【问题标题】:Force escaping Special character in XML Marshalling in SpringSpring中XML编组中的强制转义特殊字符
【发布时间】:2016-11-17 19:52:38
【问题描述】:

我想在使用 Spring Marshaller 时强制转义特殊字符。当我使用 javax.xml.bind.Marshaller

时,下面的代码完美运行

图书课

package com.odr.core.action;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRegistry;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "book")
public class Book {

    private String name;
    private String author;
    private String publisher;
    private String isbn;

    @XmlJavaTypeAdapter(value=CDATAAdapter.class)
    private String description;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getAuthor() {
        return author;
    }

    public void setAuthor(String author) {
        this.author = author;
    }

    public String getPublisher() {
        return publisher;
    }

    public void setPublisher(String publisher) {
        this.publisher = publisher;
    }

    public String getIsbn() {
        return isbn;
    }

    public void setIsbn(String isbn) {
        this.isbn = isbn;
    }

    public String getDescription() {
        return description;
    }

    public void setDescription(String description) {
        this.description = description;
    }

    @Override
    public String toString() {
        return "Book [name=" + name + ", author=" + author + ", publisher="
            + publisher + ", isbn=" + isbn + ", description=" + description
            + "]";
    }   
}

对象到 XML

        writer = new BufferedWriter(new FileWriter(selectedFile));
        context = JAXBContext.newInstance(Book.class);
        Marshaller m = context.createMarshaller();
        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

        m.setProperty("com.sun.xml.bind.marshaller.CharacterEscapeHandler",
                new CharacterEscapeHandler() {
                    @Override
                    public void escape(char[] ch, int start, int length,
                            boolean isAttVal, Writer writer)
                            throws IOException {
                        writer.write(ch, start, length);
                    }
                });
        m.marshal(book, writer);

输出:

<description>

<![CDATA[<p>With hundreds of practice questions and hands-on exercises, <b>SCJP Sun Certified Programmer for Java 6 Study Guide</b> covers what you need to know--and shows you how to prepare--for this challenging exam. </p>]]>
</description>

但是当我使用 org.springframework.oxm.jaxb.Jaxb2Marshaller 时,同样的代码不起作用,下面是代码

    Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
    Map<String, Object> map = new HashMap<String, Object>();
    map.put("jaxb.formatted.output", true);
    jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
    // com.sun.xml.bind.characterEscapeHandler
    // com.sun.xml.bind.marshaller.CharacterEscapeHandler
    map.put("com.sun.xml.bind.marshaller.CharacterEscapeHandler",
            new CharacterEscapeHandler() {
                @Override
                public void escape(char[] ac, int i, int j, boolean flag,
                        Writer writer) throws IOException {
                    writer.write(ac, i, j);
                }
            });
    jaxb2Marshaller.setMarshallerProperties(map);

    org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
    FileOutputStream fos = null;
    // String fileNamePath = directory.getAbsolutePath() + "\\" + fileName;

    try {
        // fos = new FileOutputStream(fileNamePath);
        fos = new FileOutputStream(selectedFile);
        marshaller.marshal(book, new StreamResult(fos));

        // File f = new File(directory,fileName);
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (fos != null) {
            fos.close();
        }
    }

输出

&lt;description&gt;&amp;lt;![CDATA[&amp;lt;p&amp;gt;With hundreds of practice questions and hands-on exercises, &amp;lt;b&amp;gt;SCJP Sun Certified Programmer for Java 6 Study Guide&amp;lt;/b&amp;gt; covers what you need to know--and shows you how to prepare--for this challenging exam. &amp;lt;/p&amp;gt;]]&amp;gt;&lt;/description&gt;

第一个 sn-p 没有编码特殊字符。但是使用 Spring 的第二个 sn-p 虽然我设置了属性,但确实进行了编码。为了不影响现有代码,我必须在我的项目中使用 Spring。有什么办法可以解决吗

【问题讨论】:

  • 您使用的是哪个版本的 Spring?我用 Spring 4.x 尝试了相同的 Jaxb2Marshaller 代码,它对我有用。
  • 我正在使用 spring-oxm-4.1.5.RELEASE.jar
  • 可以分享一下Book类吗?

标签: java xml spring jaxb marshalling


【解决方案1】:

好的,我遇到了同样的问题,我就这样解决了。

首先要做的事情。您应该创建两个 bean。一个用于Jaxb2Marshaller,另一个用于MarshallingHttpMessageConverter。我假设你想保留你的配置,所以我将使用你的代码。

创建Jaxb2Marshaller bean:

@Bean
public Jaxb2Marshaller getJaxb2Marshaller() {
    Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
    Map<String, Object> map = new HashMap<String, Object>();
    map.put("jaxb.formatted.output", true);
    jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
    map.put("com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler",
            new CharacterEscapeHandler() {
                @Override
                public void escape(char[] ac, int i, int j, boolean flag,
                                   Writer writer) throws IOException {
                    writer.write(ac, i, j);
                }
            });
    jaxb2Marshaller.setMarshallerProperties(map);

    org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
    FileOutputStream fos = null;

    try {
        fos = new FileOutputStream(selectedFile);
        marshaller.marshal(book, new StreamResult(fos));
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (fos != null) {
            fos.close();
        }
    }

    return jaxb2Marshaller;
}

好吧,我使用的是 Java 8,所以我将 com.sun.xml.bind.marshaller.CharacterEscapeHandler 更改为 com.sun.xml.internal .bind.marshaller.CharacterEscapeHandler 如上所示。

创建MarshallingHttpMessageConverter bean:

@Bean
public MarshallingHttpMessageConverter getMarshallingHttpMessageConverter() {
    return new MarshallingHttpMessageConverter(getJaxb2Marshaller());
}

您必须注意到我创建了自己的 HttpMessageConverter 来解决问题。这是因为 Spring 使用它自己的转换器,每次需要将实体或 DTO 转换为 XML 对象时,它都会创建一个新的 Marshaller 实例。所以,我认为下面的代码将解决您的问题。希望对你有帮助。

import com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.http.converter.xml.MarshallingHttpMessageConverter;
import org.springframework.oxm.jaxb.Jaxb2Marshaller;

@Configuration
public class XmlParseConfig {
    @Bean
    public Jaxb2Marshaller getJaxb2Marshaller() {
        Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
        Map<String, Object> map = new HashMap<String, Object>();
        map.put("jaxb.formatted.output", true);
        jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
        map.put("com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler",
                new CharacterEscapeHandler() {
                    @Override
                    public void escape(char[] ac, int i, int j, boolean flag,
                                       Writer writer) throws IOException {
                        writer.write(ac, i, j);
                    }
                });
        jaxb2Marshaller.setMarshallerProperties(map);

        org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
        FileOutputStream fos = null;

        try {
            fos = new FileOutputStream(selectedFile);
            marshaller.marshal(book, new StreamResult(fos));
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            if (fos != null) {
                fos.close();
            }
        }

        return jaxb2Marshaller;
    }

    @Bean
    public MarshallingHttpMessageConverter getMarshallingHttpMessageConverter() {
        return new MarshallingHttpMessageConverter(getJaxb2Marshaller());
    }
}

【讨论】:

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