllUsers();
    }

    @GetMapping("/users/{id}")
    public ResponseEntity<User> getUserById(
            @PathVariable(value = "id") String userId) throws ResourceNotFoundException {
        User user = userService.findUserById(userId)
                .orElseThrow(() -> new ResourceNotFoundException("user not found on :: "+ userId));
        return ResponseEntity.ok().body(user);
    }

    @PostMapping("/addUser")
    public User createUser(@Valid @RequestBody User user) { return userService.addUser(user); }

    @PutMapping("/users/{id}")
    public ResponseEntity<User> updateUser(
            @PathVariable(value = "id") String userId,
            @Valid @RequestBody User userDetails) throws ResourceNotFoundException {
        User user = userService.findUserById(userId)
                .orElseThrow(() -> new ResourceNotFoundException("user not found on :: "+ userId));

        final User updatedUser = userService.updateUser(userDetails, user);
        if  (updatedUser == null){
            return new ResponseEntity<User>(HttpStatus.EXPECTATION_FAILED);
        } else {
            return ResponseEntity.ok(updatedUser);
        }
    }

    @DeleteMapping("/user/{id}")
    public Map<String, Boolean> deleteUser(
            @PathVariable(value = "id") String userId) throws Exception {
        User user = userService.findUserById(userId)
                .orElseThrow(() -> new ResourceNotFoundException("user not found on :: "+ userId));

        userService.deleteUser(user);
        Map<String, Boolean> response = new HashMap<>();
        response.put("deleted", Boolean.TRUE);
        return response;
    }

}

用户服务：

@Service
public class UserService implements IUserService{
    @Autowired
    private UserRepository userRepository;

    @Autowired
    private AccountRepository accountRepository;

    @Override
    public List<User> findAllUsers() {
        return (List<User>) userRepository.findAll();
    }

    @Override
    public Optional<User> findUserById(String userId){
        return userRepository.findById(userId);
    }

    @Override
    public User addUser(User user){
        User userExisted = userRepository.findById(user.getUserId()).get();
        Account accountExisted = accountRepository.findById(user.getAccount().getAccountId()).get();

        if(userExisted != null || accountExisted == null){
            return null;
        } else {
            user.setAccount(accountExisted);
            return userRepository.save(user);
        }
    }

    @Override
    public User updateUser(User userDetails, User user){
        Account accountExisted = accountRepository.findById(userDetails.getAccount().getAccountId()).get();

        if( accountExisted == null){
            return null;
        } else {
            user.setEmailAddress(userDetails.getEmailAddress());
            user.setUserName(userDetails.getUserName());
            user.setAccount(userDetails.getAccount());
            user.setPassword(userDetails.getPassword());
            user.setAccount(accountExisted);

            return userRepository.save(user);
        }
    }

    @Override
    public void deleteUser (User user){
        userRepository.delete(user);
    }
}

【问题讨论】：

@YoManTaMero 可能，但是简单 JSON 格式的帐户，您也需要添加。
好的，我试试，非常感谢。
没什么，同样的异常信息。可能这个问题与另一个有关：stackoverflow.com/questions/41772855/…
你能发布你的异常消息吗？
问题来了。

标签： json spring-boot

【解决方案1】：

在您的 addUser 方法中，您正尝试使用其 userId 加载用户：

@Override
public User addUser(User user){
    User userExisted = userRepository.findById(user.getUserId()).get();
    // ...
}

虽然从技术上讲这很好，但当您知道 user 参数尚未持久化并且因此还没有生成的 id 时，它将不起作用.

你应该：

要么更新您的方法实现，以检查user 输入是否已经包含 userId 属性（如果没有，则假设尚未创建用户）：

 @Override
 public User addUser(User user){
     User userExisted = null;
     if (user.getUserId() != null) {
         userExisted = userRepository.findById(user.getUserId()).get();
     }
     // ...
 }

更新您的 addUser 方法以根据其他唯一谓词（用户名、电子邮件或两者）搜索用户。

请注意，第二个选项将是最合适的选项，并且遵循 RESTful 架构，因为尝试使用现有用户 ID 创建用户应该已经导致错误（您应该根据您的应用程序需要进行翻译）。

【讨论】：

哦，我的错！哈哈 :D 很好的答案，我会修改我的代码。非常感谢@tmarwen。问候。
很高兴能帮上忙 :)