Java 通过套接字发送和接收文件 (byte[])

Question

我正在尝试开发一个非常简单的客户端/服务器，客户端将文件转换为字节，将其发送到服务器，然后将字节转换回文件。

目前程序只创建一个空文件。我不是一个出色的 Java 开发人员，因此非常感谢任何帮助。

这是接收客户端发送的内容的服务器部分。

ServerSocket serverSocket = null;

    serverSocket = new ServerSocket(4444);


    Socket socket = null;
    socket = serverSocket.accept();

    DataOutputStream out = new DataOutputStream(new BufferedOutputStream(socket.getOutputStream()));
    DataInputStream in = new DataInputStream(new BufferedInputStream(socket.getInputStream()));
    byte[] bytes = new byte[1024];

    in.read(bytes);
    System.out.println(bytes);

    FileOutputStream fos = new FileOutputStream("C:\\test2.xml");
    fos.write(bytes);

这里是客户端部分

Socket socket = null;
    DataOutputStream out = null;
    DataInputStream in = null;
    String host = "127.0.0.1";     

    socket = new Socket(host, 4444);
    out = new DataOutputStream(new BufferedOutputStream(socket.getOutputStream()));
    in = new DataInputStream(new BufferedInputStream(socket.getInputStream()));

    File file = new File("C:\\test.xml");
    //InputStream is = new FileInputStream(file);
    // Get the size of the file
    long length = file.length();
    if (length > Integer.MAX_VALUE) {
        System.out.println("File is too large.");
    }
    byte[] bytes = new byte[(int) length];

    //out.write(bytes);
    System.out.println(bytes);

    out.close();
    in.close();
    socket.close();

Answer 1

感谢您的帮助。我现在已经设法让它工作了，所以我想我会发布，以便其他人可以用来帮助他们。

服务器：

public class Server {
    public static void main(String[] args) throws IOException {
        ServerSocket serverSocket = null;

        try {
            serverSocket = new ServerSocket(4444);
        } catch (IOException ex) {
            System.out.println("Can't setup server on this port number. ");
        }

        Socket socket = null;
        InputStream in = null;
        OutputStream out = null;
        
        try {
            socket = serverSocket.accept();
        } catch (IOException ex) {
            System.out.println("Can't accept client connection. ");
        }
        
        try {
            in = socket.getInputStream();
        } catch (IOException ex) {
            System.out.println("Can't get socket input stream. ");
        }

        try {
            out = new FileOutputStream("M:\\test2.xml");
        } catch (FileNotFoundException ex) {
            System.out.println("File not found. ");
        }

        byte[] bytes = new byte[16*1024];

        int count;
        while ((count = in.read(bytes)) > 0) {
            out.write(bytes, 0, count);
        }

        out.close();
        in.close();
        socket.close();
        serverSocket.close();
    }
}

和客户：

public class Client {
    public static void main(String[] args) throws IOException {
        Socket socket = null;
        String host = "127.0.0.1";

        socket = new Socket(host, 4444);
        
        File file = new File("M:\\test.xml");
        // Get the size of the file
        long length = file.length();
        byte[] bytes = new byte[16 * 1024];
        InputStream in = new FileInputStream(file);
        OutputStream out = socket.getOutputStream();
        
        int count;
        while ((count = in.read(bytes)) > 0) {
            out.write(bytes, 0, count);
        }

        out.close();
        in.close();
        socket.close();
    }
}

Answer 2

总结 EJP 的答案；使用它以获得更多流动性。 确保不要将他的代码放在更大的 try catch 中，在 .read 和 catch 块之间有更多代码，它可能会返回异常并一直跳转到外部 catch 块，最安全的选择是放置 EJPS 的 while 循环在 try catch 中，然后继续它之后的代码，例如：

int count;
byte[] bytes = new byte[4096];
try {
    while ((count = is.read(bytes)) > 0) {
        System.out.println(count);
        bos.write(bytes, 0, count);
    }
} catch ( Exception e )
{
    //It will land here....
}
// Then continue from here

编辑：^这发生在我身上，因为如果它是客户端到服务器的流，我没有意识到你需要放置 socket.shutDownOutput()！

希望这篇文章能解决你的任何问题

Answer 3

Java中复制流的正确方法如下：

int count;
byte[] buffer = new byte[8192]; // or 4096, or more
while ((count = in.read(buffer)) > 0)
{
  out.write(buffer, 0, count);
}

