【问题标题】:Split JSON objects in array string using regex使用正则表达式在数组字符串中拆分 JSON 对象
【发布时间】:2018-08-05 02:33:03
【问题描述】:

我有一个格式如下的字符串:

[{"HostName":"taskmanager1","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager1:45454","NodeHTTPAddress":"taskmanager1:8042","LastHealthUpdate":1519568501615,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},{"HostName":"datanode2","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode2:45454","NodeHTTPAddress":"datanode2:8042","LastHealthUpdate":1519260876106,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},{"HostName":"taskmanager3","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager3:45454","NodeHTTPAddress":"taskmanager3:8042","LastHealthUpdate":1519568502251,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},{"HostName":"datanode3","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode3:45454","NodeHTTPAddress":"datanode3:8042","LastHealthUpdate":1519260871527,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},{"HostName":"taskmanager2","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager2:45454","NodeHTTPAddress":"taskmanager2:8042","LastHealthUpdate":1519568502259,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},{"HostName":"datanode1","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode1:45454","NodeHTTPAddress":"datanode1:8042","LastHealthUpdate":1519260875647,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024}]

我想将其拆分为多个(此处为 6 个)JSON 格式,但我的模式无法按需要拆分。

我想要这样的东西:

{"HostName":"taskmanager1","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager1:45454","NodeHTTPAddress":"taskmanager1:8042","LastHealthUpdate":1519568501615,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},
{"HostName":"datanode2","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode2:45454","NodeHTTPAddress":"datanode2:8042","LastHealthUpdate":1519260876106,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},
{"HostName":"taskmanager3","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager3:45454","NodeHTTPAddress":"taskmanager3:8042","LastHealthUpdate":1519568502251,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},
{"HostName":"datanode3","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode3:45454","NodeHTTPAddress":"datanode3:8042","LastHealthUpdate":1519260871527,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024}
,{"HostName":"taskmanager2","Rack":"/default-rack","State":"RUNNING","NodeId":"taskmanager2:45454","NodeHTTPAddress":"taskmanager2:8042","LastHealthUpdate":1519568502259,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024},
{"HostName":"datanode1","Rack":"/default-rack","State":"RUNNING","NodeId":"datanode1:45454","NodeHTTPAddress":"datanode1:8042","LastHealthUpdate":1519260875647,"HealthReport":"","NodeManagerVersion":"2.8.3","NumContainers":0,"UsedMemoryMB":0,"AvailableMemoryMB":1024}

使用代码:

List<String> res = Arrays.asList(temp.replace('[', ' ').replace(']',' ').trim()).split(",");

它将针对每个, 字符进行拆分,并且使用split("},\\}") 模式也会删除}{ 字符。

如何将其拆分为制作 Json 对象的愿望?

使用 Java 模式 (\\{.+}) 将对整个字符串进行分组。

【问题讨论】:

  • 你如何解析 JSON?
  • 使用 JSONObject 和 JSONArray 我无法解析它!
  • 你能显示你试过的代码吗?你遇到的错误是什么?
  • 而且你并不需要一个显式的 JsonObject,你只需要 jsonarray 类
  • 你知道,因为它是一个String,它不能被解析为JSONArray,因为它不是嵌套的JSON,它不能被解析为JSONObject!

标签: java json regex


【解决方案1】:

您可以将 JSON 解析为一个数组,并将其内容视为单独的字符串。这是示例代码:

import org.json.JSONArray;

public class orgJson1Main {
    private static final String sample = "[{\"HostName\":\"taskmanager1\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager1:45454\",\"NodeHTTPAddress\":\"taskmanager1:8042\",\"LastHealthUpdate\":1519568501615,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode2\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode2:45454\",\"NodeHTTPAddress\":\"datanode2:8042\",\"LastHealthUpdate\":1519260876106,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"taskmanager3\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager3:45454\",\"NodeHTTPAddress\":\"taskmanager3:8042\",\"LastHealthUpdate\":1519568502251,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode3\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode3:45454\",\"NodeHTTPAddress\":\"datanode3:8042\",\"LastHealthUpdate\":1519260871527,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"taskmanager2\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager2:45454\",\"NodeHTTPAddress\":\"taskmanager2:8042\",\"LastHealthUpdate\":1519568502259,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode1\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode1:45454\",\"NodeHTTPAddress\":\"datanode1:8042\",\"LastHealthUpdate\":1519260875647,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024}]";

    public static void main(String[] args) {
        JSONArray array = new JSONArray(sample);
        for(int i=0; i < array.length(); i++){
            System.out.println(array.get(i));
        }
    }

