正则表达式在多行文本中获取 @ 和 @ 之间的所有内容

Question

希望你没事。

例如我有一个带有标签的文本 @标签 我想将标签之间的所有文本作为部分（不是一个，看最后的图片，在顶部，结果是 4 个匹配而不是一个）。问题在于每个标签的文本中可能包含符号@，这将减少我的结果匹配。

我尝试了几次不同的正则表达式，但总是没有成功

我使用的最后一个正则表达式是：

((^(@))|[^\"]@)[^(@)]+\}\n

示例centent 文本（我用于尝试）：

@main.xml
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}


@main.xml_fab
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"@firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}


@main.xml
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}

j
@main.xml_fab
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"center"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}
{"adSize":"","adUnitId":"","alpha":1.0,"checked":0,"choiceMode":0,"clickable":1,"convert":"","customView":"","dividerHeight":1,"enabled":1,"firstDayOfWeek":1,"id":"_fab","image":{"rotate":0,"scaleType":"CENTER"},"indeterminate":"false","index":0,"inject":"","layout":{"backgroundColor":16777215,"borderColor":-16740915,"gravity"}

这是图片显示我的问题

我想得到@tag1 和@tag2,3,4...等之间的全部部分， 如果符号@在标签的内容内，我该如何处理？

Answer 1

我不太确定您在表达中使用了[^\"]@...它的目的是什么？你能举个例子吗？

无论如何，您必须从排除字符列表中删除 @。并改变你在部分结束时的样子。试试：

^@[^(]+?\}\n(?=\@|$)

• ^@ 匹配行首的@
• [^(]+? 匹配除 ( 之外的任何字符一次或多次，直到（? 使其变得懒惰）下一个元素的下一次出现...
• \}\n 您的段总是以大括号结尾，后跟新行
• (?=\@|$) 关键部分：确保以下元素是 @（新段）或文件末尾的前瞻，而不捕获它。这样一来，您就不会在一段结束之前剪切一段，您仍然可以捕捉到下一段的开头。

试试Demo

Answer 2

使用

(?m)^@.+(?:\n.+)*

见regex proof。

解释

--------------------------------------------------------------------------------
  ^                        the beginning of the line due to (?m)
--------------------------------------------------------------------------------
  @                        '@'
--------------------------------------------------------------------------------
  .+                       any character except \n (1 or more times
                           (matching the most amount possible))
--------------------------------------------------------------------------------
  (?:                      group, but do not capture (0 or more times
                           (matching the most amount possible)):
--------------------------------------------------------------------------------
    \n                       '\n' (newline)
--------------------------------------------------------------------------------
    .+                       any character except \n (1 or more times
                             (matching the most amount possible))
--------------------------------------------------------------------------------
  )*                       end of grouping