【发布时间】:2018-03-16 02:02:57
【问题描述】:
我正在尝试进入 IoT 并希望让应用程序将字符串从 android 手机发送到 Linux pc。该应用程序通过实现异步任务来做到这一点:
//From the java docs, slightly modified
private Void sendThroughSocket(String s, String host, int port) {
Log.d("E", "In send through socket");
final String hostName = host;//Host is the address of the receiver, can be IP or domain
int portNumber = port;
//Check if device is connected to internet
try {
Socket clientsocket = new Socket(hostName, portNumber); //one of 2-way point communication
Log.d("E", "Created Socket: ");
DataOutputStream DOS = new DataOutputStream(clientsocket.getOutputStream());
if (clientsocket.isConnected())
Log.d("E", "Socket connected");
DOS.writeUTF(s);
clientsocket.close();
} catch (UnknownHostException e) {
System.err.println("Don't know about host " + hostName);
new Runnable() {
public void run() {
Toast.makeText(context, "Don't know about host " + hostName, Toast.LENGTH_SHORT).show();
}
};
} catch (IOException e) {
System.err.println("Couldn't get I/O for the connection to " + hostName);
//Toast can not be run using asynctask since it acesses UI
new Runnable() {
public void run() {
Toast.makeText(context, "Couldn't get I/O for the connection to " + hostName + " , check the port", Toast.LENGTH_SHORT).show();
}
};
} catch (Exception e) {
Log.d("E", "#fares" + e.getClass().getName().toString());
}
return null;
}
我尝试发送字符串 3 次,所有这些都是从我的搜索栏触发的(我将搜索栏进度值作为我的字符串发送): 公共无效onProgressChanged(SeekBar seekBar,int i,布尔b) 公共无效 onStartTrackingTouch(SeekBar seekBar) public void onStopTrackingTouch(SeekBar seekBar)
所有 3 个的实现都是相同的: public void onProgressChanged(SeekBar seekBar, int i, boolean b) {
progressvalue = i;
textView.setText("Brightness = " + progressvalue + " %");
if (((RecieverPort.equals("Please enter port Number")) || (RecieverIP.equals("Please enter receiver IP")))) {
//Make sure toast isn't persistent
if (IPPortToastcount++ == 0)
Toast.makeText(MainActivity.this, "Please set both IP and Port ", Toast.LENGTH_SHORT).show();
} else {
//Check if connected to internet
if (!isConnectedtoInternet(MainActivity.this)) {
if (ConnectivityToastCount++ < 1)
Toast.makeText(MainActivity.this, "You are not connected to the Internet", Toast.LENGTH_SHORT).show();
} else {
//Send text over wifi
SendText ST = new SendText(getApplicationContext());
ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
ST.cancel(false);
}
}
}
主要
//Send text over wifi
SendText ST = new SendText(getApplicationContext());
ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
ST.cancel(false);
服务器端(我的电脑)非常简单:
int portNumber = 44339; // Choose unused port on router
//Open a socket
try {
//System.out.println("in try statement");
try (ServerSocket serverSocket1 = new ServerSocket(portNumber)) {
portNumber = serverSocket1.getLocalPort();
System.out.println("Created socket at port " + portNumber);
Socket clientSocket = serverSocket1.accept();
System.out.println("Accepted");
DataInputStream DIS = new DataInputStream(clientSocket.getInputStream()); //get input from socket
//System.out.println("Created reader");
String inputLine;
// System.out.println("About to read");
while (DIS.available() > 0) {
inputLine = DIS.readUTF();
System.out.println(inputLine);
}
}
} catch (Exception e) {
System.out.println("Exception caught when trying to listen on port "
+ portNumber + " or listening for a connection");
System.out.println(e.getClass().getSimpleName());
}
这种工作,除了接受服务器套接字之前需要很长时间(秒)。它也只适用于 onprogresschanged ,这让我相信
//Send text over wifi
SendText ST = new SendText(getApplicationContext());
ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
ST.cancel(false);
在成功创建套接字并连接到电脑之前需要。如何确保一次点击或一次调用函数就足以发送字符串? 抱歉发了这么长的帖子,但这是我第一次问:)
编辑:我的新服务器代码:
try {
//System.out.println("in try statement");
try ( ServerSocket serverSocket1 = new ServerSocket(portNumber))
{
portNumber = serverSocket1.getLocalPort();
System.out.println("Created socket at port " + portNumber);
while(true){
Socket clientSocket = serverSocket1.accept();
// System.out.println("Accepted");
DataInputStream DIS = new DataInputStream(clientSocket.getInputStream()); //get input from socket
//System.out.println("Created reader");
//String inputLine;
//System.out.println("About to read");
System.out.println(DIS.readUTF());
}
}
} catch (Exception e) {
System.out.println("Exception caught when trying to listen on port "
+ portNumber + " or listening for a connection");
System.out.println(e.getClass().getSimpleName());
}
值得注意的是,即使在 while true 循环中,服务器总是会显示 4 个数字然后停止。
编辑:这是一个示例日志: 10-06 20:08:09.145 26372-26372/com.example.fares.ledslider D/E: #fares in test method value = 50 10-06 20:08:26.475 26372-26372/com.example.fares.ledslider D/E: #Fares in start tracking 10-06 20:08:26.722 26372-27004/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:26.810 26372-26764/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:27.241 26372-27003/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:27.304 26372-26372/com.example.fares.ledslider D/E: #fares in stop tracking
【问题讨论】:
-
因此,一旦一个客户端连接,您的服务器就会关闭。其他客户端无法连接。您应该为服务器创建一个循环,以便在完成后等待下一个客户端。
-
循环应该从 Socket clientSocket = serverSocket1.accept(); 开始
-
只需使用一个按钮来启动一个异步任务。然后看看连接需要多长时间。
-
知道当用户移动滑块时您启动了多少异步任务?
-
@greenapps 我会在要点中回答,并感谢您的帮助:) - 我添加了一个循环,它工作得更好但仍然不快 - 如果我点击搜索栏上的某个地方,那也很好按下按钮时,它不连接。 - asynctaks 的数量是可变的,它取决于 seekbar 进度值的变化,即,如果从 100 变为 99,则为 3。总共公式 NumberOfAsyncTasksLaunched= ChangeInSeekBarProgress + 2
标签: java android sockets network-programming java-websocket