【问题标题】:Some error in hbm.xml filehbm.xml 文件中的一些错误
【发布时间】:2014-10-19 08:18:27
【问题描述】:

我是休眠新手。我正在尝试使用休眠从 oracle 表中简单检索记录。

我的实体类名为pojo1,pojo1.hbm.xml如下:

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd" >

<hibernate-mapping package="hibernate" default-lazy="true">

<class name="pojo1" table="QUOTE_MESSAGE_TRANSLATION_BKP">
<meta attribute="class-description">
</meta>
<property name="id" column="TRANSLATION_ID" type="java.lang.Integer"/>
<property name="commitCode" column="COMMIT_CODE" type="java.lang.Integer"/>
</class>
</hibernate-mapping>

运行包含所有事务代码的应用程序类时出现以下错误:

... ...
INFO: HHH000221: Reading mappings from resource: pojo1.hbm.xml
Aug 26, 2014 10:32:28 AM org.hibernate.internal.util.xml.ErrorLogger logErrors
ERROR: HHH000196: Error parsing XML (3) : The content of element type "class" must     match "(meta*,subselect?,cache?,synchronize*,comment?,tuplizer*,(id|composite-    id),discriminator?,natural-id?,(version|timestamp)?,(property|many-to-one|one-to-one|component|dynamic-component|properties|any|map|set|list|bag|idbag|array|primitive-array)*,((join*,subclass*)|joined-subclass*|union-subclass*),loader?,sql-insert?,sql-update?,sql-delete?,filter*,fetch-profile*,resultset*,(query|sql-query)*)".
Aug 26, 2014 10:32:28 AM org.hibernate.internal.util.xml.ErrorLogger logErrors
ERROR: HHH000196: Error parsing XML (3) : The content of element type "class" must match "(meta*,subselect?,cache?,synchronize*,comment?,tuplizer*,(id|composite-id),discriminator?,natural-id?,(version|timestamp)?,(property|many-to-one|one-to-one|component|dynamic-component|properties|any|map|set|list|bag|idbag|array|primitive-array)*,((join*,subclass*)|joined-subclass*|union-subclass*),loader?,sql-insert?,sql-update?,sql-delete?,filter*,fetch-profile*,resultset*,(query|sql-query)*)".
Failed to create sessionFactory object.org.hibernate.InvalidMappingException: Unable to read XML
Exception in thread "main" java.lang.ExceptionInInitializerError
at hibernate.app.main(app.java:20)
Caused by: org.hibernate.InvalidMappingException: Unable to read XML
at org.hibernate.internal.util.xml.MappingReader.legacyReadMappingDocument(MappingReader.java:375)
at org.hibernate.internal.util.xml.MappingReader.readMappingDocument(MappingReader.java:304)
at org.hibernate.cfg.Configuration.add(Configuration.java:516)
at org.hibernate.cfg.Configuration.add(Configuration.java:512)
at org.hibernate.cfg.Configuration.add(Configuration.java:686)
at org.hibernate.cfg.Configuration.addResource(Configuration.java:769)
at org.hibernate.cfg.Configuration.parseMappingElement(Configuration.java:2255)
at org.hibernate.cfg.Configuration.parseSessionFactory(Configuration.java:2227)
at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:2207)
at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:2160)
at org.hibernate.cfg.Configuration.configure(Configuration.java:2075)
at org.hibernate.cfg.Configuration.configure(Configuration.java:2054)
at hibernate.app.main(app.java:17)
Caused by: org.xml.sax.SAXParseException; lineNumber: 13; columnNumber: 12; The content of element type "class" must match "(meta*,subselect?,cache?,synchronize*,comment?,tuplizer*,(id|composite-id),discriminator?,natural-id?,(version|timestamp)?,(property|many-to-one|one-to-one|component|dynamic-component|properties|any|map|set|list|bag|idbag|array|primitive-array)*,((join*,subclass*)|joined-subclass*|union-subclass*),loader?,sql-insert?,sql-update?,sql-delete?,filter*,fetch-profile*,resultset*,(query|sql-query)*)".
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198)
at .... ....

请帮忙。

【问题讨论】:

    标签: hibernate


    【解决方案1】:

    您必须使用&lt;id&gt; 标签为您的实体类声明id

    所以改变这个:

    <property name="id" column="TRANSLATION_ID" type="java.lang.Integer"/>
    

    到这里:

    <id name="id" column="TRANSLATION_ID" type="int"></id>
    

    【讨论】:

      【解决方案2】:

      您需要在 &lt;class&gt; 元素中添加一个 &lt;id&gt;&lt;composite-id&gt; 元素。

      请参阅文档here

      映射类必须声明数据库的主键列 表。

      【讨论】:

      • 但是id相当于表的主键吧?如果我没有/需要一个怎么办? @罗比
      • 那么看来你是SOL。另见here。绕过它的建议here
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