【问题标题】:Adding to collection creates record, but does not link it to parent添加到集合会创建记录,但不会将其链接到父级
【发布时间】:2018-08-21 13:02:49
【问题描述】:

我有两个非常简单的实体:

@Entity
public class CanonUser {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String crm;
    private String name;
    @OneToMany(mappedBy = "user", cascade = CascadeType.ALL, orphanRemoval = true)
    private List<Address> address;

    // getters and setters omitted
}

@Entity
public class Address {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String city;
    private String street;

    @ManyToOne
    private CanonUser user;

    // getters and setters omitted
}

和一个基本存储库:

@RepositoryRestResource(path = "users", collectionResourceRel = "users", itemResourceRel = "user")
public interface CanonUserRepo extends CrudRepository<CanonUser, Long> {
}

我正在尝试通过此请求将项目添加到地址:

curl 'http://localhost:8080/companion-backend/api/users/3' -i -X PATCH \
    -H 'Accept: application/hal+json' \
    -H 'Content-Type: application/json-patch+json; charset=ISO-8859-1' \
    -d '[{"op":"add", "path":"/address/-","value":{"city":"Jim", "street":"Jim Grove"}}]'

这会创建地址记录,但不会将其链接到用户:

2018-03-13 11:05:04.242 DEBUG 18533 --- [nio-8080-exec-1] jdbc.sqltiming                           :  com.zaxxer.hikari.pool.ProxyPreparedStatement.executeQuery(ProxyPreparedStatement.java:52)
1. select canonuser0_.id as id1_1_0_, canonuser0_.crm as crm2_1_0_, canonuser0_.name as name3_1_0_, address1_.user_id as user_id4_0_1_, address1_.id as id1_0_1_, address1_.id as id1_0_2_, 
address1_.city as city2_0_2_, address1_.street as street3_0_2_, address1_.user_id as user_id4_0_2_ from canon_user canonuser0_ left outer join address address1_ on canonuser0_.id=address1_.user_id 
where canonuser0_.id=3 
 {executed in 0 msec}
2018-03-13 11:05:04.353 DEBUG 18533 --- [nio-8080-exec-1] jdbc.sqltiming                           :  com.zaxxer.hikari.pool.ProxyPreparedStatement.executeUpdate(ProxyPreparedStatement.java:61)
1. insert into address (id, city, street, user_id) values (null, 'Jim', 'Jim Grove', NULL) 
 {executed in 2 msec}
2018-03-13 11:05:04.355 DEBUG 18533 --- [nio-8080-exec-1] jdbc.sqltiming                           :  com.zaxxer.hikari.pool.ProxyStatement.getGeneratedKeys(ProxyStatement.java:230)
1. getGeneratedKeys on query: insert into address (id, city, street, user_id) values (null, 'Jim', 'Jim Grove', NULL) 
 {executed in 2 msec}

我做错了什么?

<spring.version>5.0.4.RELEASE</spring.version>
<spring-data-releasetrain.version>Kay-SR4</spring-data-releasetrain.version>

【问题讨论】:

  • 建立一对多关系uni-directional
  • 谢谢,成功了。你能写一个答案并解释原因吗?
  • 我想我无法比 Spring Data 更好地解释 author...))

标签: spring-data-rest


【解决方案1】:

正如我在评论中所说,Spring Data 作者解释了为什么双向一对多在 SDR 中不起作用,您可以找到 here

但是您可以使用折衷的变体来避免第 3 个,即加入表,与 @JoinColumn 注释的组合进行一对多关联:

@Data
@Entity
public class Parent implements Serializable {

  @Id @GeneratedValue private Integer id;

  private String name;

  @OneToMany(cascade = ALL, orphanRemoval = true)
  @JoinColumn(name = "parent_id", foreignKey = @ForeignKey(name = "fk_children_parent"))
  private List<Child> children;
}

@Data
@Entity
public class Child implements Serializable {
  @Id @GeneratedValue private Integer id;
  private String name;
}

public interface ParentRepo extends JpaRepository<Parent, Integer> {
}

在这种情况下,您只会得到两个表:

CREATE TABLE PARENT
(
    ID integer PRIMARY KEY NOT NULL,
    NAME varchar(255)
)

CREATE TABLE CHILD
(
    ID integer PRIMARY KEY NOT NULL,
    NAME varchar(255),
    PARENT_ID integer,
    CONSTRAINT FK_CHILDREN_PARENT FOREIGN KEY (PARENT_ID) REFERENCES PARENT (ID)
);

我写了“妥协变体”,因为这种组合会产生过多的查询,compared 到双向查询。例如,创建一个有两个孩子的父母会产生五个查询:

POST http://localhost:8080/parents
{
    "name": "parent1",
    "children": [
        {
            "name": "child1"
        },
        {
            "name": "child2"
        }
    ]
}
insert into parent (name, id) values ('parent1', 1)
insert into child (name, id) values ('child1', 2) 
insert into child (name, id) values ('child2', 3) 
update child set parent_id=1 where id=2 
update child set parent_id=1 where id=3

用一个孩子更新这个父母会产生以下查询序列:

PATCH http://localhost:8080/parents/1
{
    "name": "parent1",
    "children": [
        {
            "name": "child3"
        }
    ]
}
select c.parent_id, c.id, c.name from child c where c.parent_id=1
update child set name='child3' where id=2 
update child set parent_id=null where parent_id=1 and id=3 
delete from child where id=3 

【讨论】:

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