【发布时间】:2020-12-10 12:36:51
【问题描述】:
我正在尝试使用 Spring Data 中的 @Query 注释在连接字段上将排序与 Pageable 集成。
第一个接口的方法(没有@Query,但有Pageable)就像一个魅力。就像我只使用@Query 获取一名员工时一样,但我使用Pageable 而不是Optional<Employee> 那里(第三种方法)。 但是当我尝试将这两者合二为一时,乐趣就开始了——它不再起作用了。
当我尝试按 name 字段对数据进行排序时,它会报错:
Caused by: org.hibernate.QueryException: could not resolve property: name of: (....).model.employee.Employee
所以问题是:如何告诉 spring 在连接字段中查找 name?如何使用 Spring Data 做到这一点?
我已经尝试了几件事,但它们都不起作用或者我仍然不知道如何正确使用它们:
- 有人建议将
countQuery添加到@Query参数中,这样这与分页(spring data jpa @query and pageable)以某种方式对应 - 我关注了Baeldung's tutorial,但这不包括连接
-
Spring-Data FETCH JOIN with Paging is not working 也建议使用
countQuery,但我更愿意坚持使用Page<Employee>而不是List<Employee>。
我将在下面留下一些代码示例。如果我遗漏了重要的内容,请随时要求更新。
// Employee
@Entity
@Table(name = "employee", schema = "emp")
@Data
@NoArgsConstructor
public class Employee {
private static final String SEQUENCE = "EMPLOYEE_SEQUENCE";
@Id
@SequenceGenerator(sequenceName = SEQUENCE, name = SEQUENCE, allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = SEQUENCE)
private Long id;
@Column(name = "employee_number")
private String employeeNumber;
@Column
@Enumerated(EnumType.STRING)
private EmployeeStatus status;
@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@Audited(targetAuditMode = RelationTargetAuditMode.NOT_AUDITED)
@JoinColumn(name = "id_details")
private Details details;
// some other fields ...
}
// Details
@Entity
@Table(name = "details", schema = "emp")
@Data
@NoArgsConstructor
public class Details {
private static final String SEQUENCE = "DETAILS_SEQUENCE";
@Id
@SequenceGenerator(sequenceName = SEQUENCE, name = SEQUENCE, allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = SEQUENCE)
private Long id;
private String name;
private String surname;
// some other fields ...
}
// EmployeeDTO
@NoArgsConstructor
@AllArgsConstructor
@Data
@Builder(toBuilder = true)
public class EmployeeDTO {
private Long id;
private String employeeNumber;
private String status;
private String name;
private String surname;
// some other fields ...
}
// EmployeeRepository
@Repository
public interface EmployeeRepository extends JpaRepository<Employee, Long> {
// 1st method
Page<Employee> findByStatus(EmployeeStatus status, Pageable pageable);
// 2nd method
@Query(value = "select e from Employee e join e.details where e.status = :status",
countQuery = "select count(*) from Employee e join e.details where e.status = :status")
Page<Employee> getEmployeeDetails(@Param("status") EmployeeStatus status, Pageable pageable);
// 3rd method
@Query("select e from Employee e join fetch e.details where e.id = :id")
Optional<Employee> findByIdWithDetails(Long id);
// ...
}
// EmployeeService
@Service
public class EmployeeService {
private final EmployeeRepository employeeRepository;
private final EntityDtoConverter entityDtoConverter;
@Autowired
public EmployeeService(EmployeeRepository employeeRepository, EntityDtoConverter entityDtoConverter) {
this.employeeRepository = employeeRepository;
this.entityDtoConverter = entityDtoConverter;
}
public EmployeeResponse getEmployeesByStatus(EmployeeStatus status, int pageSize, int pageIndex, Sort.Direction sortDirection, String sortColumn) {
Page<EmployeeDTO> employeePage = employeeRepository.findByStatus(status, PageRequest.of(pageIndex, pageSize, Sort.by(sortDirection, sortColumn)))
.map(entityDtoConverter::convertEmployeeBaseToDto);
return new EmployeeResponse(employeePage);
}
public EmployeeResponse getEmployeeDetails(EmployeeStatus status, int pageSize, int pageIndex, Sort.Direction sortDirection, String sortColumn) {
Page<EmployeeDTO> employeePage = employeeRepository.getEmployeeDetails(status, PageRequest.of(pageIndex, pageSize, Sort.by(sortDirection, sortColumn)))
.map(entityDtoConverter::convertToEmployeeWithDetailsDto);
return new EmployeeResponse(employeePage);
}
// ...
}
// EntityDtoConverter
@Component
public class EntityDtoConverter {
public EmployeeDTO convertEmployeeBaseToDto(Employee entity) {
return EmployeeDTO.builder()
.id(entity.getId())
.employeeNumber(entity.getEmployeeNumber())
.status(entity.getStatus())
.build();
}
public EmployeeDTO convertToEmployeeWithDetailsDto(Employee entity) {
return convertEmployeeBaseToDto(entity).toBuilder()
.name(entity.getDetails().getName())
.surname(entity.getDetails().getSurname())
.build();
}
// ...
}
编辑:
这是我的rest控制器的方法之一:
@GetMapping
public ResponseEntity<EmployeeResponse> getEmployeesByStatus(EmployeeStatus status, int pageSize, int pageIndex, String sortDirection, String sortColumn) {
try {
EmployeeResponse employeeResponse = employeeService.getEmployeesByStatus(status, pageSize, pageIndex, Sort.Direction.fromString(sortDirection), sortColumn);
return employeeResponse.getTotalElements().equals(0L) ? ResponseEntity.noContent().build() : ResponseEntity.ok(employeeResponse);
} catch (Exception e) {
log.error(ERROR_MESSAGE, e);
return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).build();
}
}
【问题讨论】:
-
您能具体说明您收到错误的是哪个查询吗?如果是第二种方法,那么我没有找到
name? -
是的,这完全是关于第二个 -
getEmployeeDetails。 “我没有找到name”是什么意思? -
您想按详细信息属性的名称排序?然后使用
.发送排序参数,如sort=details.name,asc -
问题是我希望它在用户点击表格列标题时进行排序,我需要给他一个选项来点击他想要的每个标题,所以这不仅仅是名称,而是每个字段的加入
Details -
对于您需要使用的每个详细信息字段,例如
sort=details.field,这就是 Spring Data JPA 的工作方式。
标签: java spring-boot hibernate spring-data-jpa