如何在 HQL for Oracle 中获取日期的年份

Question

List employees = session.createQuery("FROM Employee where date1 between '04-APR-04 02.27.05.187000 AM' and '04-APR-14 02.27.05.187000 AM' and YEAR('04-APR-04 02.27.05.187000 AM')=YEAR('04-APR-04 02.27.05.187000 AM')").list();

我遇到了这个问题：

    Hibernate: select emThrployee0_.id as id2_, employee0_.firstName as firstName2_, employee0_.lastName as lastName2_, employee0_.date1 as date4_2_ from emp1 employee0_ where (employee0_.date1 between '04-APR-04 02.27.05.187000 AM' and '04-APR-14 02.27.05.187000 AM') and extract(year from '04-APR-04 02.27.05.187000 AM')=extract(year from '04-APR-04 02.27.05.187000 AM')
org.hibernate.exception.GenericJDBCException: could not execute query
    at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103)
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
    at org.hibernate.loader.Loader.doList(Loader.java:2214)
    at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2095)
    at org.hibernate.loader.Loader.list(Loader.java:2090)
    at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:388)
    at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:338)
    at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:172)
    at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1121)
    at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79)
    at main.StoreData.listEmployees(StoreData.java:68)
    at main.StoreData.main(StoreData.java:57)
Caused by: java.sql.SQLException: ORA-30076: invalid extract field for extract source

    at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:112)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:331)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:288)
    at oracle.jdbc.driver.T4C8Oall.receive(T4C8Oall.java:743)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:216)
    at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:799)
    at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:1038)
    at oracle.jdbc.driver.T4CPreparedStatement.executeMaybeDescribe(T4CPreparedStatement.java:839)
    at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1133)
    at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3285)
    at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:3329)
    at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:186)
    at org.hibernate.loader.Loader.getResultSet(Loader.java:1778)
    at org.hibernate.loader.Loader.doQuery(Loader.java:662)
    at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224)
    at org.hibernate.loader.Loader.doList(Loader.java:2211)
    ... 9 more

我需要 Oracle 休眠中从日期开始的年份 但是这段代码在 Sql server 中工作但在 Oracle 中不工作。 我尝试了，但我无法解决如果知道请帮助任何人

谢谢

Answer 1

我会尝试阅读文档，因为您的查询应该采用这种结构：

Select * FROM table t WHERE t.column...

您可以尝试以下方法：

"SELECT * FROM Employee e WHERE e.date1 > '2013-01-01' AND e.date1 <'2014-01-01'"

这将从您的员工表中获取所有列，您可以尝试these 格式的日期。使用这些格式，您可以使用函数YEAR(date)。

Answer 2

隐式转换在 Oracle 中不如在 SQL Server 中那么容易。查看将日期时间字符串填充到查询中的 TO_DATE() 函数中。

http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions183.htm