使用扫描仪接受字符串输入并存储在字符串数组中

Question

谁能帮帮我。我进行了多次搜索，但在任何地方都找不到解决方案。 我是 Java 的初学者，目前正在大学休息期间练习一些代码。

我正在尝试制作电话簿程序。目前我正在尝试添加新联系人，下面是我拥有的代码，但我不确定如何将信息存储在数组中，有人可以给我一些指点。

    import java.util.Scanner;

    public class addContact {
    public static void main(String [] args){

    //declare arrays
        String [] contactName = new String [12];
        String [] contactPhone = new String [12];
        String [] contactAdd1 = new String [12];
        String [] contactAdd2 = new String [12];

    //inputs
    String name = "";
    String phone = "";
    String add1 = "";
    String add2 = "";

    //method of taken input
    Scanner input = new Scanner(System.in);

    //while name field is empty display prompt etc.
    while (name.equals(""))
    {
    System.out.println("Enter contacts name: ");
    name = input.nextLine();
    name += contactName[];
    }


    while (add1.equals(""))
    {
    System.out.println("Enter contacts addressline1:");
    add1 = input.nextLine();
    add1 += contactAdd1[];
    }

    while (add2.equals(""))
    {
    System.out.println("Enter contacts addressline2:");
    add2 = input.nextLine();
    add2 += contactAdd2[];
    }

    while (phone.equals(""))
    {
    System.out.println("Enter contact phone number: ");
    phone = input.nextLine();
    phone += contactPhone[];
    }

    }   
}

Answer 1

更简洁的方法是创建一个包含contactName、contactPhone 等的Person 对象。然后，使用ArrayList 而不是数组来添加新对象。创建一个循环，接受每个 `Person:

的所有字段

while (!done) {
   Person person = new Person();
   String name = input.nextLine();
   person.setContactName(name);
   ...

   myPersonList.add(person);
}

使用列表将消除对数组边界检查的需要。

Answer 2

这段代码的问题之一是：

name += contactName[];

此指令不会在数组中插入任何内容。相反，它会将变量名称的当前值与contactName 数组的字符串表示形式连接起来。

改用这个：

contactName[index] = name;

这条指令会将变量名存储在索引index处的contactName数组中。

您遇到的第二个问题是您没有变量index。

你可以做的是一个循环 12 次迭代来填充你的所有数组。 （而index 将是您的迭代变量）

Answer 3

//go through this code I have made several changes in it//

import java.util.Scanner;

public class addContact {
public static void main(String [] args){

//declare arrays
String [] contactName = new String [12];
String [] contactPhone = new String [12];
String [] contactAdd1 = new String [12];
String [] contactAdd2 = new String [12];
int i=0;
String name = "0";
String phone = "0";
String add1 = "0";
String add2 = "0";
//method of taken input
Scanner input = new Scanner(System.in);

//while name field is empty display prompt etc.
while (i<11)
{
    i++;
System.out.println("Enter contacts name: "+ i);
name = input.nextLine();
name += contactName[i];
}


while (i<12)
{
    i++;
System.out.println("Enter contacts addressline1:");
add1 = input.nextLine();
add1 += contactAdd1[i];
}

while (i<12)
{
    i++;
System.out.println("Enter contacts addressline2:");
add2 = input.nextLine();
add2 += contactAdd2[i];
}

while (i<12)
{
    i++;
System.out.println("Enter contact phone number: ");
phone = input.nextLine();
phone += contactPhone[i];
}

}   
}

Answer 4

这样会更好吗？

import java.util.Scanner;

public class Work {

public static void main(String[] args){

    System.out.println("Please enter the following information");

    String name = "0";
    String num = "0";
    String address = "0";

    int i = 0;

    Scanner input = new Scanner(System.in);

    //The Arrays
    String [] contactName = new String [7];
    String [] contactNum = new String [7];
    String [] contactAdd = new String [7];

    //I set these as the Array titles
    contactName[0] = "Name";
    contactNum[0] = "Phone Number";
    contactAdd[0] = "Address";

    //This asks for the information and builds an Array for each
    //i -= i resets i back to 0 so the arrays are not 7,14,21+
    while (i < 6){

        i++;
        System.out.println("Enter contact name." + i);
        name = input.nextLine();
        contactName[i] = name;
    }

    i -= i;
    while (i < 6){
        i++;
        System.out.println("Enter contact number." + i);
        num = input.nextLine();
        contactNum[i] = num;
    }

    i -= i;
    while (i < 6){
        i++;
        System.out.println("Enter contact address." + i);
        num = input.nextLine();
        contactAdd[i] = num;
    }


    //Now lets print out the Arrays
    i -= i;
    while(i < 6){
    i++;
    System.out.print( i + " " + contactName[i] + " / " );
    }

    //These are set to print the array on one line so println will skip a line
    System.out.println();
    i -= i;
    i -= 1;

    while(i < 6){
    i++;

    System.out.print( i + " " + contactNum[i] + " / " );
    }

    System.out.println();
    i -= i;
    i -= 1;

    while(i < 6){
        i++;

    System.out.print( i + " " + contactAdd[i] + " / " );
    }

    System.out.println();

    System.out.println("End of program");

}

}

Answer 5

如果我错了，请纠正我。`

public static void main(String[] args) {

    Scanner na = new Scanner(System.in);
    System.out.println("Please enter the number of contacts: ");
    int num = na.nextInt();

    String[] contactName = new String[num];
    String[] contactPhone = new String[num];
    String[] contactAdd1 = new String[num];
    String[] contactAdd2 = new String[num];

    Scanner input = new Scanner(System.in);

    for (int i = 0; i < num; i++) {

        System.out.println("Enter contacts name: " + (i+1));
        contactName[i] = input.nextLine();

        System.out.println("Enter contacts addressline1: " + (i+1));
        contactAdd1[i] = input.nextLine();

        System.out.println("Enter contacts addressline2: " + (i+1));
        contactAdd2[i] = input.nextLine();

        System.out.println("Enter contact phone number: " + (i+1));
        contactPhone[i] = input.nextLine();

    }

    for (int i = 0; i < num; i++) {
        System.out.println("Contact Name No." + (i+1) + " is "+contactName[i]);
        System.out.println("First Contacts Address No." + (i+1) + " is "+contactAdd1[i]);
        System.out.println("Second Contacts Address No." + (i+1) + " is "+contactAdd2[i]);
        System.out.println("Contact Phone Number No." + (i+1) + " is "+contactPhone[i]);
    }
}

`

Answer 6

到目前为止，java 中还没有使用指针。您可以从类中创建一个对象，并使用相互链接的不同类，并使用主类中每个类的功能。