希望我每次在论坛上发帖都能得到一美元。

Answer 4

为了避免文件大小的限制，在创建文件大小为byte[] bytes = new byte[(int) length];的数组时，会导致抛出异常java.lang.OutOfMemoryError，我们可以这样做

    byte[] bytearray = new byte[1024*16];
    FileInputStream fis = null;
    try {

        fis = new FileInputStream(file);
        OutputStream output= socket.getOututStream();
        BufferedInputStream bis = new BufferedInputStream(fis);

        int readLength = -1;
        while ((readLength = bis.read(bytearray)) > 0) {
            output.write(bytearray, 0, readLength);

        }
        bis.close();
        output.close();
    }
    catch(Exception ex ){

        ex.printStackTrace();
    } //Excuse the poor exception handling...

Answer 5

这里是服务器 打开文件流并通过网络发送

import java.io.BufferedInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;

public class SimpleFileServer {

  public final static int SOCKET_PORT = 5501;
  public final static String FILE_TO_SEND = "file.txt";

  public static void main (String [] args ) throws IOException {
    FileInputStream fis = null;
    BufferedInputStream bis = null;
    OutputStream os = null;
    ServerSocket servsock = null;
    Socket sock = null;
    try {
      servsock = new ServerSocket(SOCKET_PORT);
      while (true) {
        System.out.println("Waiting...");
        try {
          sock = servsock.accept();
          System.out.println("Accepted connection : " + sock);
          // send file
          File myFile = new File (FILE_TO_SEND);
          byte [] mybytearray  = new byte [(int)myFile.length()];
          fis = new FileInputStream(myFile);
          bis = new BufferedInputStream(fis);
          bis.read(mybytearray,0,mybytearray.length);
          os = sock.getOutputStream();
          System.out.println("Sending " + FILE_TO_SEND + "(" + mybytearray.length + " bytes)");
          os.write(mybytearray,0,mybytearray.length);
          os.flush();
          System.out.println("Done.");
        } catch (IOException ex) {
          System.out.println(ex.getMessage()+": An Inbound Connection Was Not Resolved");
        }
        }finally {
          if (bis != null) bis.close();
          if (os != null) os.close();
          if (sock!=null) sock.close();
        }
      }
    }
    finally {
      if (servsock != null)
        servsock.close();
    }
  }
}

这里是客户端 接收通过网络发送的文件

import java.io.BufferedOutputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.Socket;

public class SimpleFileClient {

  public final static int SOCKET_PORT = 5501;
  public final static String SERVER = "127.0.0.1";
  public final static String
       FILE_TO_RECEIVED = "file-rec.txt";

  public final static int FILE_SIZE = Integer.MAX_VALUE;

  public static void main (String [] args ) throws IOException {
    int bytesRead;
    int current = 0;
    FileOutputStream fos = null;
    BufferedOutputStream bos = null;
    Socket sock = null;
    try {
      sock = new Socket(SERVER, SOCKET_PORT);
      System.out.println("Connecting...");

      // receive file
      byte [] mybytearray  = new byte [FILE_SIZE];
      InputStream is = sock.getInputStream();
      fos = new FileOutputStream(FILE_TO_RECEIVED);
      bos = new BufferedOutputStream(fos);
      bytesRead = is.read(mybytearray,0,mybytearray.length);
      current = bytesRead;

      do {
         bytesRead =
            is.read(mybytearray, current, (mybytearray.length-current));
         if(bytesRead >= 0) current += bytesRead;
      } while(bytesRead > -1);

      bos.write(mybytearray, 0 , current);
      bos.flush();
      System.out.println("File " + FILE_TO_RECEIVED
          + " downloaded (" + current + " bytes read)");
    }
    finally {
      if (fos != null) fos.close();
      if (bos != null) bos.close();
      if (sock != null) sock.close();
    }
  }    
}

Answer 6

菜鸟，如果你想通过socket将文件写入服务器，那么使用fileoutputstream而不是dataoutputstream怎么样？ dataoutputstream 更适合协议级别的读写。您的代码在字节读取和写入方面不是很合理。在 java io 中循环读写是必要的。而且，您使用缓冲方式。冲洗是必要的。这是一个代码示例：http://www.rgagnon.com/javadetails/java-0542.html