}

输出

{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519568501615,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"taskmanager1:45454","UsedMemoryMB":0,"NodeHTTPAddress":"taskmanager1:8042","HostName":"taskmanager1","NumContainers":0}
{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519260876106,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"datanode2:45454","UsedMemoryMB":0,"NodeHTTPAddress":"datanode2:8042","HostName":"datanode2","NumContainers":0}
{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519568502251,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"taskmanager3:45454","UsedMemoryMB":0,"NodeHTTPAddress":"taskmanager3:8042","HostName":"taskmanager3","NumContainers":0}
{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519260871527,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"datanode3:45454","UsedMemoryMB":0,"NodeHTTPAddress":"datanode3:8042","HostName":"datanode3","NumContainers":0}
{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519568502259,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"taskmanager2:45454","UsedMemoryMB":0,"NodeHTTPAddress":"taskmanager2:8042","HostName":"taskmanager2","NumContainers":0}
{"NodeManagerVersion":"2.8.3","Rack":"/default-rack","LastHealthUpdate":1519260875647,"HealthReport":"","State":"RUNNING","AvailableMemoryMB":1024,"NodeId":"datanode1:45454","UsedMemoryMB":0,"NodeHTTPAddress":"datanode1:8042","HostName":"datanode1","NumContainers":0}

编辑:

首先,我从上面的代码中删除了JSONTokener。其次,为了完整起见,我添加了以下代码,显示如何使用最初要求的正则表达式在示例字符串中查找单个 JSON 对象。

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class orgJson1Main {
    private static final String sample = "[{\"HostName\":\"taskmanager1\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager1:45454\",\"NodeHTTPAddress\":\"taskmanager1:8042\",\"LastHealthUpdate\":1519568501615,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode2\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode2:45454\",\"NodeHTTPAddress\":\"datanode2:8042\",\"LastHealthUpdate\":1519260876106,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"taskmanager3\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager3:45454\",\"NodeHTTPAddress\":\"taskmanager3:8042\",\"LastHealthUpdate\":1519568502251,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode3\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode3:45454\",\"NodeHTTPAddress\":\"datanode3:8042\",\"LastHealthUpdate\":1519260871527,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"taskmanager2\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"taskmanager2:45454\",\"NodeHTTPAddress\":\"taskmanager2:8042\",\"LastHealthUpdate\":1519568502259,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024},{\"HostName\":\"datanode1\",\"Rack\":\"/default-rack\",\"State\":\"RUNNING\",\"NodeId\":\"datanode1:45454\",\"NodeHTTPAddress\":\"datanode1:8042\",\"LastHealthUpdate\":1519260875647,\"HealthReport\":\"\",\"NodeManagerVersion\":\"2.8.3\",\"NumContainers\":0,\"UsedMemoryMB\":0,\"AvailableMemoryMB\":1024}]";

    public static void main(String[] args) {

        Matcher matcher = Pattern.compile("\\{[^}]*\\}").matcher(sample);
        while(matcher.find()){
            System.out.println(matcher.group());
        }
    }

}

【讨论】:

【解决方案2】:

要在}, { 上拆分,但在标记中保留大括号,请在此正则表达式上拆分:

"(?<=\\}), (?=\\{)"

它使用 look behindlook ahead 来断言花括号在逗号之前和之后,但 在分裂。

整行就变成了:

List<String> res = Arrays.asList(temp.replaceAll("^.|.$", "").split("(?<=\\}), (?=\\{)");

还要注意前导 [ 和尾随 ] 的简化修剪,但更简单的是在一次操作中删除第一个和最后一个字符。

【讨论】:

    【解决方案3】:

    如果您打算将此列表用作 MyJsonObject 的列表,我建议您重用出色的 google gson 库。 有一种简单的方法可以将 String 转换为 List,而无需使用 List 进行中间操作。 您需要遵循以下步骤。

    1) 创建你的 POJO 类:

    public class POJO 
    {
        String HostName;
        String Rack;
        String State;
        String NodeId;
        String NodeHTTPAddress;
        String LastHealthUpdate;
        String HealthReport;
        String NodeManagerVersion;
        String NumContainers;
        String UsedMemoryMB;
        String AvailableMemoryMB;
        ... getters/setters here ....
    }
    

    2) 创建gson转换器:

    Gson gson = (new GsonBuilder() ).create();
    

    3) 为您的 POJO 列表创建 typeToken:

     Type type = new TypeToken< List<POJO> >(){}.getType();
    

    4) 将String转换为期望的集合:

     List<MyJsonObject> list = gson.fromJson( json, type );
    

    【讨论】:

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