蓝牙插座冻结电话

Question

我正在为 Android 开发一个应用程序。此应用程序应与蓝牙 (BT) 设备通信（发送一些字节）。我在我的设备（Samsung Galaxy mini）上调试/运行此应用程序时遇到问题。当我创建一个 BT 插座并停止调试时，手机死机，我必须通过取出电池重新启动它。如果运行此应用程序（从 Eclipse）一切正常，但当我尝试再次运行它时，手机冻结并且未安装应用程序。如果我在第二次运行之前尝试手动卸载此应用程序，手机会再次冻结。这是一个有问题的代码：

private final BluetoothDevice mmDevice;
private UUID uuid;

public ConnectionThread(BluetoothDevice device) {
    Log.d(TAG, "create ConnectionThread");

    uuid = UUID.fromString("00001101-0000-1000-8000-00805F9B34FB"); 
    BluetoothSocket tmp = null;
    mmDevice = device;

    try {
        tmp = mmDevice.createRfcommSocketToServiceRecord(uuid);
    } catch (IOException e) { }
    mmSocket = tmp;
    socketConnected = true;
}

这是线程的构造函数。当我评论该行时

    tmp = mmDevice.createRfcommSocketToServiceRecord(uuid);

手机不会死机，所以问题在于创建套接字（未连接）。每次调试或运行后重启手机很烦人，我还要做很多工作。

如果我从手机运行这个应用程序（从 Eclipse 断开），它可以正常工作。任何想法可能是一个问题或如何解决它？谢谢。

Answer 1

我也在使用 SGSIII mini 进行开发。以下代码对我很有效：

    private class ConnectThread extends Thread {
    private final BluetoothSocket mmSocket;
    private final BluetoothDevice mmDevice;

    public ConnectThread(BluetoothDevice device) {
        mmDevice = device;

        BluetoothSocket tmp = null;

        // Get a BluetoothSocket for a connection with the
        // given BluetoothDevice
        try {
            //tmp = device.createRfcommSocketToServiceRecord(MY_UUID);
            tmp = device.createInsecureRfcommSocketToServiceRecord(MY_UUID);
        } catch (IOException e) {
            Log.e(LOG_TAG, "create() failed", e);
        }
        mmSocket = tmp;

        Main.myBluetoothSocket = mmSocket;
        Main.myBluetoothDevice = mmDevice;
    }

    @Override
    public void run() {
        Log.i(LOG_TAG, "BEGIN mConnectThread");
        setName("ConnectThread");

        // Always cancel discovery because it will slow down a connection
        mAdapter.cancelDiscovery();

        // Send a failure message back to the Activity
        Message msg = mHandler.obtainMessage(MESSAGE_TOAST);
        Log.e(LOG_TAG, "Attempting connection to " + mmSocket.getRemoteDevice().getName());
        String ss = "Attempting connection to " + mmSocket.getRemoteDevice().getName();
        Bundle bundle = new Bundle();
        bundle.putString(TOAST, ss);
        msg.setData(bundle);
        mHandler.sendMessage(msg);

        // Make a connection to the BluetoothSocket
        try {
            // This is a blocking call and will only return on a
            // successful connection or an exception
            mmSocket.connect();
        } catch (IOException e) {
            Log.e(LOG_TAG, "*+*+*+*   Connection Failed");
            connectionFailed();
            // Close the socket
            try {
                mmSocket.close();
            } catch (IOException e2) {
                Log.e(LOG_TAG, "unable to close() socket during connection failure", e2);
            }
            // Start the service over to restart listening mode
            BluetoothCommandService.this.start();
            return;
        }

        // Reset the ConnectThread because we're done
        synchronized (BluetoothCommandService.this) {
            mConnectThread = null;
        }

        // Start the connected thread
        connected(mmSocket, mmDevice);
    }

    public void cancel() {
        try {
            mmSocket.close();
        } catch (IOException e) {
            Log.e(LOG_TAG, "close() of connect socket failed", e);
        }
    }
}

Answer 2

我也面临同样的问题，你可以使用反射方法它会工作

Method m = device.getClass().getMethod("createRfcommSocket", new Class[] {int.class});
BluetoothSocket socket = socket = (BluetoothSocket) m.invoke(device, 1);