【发布时间】:2021-07-17 16:48:39
【问题描述】:
有人可以帮忙解答一个问题吗?我已经按照文档制作了对象结构,但是关系芯片 OneToMany 不起作用。
Order:
- Positions
- Partners
I receiving error:
SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (order_id)' at line 1
订单:
@Getter
@Setter
@Entity
@Table(name = "e_orders")
public class Order {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "order_id")
private int orderId;
@Column(unique = true)
private String orderNumber;
private int count;
@OneToMany(mappedBy = "e_orders", fetch = FetchType.LAZY)
private List<Partner> partners;
@OneToMany(mappedBy = "e_orders", fetch = FetchType.LAZY)
private List<Position> positions;
}
合作伙伴:
@Getter
@Setter
@Entity
@Table(name = "e_partner")
public class Partner {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "partner_id")
private int id;
private String name;
private String street;
private String city;
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
@JoinColumn(name = "order_e_id")
private Order attachedOrder;
}
职位:
@Getter
@Setter
@Entity
@Table(name = "e_position")
public class Position {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "position_id")
private int id;
private String guid;
private String posnr;
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
@JoinColumn(name = "order_e_id")
private Order attachedOrder;
}
【问题讨论】:
-
order是一个受限的 SQL 字 -
我已更改为“e_orders”,但仍然是同样的问题
-
分享一个生成的sql,plz
-
你还有
mappedBy = "orders",而属性是order(合伙人+职位) -
尤里·察尔科夫。它在调用创建脚本之前崩溃。它直接在 HibernateJpaConfiguration.class 配置的第一阶段崩溃
标签: java spring jpa spring-data one-to-many