【问题标题】:Android and java sockets. Sockets connection attempted many times before successAndroid 和 Java 套接字。成功前多次尝试套接字连接
【发布时间】:2018-03-16 02:02:57
【问题描述】:

我正在尝试进入 IoT 并希望让应用程序将字符串从 android 手机发送到 Linux pc。该应用程序通过实现异步任务来做到这一点:

//From the java docs, slightly modified
private Void sendThroughSocket(String s, String host, int port) {
    Log.d("E", "In send through  socket");
    final String hostName = host;//Host is the address of the receiver, can be IP or domain
    int portNumber = port;
    //Check if device is connected to internet

    try {
        Socket clientsocket = new Socket(hostName, portNumber); //one of 2-way point communication
        Log.d("E", "Created Socket: ");
        DataOutputStream DOS = new DataOutputStream(clientsocket.getOutputStream());
        if (clientsocket.isConnected())
            Log.d("E", "Socket connected");
        DOS.writeUTF(s);
        clientsocket.close();
    } catch (UnknownHostException e) {
        System.err.println("Don't know about host " + hostName);
        new Runnable() {
            public void run() {
                Toast.makeText(context, "Don't know about host " + hostName, Toast.LENGTH_SHORT).show();
            }
        };

    } catch (IOException e) {
        System.err.println("Couldn't get I/O for the connection to " + hostName);
        //Toast can not be run using asynctask since it acesses UI
        new Runnable() {
            public void run() {
                Toast.makeText(context, "Couldn't get I/O for the connection to " + hostName + " , check the port", Toast.LENGTH_SHORT).show();
            }
        };

    } catch (Exception e) {
        Log.d("E", "#fares" + e.getClass().getName().toString());

    }
    return null;
}

我尝试发送字符串 3 次,所有这些都是从我的搜索栏触发的(我将搜索栏进度值作为我的字符串发送): 公共无效onProgressChanged(SeekBar seekBar,int i,布尔b) 公共无效 onStartTrackingTouch(SeekBar seekBar) public void onStopTrackingTouch(SeekBar seekBar)

所有 3 个的实现都是相同的: public void onProgressChanged(SeekBar seekBar, int i, boolean b) {

                    progressvalue = i;
                    textView.setText("Brightness = " + progressvalue + " %");


                    if (((RecieverPort.equals("Please enter port Number")) || (RecieverIP.equals("Please enter receiver IP")))) {

                        //Make sure toast isn't persistent
                        if (IPPortToastcount++ == 0)
                            Toast.makeText(MainActivity.this, "Please set both IP and Port ", Toast.LENGTH_SHORT).show();

                    } else {
                        //Check if connected to internet
                        if (!isConnectedtoInternet(MainActivity.this)) {
                            if (ConnectivityToastCount++ < 1)
                                Toast.makeText(MainActivity.this, "You are not connected to the Internet", Toast.LENGTH_SHORT).show();
                        } else {
                            //Send text over wifi
                            SendText ST = new SendText(getApplicationContext());
                            ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
                            ST.cancel(false);


                        }

                    }


                }

主要

//Send text over wifi
                            SendText ST = new SendText(getApplicationContext());
                            ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
                            ST.cancel(false);

服务器端(我的电脑)非常简单:

int portNumber =  44339; // Choose unused port on router
    //Open a socket

    try {

        //System.out.println("in try statement");
        try (ServerSocket serverSocket1 = new ServerSocket(portNumber)) { 
            portNumber = serverSocket1.getLocalPort();
           System.out.println("Created socket at port " + portNumber);
            Socket clientSocket = serverSocket1.accept();

            System.out.println("Accepted");

            DataInputStream DIS = new DataInputStream(clientSocket.getInputStream()); //get input from socket
            //System.out.println("Created reader");

            String inputLine;


           // System.out.println("About to read");


            while (DIS.available() > 0) {
                inputLine = DIS.readUTF();
                System.out.println(inputLine);
            }


        }
    } catch (Exception e) {
        System.out.println("Exception caught when trying to listen on port "
                + portNumber + " or listening for a connection");
        System.out.println(e.getClass().getSimpleName());
    }

这种工作,除了接受服务器套接字之前需要很长时间(秒)。它也只适用于 onprogresschanged ,这让我相信

//Send text over wifi
                            SendText ST = new SendText(getApplicationContext());
                            ST.execute(String.valueOf(progressvalue), RecieverIP, RecieverPort);
                            ST.cancel(false);

在成功创建套接字并连接到电脑之前需要。如何确保一次点击或一次调用函数就足以发送字符串? 抱歉发了这么长的帖子,但这是我第一次问:)

编辑:我的新服务器代码:

try {

        //System.out.println("in try statement");
        try ( ServerSocket serverSocket1 = new ServerSocket(portNumber)) 
        { 
            portNumber = serverSocket1.getLocalPort();
           System.out.println("Created socket at port " + portNumber);
           while(true){
            Socket clientSocket = serverSocket1.accept();

           // System.out.println("Accepted");

            DataInputStream DIS = new DataInputStream(clientSocket.getInputStream()); //get input from socket
            //System.out.println("Created reader");

            //String inputLine;


           //System.out.println("About to read");
           System.out.println(DIS.readUTF());


            }


        }
    } catch (Exception e) {
        System.out.println("Exception caught when trying to listen on port "
                + portNumber + " or listening for a connection");
        System.out.println(e.getClass().getSimpleName());
    }

值得注意的是,即使在 while true 循环中,服务器总是会显示 4 个数字然后停止。

编辑:这是一个示例日志: 10-06 20:08:09.145 26372-26372/com.example.fares.ledslider D/E: #fares in test method value = 50 10-06 20:08:26.475 26372-26372/com.example.fares.ledslider D/E: #Fares in start tracking 10-06 20:08:26.722 26372-27004/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:26.810 26372-26764/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:27.241 26372-27003/com.example.fares.ledslider D/E: #fares 套接字已连接 10-06 20:08:27.304 26372-26372/com.example.fares.ledslider D/E: #fares in stop tracking

【问题讨论】:

  • 因此,一旦一个客户端连接,您的服务器就会关闭。其他客户端无法连接。您应该为服务器创建一个循环,以便在完成后等待下一个客户端。
  • 循环应该从 Socket clientSocket = serverSocket1.accept(); 开始
  • 只需使用一个按钮来启动一个异步任务。然后看看连接需要多长时间。
  • 知道当用户移动滑块时您启动了多少异步任务?
  • @greenapps 我会在要点中回答,并感谢您的帮助:) - 我添加了一个循环,它工作得更好但仍然不快 - 如果我点击搜索栏上的某个地方,那也很好按下按钮时,它不连接。 - asynctaks 的数量是可变的,它取决于 seekbar 进度值的变化,即,如果从 100 变为 99,则为 3。总共公式 NumberOfAsyncTasksLaunched= ChangeInSeekBarProgress + 2

标签: java android sockets network-programming java-websocket


【解决方案1】:

ST.cancel() 可以被移除。也不等待可用性看起来不好。

【讨论】:

    猜你喜欢
    • 2017-11-10
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 2013-05-21
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    相关资源
    最近更新 更多