过滤后的数据未显示在我的 UITableView Objective C iOS7 中

Question

我正在尝试在我的 UITableView 中绑定“搜索栏和搜索显示控制器”。过滤后的数组具有正确的数据，但它不显示在 tableview 中。当我在搜索栏中输入内容时，它会显示空白表格视图。 在函数“cellForRowAtIndexPath”中，当它绑定正确的数据但仍未显示时。在同一个函数中，我还更改了代码
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"PersonCell" forIndexPath:indexPath];
到
UITableViewCell *cell = [self.personTableView dequeueReusableCellWithIdentifier:@"PersonCell" forIndexPath:indexPath];

然后它会抛出以下异常： 由于未捕获的异常“NSInvalidArgumentException”而终止应用程序，原因：“-[Person length]: unrecognized selector sent to instance 0x1780ca170”

代码：

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
 if (tableView == self.searchDisplayController.searchResultsTableView) {
    return [self.filteredPersonArray count];
 } else {
    return [self.personArray count];
}
}

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
// Return the number of sections.
return 1;
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"PersonCell" forIndexPath:indexPath];

Person *person;
if (tableView == self.searchDisplayController.searchResultsTableView) {
    person = (Person *)[self.filteredPersonArray objectAtIndex:indexPath.row];
} else {
     person = (Person *)[self.personArray objectAtIndex:indexPath.row];
}
UILabel *nameLabel = (UILabel *)[cell viewWithTag:1];
nameLabel.text = [NSString stringWithFormat:@"%@ %@", person.firstName, person.lastName];
// so on;
return cell;
}

-(void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope {
// Update the filtered array based on the search text and scope.
// Remove all objects from the filtered search array
[self.filteredPersonArray removeAllObjects];
// Filter the array using NSPredicate
NSPredicate *lastNamepredicate = [NSPredicate predicateWithFormat:@"SELF.lastName contains[c] %@",searchText];
//NSPredicate *firstNamePredicate = [NSPredicate predicateWithFormat:@"SELF.firstName contains[c] %@",scope];
//tempArray = [tempArray filteredArrayUsingPredicate:lastNamepredicate];
self.filteredPersonArray = [NSMutableArray arrayWithArray:[self.personArray  
filteredArrayUsingPredicate:lastNamepredicate]];
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller 
shouldReloadTableForSearchString:(NSString *)searchString {
// Tells the table data source to reload when text changes
[self filterContentForSearchText:searchString scope:
 [[self.searchDisplayController.searchBar scopeButtonTitles] objectAtIndex:  
[self.searchDisplayController.searchBar selectedScopeButtonIndex]]];
// Return YES to cause the search result table view to be reloaded.
return YES;
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller 
shouldReloadTableForSearchScope:(NSInteger)searchOption {
// Tells the table data source to reload when scope bar selection changes
[self filterContentForSearchText:self.searchDisplayController.searchBar.text scope:
 [[self.searchDisplayController.searchBar scopeButtonTitles] objectAtIndex:searchOption]];
// Return YES to cause the search result table view to be reloaded.
return YES;
}

Answer 1

这个问题的解决方法：
我在创建单元格时引用了不同的 tableview 对象，以防
1.搜索后加载数据
2. 在tableview中加载数据

- (UITableViewCell *)tableView:(UITableView *)tableView     cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell;
    Person *person;
    if (tableView == self.searchDisplayController.searchResultsTableView) 
    {
        cell = [self.personTableView dequeueReusableCellWithIdentifier:@"PersonCell"];
        person = (Person *)[self.filteredPersonArray objectAtIndex:indexPath.row];
    } else {
        cell = [tableView dequeueReusableCellWithIdentifier:@"PersonCell"];
        person = (Person *)[self.personArray objectAtIndex:indexPath.row];
    }
    UILabel *nameLabel = (UILabel *)[cell viewWithTag:1];
    nameLabel.text = [NSString stringWithFormat:@"%@ %@", person.firstName,     person.lastName];
    // so on;
    return cell;
}