如何从 Spring 3.x 迁移到 5.x？ [复制]

Question

我有一个 Spring 3 项目，我希望将其迁移到 Spring 5。

现在，我在下面给出的项目中有 web.xml：

<servlet-mapping>
                    <servlet-name>mvc-dispatcher</servlet-name>
                    <url-pattern>/registrationapplication/*</url-pattern>
                </servlet-mapping>
                <servlet-mapping>
                    <servlet-name>mvc-dispatcher</servlet-name>
                    <url-pattern>/maintenance/lienholder/*</url-pattern>
                </servlet-mapping>
                <servlet-mapping>
                    <servlet-name>mvc-dispatcher</servlet-name>
                    <url-pattern>/login/*</url-pattern>
                </servlet-mapping>
                <servlet-mapping>
                    <servlet-name>mvc-dispatcher</servlet-name>
                    <url-pattern>/messagemap/*</url-pattern>
                </servlet-mapping>

            <servlet>
                    <servlet-name>mvc-dispatcher</servlet-name>
                    <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class>
                    <load-on-startup>1</load-on-startup>
                </servlet>

            <context-param>
                    <param-name>contextConfigLocation</param-name>
                    <param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
                </context-param>

在迁移之前，我有一些问题。它们如下：

1. 在从 Spring 3.0 迁移到 Spring 5 时，如何将 web.xml 中的以下行转换为基于 Java 的配置

2. 我是否需要阅读 mvc-dispatcher-servlet.xml 还是需要迁移基于 java 的配置以在 spring 5 中转换 mvc-dispatcher-servlet.xml？

Answer 1

1.Spring 5 不需要更改web.xml。您可以更改 servlet 版本（如果需要）。

它保持原样：

Spring 的典型 web.xml：

 <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
      <display-name>example</display-name>
      <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
          <param-name>contextConfigLocation</param-name>
          <param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
      </servlet>
      <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
      </servlet-mapping>
      <!-- Custom Servlet Mapping-->
      <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/registrationapplication/*</url-pattern>
      </servlet-mapping>
      <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/maintenance/lienholder/*</url-pattern>
      </servlet-mapping>
      <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/login/*</url-pattern>
      </servlet-mapping>
      <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/messagemap/*</url-pattern>
      </servlet-mapping>
    </web-app>

1. 您可以使用基于 Java 的配置或基于 xml 的配置。两者都受支持。您仍然可以使用旧配置。

基于 Java 的配置将是这样的：

public class DispatcherServletConfig extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class[] { Configure.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return null;
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/", "/registrationapplication", "/login", "/messagemap", "/maintenance/lienholder"};
    }

}

@Configuration
@EnableWebMvc 
@ComponentScan(value = {"com.example"})
public class Configure {

    @Bean
    public InternalResourceViewResolver getInternalResourceViewResolver() {
        InternalResourceViewResolver resolver = new InternalResourceViewResolver();
        resolver.setPrefix("/WEB-INF/views/");
        resolver.setSuffix(".jsp");
        return resolver;
    }
}