无法捕获错误消息 - selenium java junit

Question

我需要捕获显示的错误消息，我尝试了很多方法，但每个方法都会抛出异常——无法找到元素， 请帮助代码。这些是我尝试过的方法。另外，没有 ID，它是 div 元素。像这样...

<div id="webformErrors" class="text" name="errorContent">
<div>
There were 4 errors:
<ul>
<li>
You did not enter a value for:
<b>First Name</b>
</li>
<li>
You did not enter a value for:
<b>Last Name</b>
</li>
<li>
<li>

//String errormsg;
![enter image description here][1]errormsg = Hcd.findElement(By.xpath("//div[@id=webformErrors']/text()")).getText();

// WebElement divElement = Hcd.findElement(By.className("errorContent"));

// Hcd.findElement(By.name("There were 4 errors:")).isDisplayed();

**String pstring = Hcd.findElement(By.id("webformErrors")).getText();
        System.out.println(pstring);

Answer 1

您输入的类名和名称错误。类名是“文本”，名称是“错误内容”。

WebElement divElement = Hcd.findElement(By.className("text"));