加入 3 个表 Hibernate 和 JPA

Question

我有三张桌子，我想加入它们，这让我发疯。

标签：任务 项目 用户

它们之间都有多对多关系：比如项目有多个用户，反之亦然，任务也有多个用户，反之亦然，项目和用户也是如此。 p>

我正在尝试找到一种在 JPA 和 Hibernate 中实现它的方法，我有 2 个选择： ** 1 ** 像这样加入 3 个实体：

项目：

   @ManyToMany(fetch = FetchType.EAGER, 
    cascade =
    {
            CascadeType.DETACH,
            CascadeType.MERGE,
            CascadeType.REFRESH,
            CascadeType.PERSIST
    },
    targetEntity = User.class)
  @JoinTable(name = "Collaborators", 
           joinColumns = @JoinColumn(name = "ProjectFk", referencedColumnName = "id", updatable=false, nullable=false), 
           inverseJoinColumns = @JoinColumn(name = "UserFk", referencedColumnName = "id", updatable=false, nullable=false))
  private Set<User> users = new HashSet<>();

用户：

    @ManyToMany(fetch = FetchType.EAGER, 
            cascade =
                {
                        CascadeType.DETACH,
                        CascadeType.MERGE,
                        CascadeType.REFRESH,
                        CascadeType.PERSIST
                },
                targetEntity = Project.class)
    @JoinTable(name = "Collaborators", 
           joinColumns = @JoinColumn(name = "UserFk", referencedColumnName = "id", updatable=false, nullable=false), 
           inverseJoinColumns = @JoinColumn(name = "ProjectFk", referencedColumnName = "id", updatable=false, nullable=false))
    private Set<Project> projects = new HashSet<>();

任务：

    @ManyToMany(fetch = FetchType.EAGER, 
        cascade =
        {
                CascadeType.DETACH,
                CascadeType.MERGE,
                CascadeType.REFRESH,
                CascadeType.PERSIST
        },
        targetEntity = User.class)
    @JoinTable(name = "Collaborators", 
       joinColumns = @JoinColumn(name = "TaskFk", referencedColumnName = "id", updatable=false, nullable=false), 
       inverseJoinColumns = @JoinColumn(name = "ProjectFk", referencedColumnName = "id", updatable=false, nullable=false))
    @MapKeyJoinColumn(name = "User_id")
    @ElementCollection
    private Map<Project, User> projectUserMap = new HashMap<>();

但这里似乎不起作用

2：创建第 4 个实体并将其命名为 Collaborator，然后尝试找到实现此 SQL 查询的方法：

select * from (
select user.id, Project.id, Task.id
inner join Project on user.join_key = Project.join_key
inner join  Task  on task.join_key = = Project.join_key
) collaborator

任何帮助都会非常感激。谢谢。

Answer 1

应该像下面这样实现：

项目类

 @Entity
public class Project extends ABaseEntity{

private Set<User> users = new HashSet<>();

@ManyToMany
@JoinTable(name = "Collaborators",
        joinColumns = @JoinColumn(name = "Project_ID", referencedColumnName = "id", updatable=false, nullable=false),
        inverseJoinColumns = @JoinColumn(name = "User_ID", referencedColumnName = "id", updatable=false, nullable=false))
public Set<User> getUsers() {
    return users;
}

public void setUsers(Set<User> users) {
    this.users = users;
}
}

用户类

@Entity
@Table(name = "EMA_USER")
public class User extends ABaseEntity {

private Set<Project> projects = new HashSet<>();


@ManyToMany(fetch = FetchType.EAGER,
        cascade = CascadeType.ALL,
        targetEntity = Project.class)
@JoinTable(name = "Collaborators",
        joinColumns = @JoinColumn(name = "User_ID", referencedColumnName = "id", updatable = false, nullable = false),
        inverseJoinColumns = @JoinColumn(name = "Project_ID", referencedColumnName = "id", updatable = false, nullable = false))
public Set<Project> getProjects() {
    return projects;
}

public void setProjects(Set<Project> projects) {
    this.projects = projects;
}
}

任务类

@Entity
public class Task extends ABaseEntity{

private Map<Project, User> projectUserMap = new HashMap<>();

@ManyToMany(
        fetch = FetchType.EAGER,
        cascade = CascadeType.ALL
)
@JoinTable(
        name = "Collaborators",
        joinColumns = @JoinColumn(name = "Task_ID", referencedColumnName = "id", updatable = false, nullable = false),
        inverseJoinColumns = @JoinColumn(name = "User_ID", referencedColumnName = "id", updatable = false, nullable = false)
)
@MapKeyJoinColumn(name = "Project_Id")
public Map<Project, User> getProjectUserMap() {
    return projectUserMap;
}

public void setProjectUserMap(Map<Project, User> projectUserMap) {
    this.projectUserMap = projectUserMap;
}
}

您的任务类有什么问题：

@MapKeyJoinColumn(name = "User_id")

@MapKeyJoinColumn 用于映射 key 的列，这里是 Project 实体。

@ElementCollection

如果映射的值为@Embeddable，则使用

@JoinTable

定义实体类与Map的值中定义的实体之间的关系（这里是Task和User之间的关系）。

 targetEntity = User.class

所有 targetEntity 都是多余的，因为您使用了具有已定义泛型类型的集合。

此外，您不必像这样配置 3 个类。据我了解，您只需要一个包含这三个类之间关系的表。 所以只需像这样定义一个名为 Collaboration 的实体：

@Entity
public class Collaboration{
  @ManyToOne
  private User user;
  @ManyToOne
  private Task task;
  @ManyToOne
  private Project project;
}

通过分离的协作实体，您可以找到所有已给用户的协作。

如果没有这个实体，您可以编写一个查询来查找与给定用户相关的所有任务，然后当然可以自己在 java 代码中收集项目和任务。 查询将像

 'Select t from Task t join projectUserMap m where m = :user '