Curl POST命令将json数据传递给spring-boot应用程序不起作用

Question

查看了其他相关帖子，但似乎没有任何效果。

基本上，我想弄清楚如何将数据传递给我宁静的 spring-boot 应用程序。

这是我正在使用的 curl 命令：

$ curl -iX POST -H 'Content-Type: application/json' -d @args.json http://localhost:8080/myapp/dummyApi

args.json 包含：

file: args.json:

{
  "arg1": "hello",
  "arg2": 10, 
  "arg3": {
    "a": "1",
    "b": "2" 
  }
}

API 在MyController.java 中定义如下：

file: MyController.java

@RestController
@RequestMapping("/myapp")
public class MyController {

//...

static class DummyRet {
    private String foo;
    public DummyRet(String f) {
        foo = f;
    }
    public String getFoo() {
        return foo;
    }
    public void setFoo(String foo) {
        this.foo = foo;
    }
}

@RequestMapping(value="/dummyApi", method=RequestMethod.POST)
public DummyRet dummyApi(@RequestParam(value = "arg1", required = false, defaultValue = "") String arg1,
                               @RequestParam(value = "arg2", required = false, defaultValue = "") Long arg2,
                               @RequestParam(value = "arg3", required = false) Map<String, String> arg3) {
    LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
    LOGGER.info("Arguments received:");
    LOGGER.info("arg1: " + arg1);
    LOGGER.info("arg2: " + arg2);
    LOGGER.info("arg3: " + arg3);
    LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
    return new DummyRet("foo");
}

//...
}

curl 命令的返回是 200 成功（因为不需要任何参数）但是 args 的值没有达到dummyApi 方法

$ curl -iX POST -H 'Content-Type: application/json' -d @args.json http://localhost:8080/myapp/dummyApi
HTTP/1.1 200 
Content-Type: application/json;charset=UTF-8
Transfer-Encoding: chunked
Date: Sun, 04 Jun 2017 15:37:42 GMT

{"foo":"foo"}

服务器控制台如下所示：

2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : DispatcherServlet with name 'dispatcherServlet' processing POST request for [/myapp/dummyApi]
2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /myapp/dummyApi
2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Returning handler method [public com.xx.controllers.MyController$DummyRet com.xx.controllers.MyController.dummyApi(java.lang.String,java.lang.Long,java.util.Map<java.lang.String, java.lang.String>)]
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : Arguments received:
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : arg1: 
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : arg2: null
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : arg3: null
2017-06-04 18:17:56.819  INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController       : >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] m.m.a.RequestResponseBodyMethodProcessor : Written [com.xx.controllers.MyController$DummyRet@c35d46f] as "application/json" using [org.springframework.http.converter.json.MappingJackson2HttpMessageConverter@301ec38b]
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : Successfully completed request

我希望我没有遗漏任何重要的细节，但如果有任何遗漏，请告诉我。

Answer 1

这行得通：

我的 spring-boot java 方法有两个问题，

1. 我为参数指定了@RrequestParam，而我应该使用@RequestBody
2. 我有多个这样的方法参数，在 POST 中它应该是一个（见脚注）@RequestBody

但由于我需要将多个参数传递给该方法，因此解决方案是将这些参数包装在一个支持对象中，如下所示：

public static class Args {
    // members
    private String arg1;
    private Long arg2;
    private Map<String, String> arg3;
    // accessors
    public String getArg1() {return arg1;}
    public void setArg1(String arg1) {this.arg1 = arg1;}
    public Long getArg2() {return arg2;}
    public void setArg2(Long arg2) {this.arg2 = arg2;}
    public Map<String, String> getArg3() {return arg3;}
    public void setArg3(Map<String, String> arg3) {this.arg3 = arg3;}
}

接收器方法将是：

@RequestMapping(value="/dummyApi", method=RequestMethod.POST)
public DummyRet dummyApi(@RequestBody Args args) {
  LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
  LOGGER.info("Arguments received:");
  LOGGER.info("arg1: " + args.getArg1().toString());
  LOGGER.info("arg2: " + args.getArg2().toString());
  LOGGER.info("arg3: " + args.getArg3().toString());
  LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
  return new DummyRet("foo");
}

脚注：事实上，可以通过自定义实现传递多个参数，如this SO 响应中所述。没试过

Answer 2

参考下面的示例，

curl -H "Content-Type: application/json" --data @body.json 
http://localhost:8080/ui/webapp/conf