请求处理失败；嵌套异常是 org.springframework.dao.DataIntegrityViolationException：无法执行语句；

Question

我在这里跟进本教程 http://hellokoding.com/registration-and-login-example-with-spring-xml-configuration-maven-jsp-and-mysql/ 使用 spring mvc 和 maven 创建注册和注册流程。 我已经在角色表和用户表之间创建了映射到 user_role 的关系。一切似乎都很好，但是当我尝试创建新用户时，应用程序会抛出错误。

User.java

@ManyToMany
    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "role_id"))
    public Set<Role> getRoles() {
        return roles;
    }

Role.java

@ManyToMany(mappedBy = "roles")
    public Set<User> getUsers() {
        return users;
    }

这是角色表到角色用户表和用户表到角色用户表之间关系的图形表示

请问为什么我会收到此错误Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement;

这是完整的堆栈跟踪

HTTP Status 500 - Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.DataException: could not execute statement
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.DataException: could not execute statement
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:982)
    org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:872)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:648)
    org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:846)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:729)

添加更多堆栈跟踪

root cause
org.hibernate.exception.DataException: could not execute statement
    org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:69)
    org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
    org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
    org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
    org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:211)


root cause

com.mysql.jdbc.MysqlDataTruncation: Data truncation: Data too long for column 'password' at row 1
    com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3845)
    com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3783)
    com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2447)
    com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2594)
    com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2545)
    com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1901)
    com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2113)
    com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2049)
    com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2034)

当我尝试创建新用户时，会出现上述堆栈跟踪

请问我做错了什么？非常感谢

Answer 1

问题很明确“第 1 行的“密码”列的数据太长”

在示例中，您使用 UserService 在保存用户之前对密码进行加密。

这里是 UserServiceImpl.class

@Override
    public void save(User user) {
        user.setPassword(bCryptPasswordEncoder.encode(user.getPassword()));
        user.setRoles(new HashSet<>(roleRepository.findAll()));
        userRepository.save(user);
    }

试试这个link 以查看生成的加密密码并相应地扩展您的列。

我希望这会有所帮助。