带有注释的 Spring MVC 3 验证 - 不显示表单：错误

Question

我已经坚持了大约一个小时，这不是我第一次这样做，但我无法弄清楚。

它应该向我显示表单错误，而不是抛出这个异常。

LE：同时我设法解决了异常，但我仍然看不到错误。它们没有被渲染

org.springframework.web.util.NestedServletException：请求处理失败；嵌套异常是 org.springframework.validation.BindException: org.springframework.validation.BeanPropertyBindingResult: 1 错误 字段“名称”上的对象“类别”中的字段错误：拒绝值 [jk]；代码 [Range.category.name,Range.name,Range.java.lang.String,Range];参数 [org.springframework.context.support.DefaultMessageSourceResolvable: 代码 [category.name,name];论据 [];默认消息 [名称],25,3]；默认消息 [gfhghj] org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:894) org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:789) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:311) org.springframework.security.web.access.intercept.FilterSecurityInterceptor.invoke(FilterSecurityInterceptor.java:116) org.springframework.security.web.access.intercept.FilterSecurityInterceptor.doFilter(FilterSecurityInterceptor.java:83) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.access.ExceptionTranslationFilter.doFilter(ExceptionTranslationFilter.java:113) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.session.SessionManagementFilter.doFilter(SessionManagementFilter.java:101) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.authentication.AnonymousAuthenticationFilter.doFilter(AnonymousAuthenticationFilter.java:113) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.servletapi.SecurityContextHolderAwareRequestFilter.doFilter(SecurityContextHolderAwareRequestFilter.java:54) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.savedrequest.RequestCacheAwareFilter.doFilter(RequestCacheAwareFilter.java:45) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.authentication.www.BasicAuthenticationFilter.doFilter(BasicAuthenticationFilter.java:150) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:182) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:105) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:87) org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:323) org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:173) org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:346) org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:259) org.springframework.web.filter.HiddenHttpMethodFilter.doFilterInternal(HiddenHttpMethodFilter.java:77) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:76) org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:88) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:76)

@Controller
@RequestMapping("/category")
public class CategoryController {

@Autowired
StockGateway stockGateway;

@RequestMapping(value = "add", method = RequestMethod.POST)
public String addCategory(@Valid @ModelAttribute("category") CategoryAdd category, ModelMap model,
        BindingResult binding) {

    if (binding.hasErrors()) {
        return "category.add";
    }
    CategoryDTO dto = Converter.toCategory(category);
    try {
        stockGateway.createCategory(dto);
    } catch (StockGatewayException e) {
        e.printStackTrace();
    }
    return "redirect:/category/add";

}

@RequestMapping(value = "add", method = RequestMethod.GET)
public String initView(ModelMap model) {
    model.put("category", new CategoryAdd());
    return "category.add";
}

}

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<div xmlns:jsp="http://java.sun.com/JSP/Page" 
xmlns:spring="http://www.springframework.org/tags"
 xmlns:c="http://java.sun.com/jsp/jstl/core" 
 xmlns:security = "http://www.springframework.org/security/tags"
 xmlns:util="urn:jsptagdir:/WEB-INF/tags/util"
 xmlns:form="http://www.springframework.org/tags/form"
 version="2.0">

<security:authorize access="hasRole('ROLE_STOCK')" var="isStock">
    <form:form modelAttribute="category"  method="POST" action="add"  >
            <table>
            <tr>
                <td>Name  :</td> <td> <form:input path="name" /></td>
            </tr>
            <tr>
                <td></td> <td> <form:errors path="name" cssClass="error" /></td>
            </tr>
            </table>
            <form:button>Add</form:button>
    </form:form>
</security:authorize>

public class CategoryAdd {

@Range(min= 3 , max = 25, message="gfhghj")
private String name;



public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

Answer 1

所以完整的解决方案是：

public String addCategory(@Valid CategoryAdd category,BindingResult result,
        Map map
        ) {

    if (result.hasErrors()) {
        map.put("categoryAdd", (CategoryAdd)result.getTarget());
        return "category.add";
    }
    CategoryDTO dto = Converter.toCategory(category);
    try {
        stockGateway.createCategory(dto);
    } catch (StockGatewayException e) {
        e.printStackTrace();
    }
    return "redirect:/category/add";

请注意，我将参数 ModelMap 更改为 Map，如果结果有错误，我会从结果中放回模型。

现在 WTF： BindingResult 有一个字段 objectName，它的值是类的名称。 您必须将 modelAttribute/commandName 设置为此。与 BindingResult 中的 objectName 相同，否则不会呈现错误。 所以要匹配它：

    <form:form modelAttribute="categoryAdd" commandName="categoryAdd"  method="POST" action="add"  >

有谁知道我们如何更改 BindingResult 中的 objectName？默认情况下，它将采用类的名称。

Answer 2

似乎依赖于必须在映射控制器方法中列出参数的顺序。
例如：

public String addCategory(@Valid CategoryAdd category,BindingResult result, 
Map map)

会起作用，而：

public String addCategory(@Valid CategoryAdd category, Map map, 
BindingResult result)

不会。我不完全理解为什么会这样，尤其是编译时没有任何问题。