【发布时间】:2017-10-29 21:17:12
【问题描述】:
我正在使用 Swing 用 Java 制作一个老式的 Snake 游戏。我已经读过,为了实时捕获输入,我需要在新线程中运行我的游戏循环,这样 wait() 方法就不会干扰输入捕获。我已经让 InputCapture 类实现了 KeyListener 并且我已经实现了 keyPressed() 这样的方法:
public class InputCapture implements KeyListener {
private Direction capturedDirection;
//Methods
@Override
public void keyPressed(KeyEvent e) {
boolean inputConsoleDebug = true;
if (e.getKeyCode() == KeyEvent.VK_LEFT) {
capturedDirection = Direction.left;
if (inputConsoleDebug) System.out.println("LEFT");
} else if (e.getKeyCode() == KeyEvent.VK_RIGHT) {
capturedDirection = Direction.right;
if (inputConsoleDebug) System.out.println("RIGHT");
} else if (e.getKeyCode() == KeyEvent.VK_UP) {
capturedDirection = Direction.up;
if (inputConsoleDebug) System.out.println("UP");
} else if (e.getKeyCode() == KeyEvent.VK_DOWN) {
capturedDirection = Direction.down;
if (inputConsoleDebug) System.out.println("DOWN");
}
}
@Override
public void keyReleased(KeyEvent e) {
}
@Override
public void keyTyped(KeyEvent e) {
}
public Direction getCapturedDirection() {
return capturedDirection;
}
}
然后我创建了 Game 类扩展 Thread 并将游戏循环代码放入 run() 方法中:
public class Game extends Thread {
private Board board;
private Snake snake;
private JFrame frame;
private long waitTime;
private int difficultyStep;
private Direction inputDirection;
private InputCapture inputManager;
//Constructors
Game(Dimension boardSize) {
//Set difficulty
int applesToWin = boardSize.width * boardSize.height - 1;
final int easiestWaitTime = 1000;
final int hardestWaitTime = 100;
difficultyStep = (easiestWaitTime - hardestWaitTime) / applesToWin;
waitTime = easiestWaitTime;
//Set starting point
final int startingPointX = boardSize.width / 2;
final int startingPointy = boardSize.height / 2;
//Set board and snake
board = new Board(boardSize);
snake = new Snake(board, startingPointX, startingPointy);
//Set window Frame
frame = new JFrame(SnakeApplication.getApplicationName());
frame.setContentPane(board);
frame.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
frame.pack();
frame.setResizable(false);
frame.addWindowListener(new WindowAdapter() {
@Override
public void windowClosing(WindowEvent e) {
super.windowClosing(e);
interrupt();
}
});
//Set input manager
inputManager = new InputCapture();
frame.addKeyListener(inputManager);
inputDirection = null;
}
//Methods
public void run() {
board.spawnApple();
while (!isWon()) {
try {
sleep(waitTime);
} catch (InterruptedException e) {
return;
}
try {
inputDirection = inputManager.getCapturedDirection();
snake.move(inputDirection);
} catch (LosingMove e) {
showGameOverDialog();
return;
}
board.repaint();
}
showWinDialog();
}
JFrame getFrame() {
return frame;
}
private boolean isWon() {
for (int row = 0; row < board.getFields().length; row++) {
for (int col = 0; col < board.getFields()[0].length; col++) {
if (!(board.getFields()[row][col].getContent() instanceof Snake.SnakeNode)) return false;
}
}
return true;
}
private void showGameOverDialog() {
JFrame gameOverFrame = new JFrame();
JOptionPane.showMessageDialog(gameOverFrame, "Game Over!");
}
private void showWinDialog() {
JFrame gameOverFrame = new JFrame();
JOptionPane.showMessageDialog(gameOverFrame, "You Win!");
}
}
在我的MainMenu 类中,我创建了startNewGame() 方法,该方法在单击新游戏按钮时被调用。该方法创建Game对象并通过调用start()方法启动一个新线程。
public class MainMenu {
//Form components references
private JButton exitButton;
private JFrame frame;
private JPanel mainPanel;
private JButton newGameButton;
private JLabel titleLabel;
//Constructors
MainMenu() {
//Set window Frame
frame = new JFrame(SnakeApplication.getApplicationName());
frame.setContentPane(mainPanel);
frame.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
frame.setResizable(false);
frame.pack();
newGameButton.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
startNewGame();
}
});
exitButton.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
exitGame();
}
});
}
JFrame getFrame() {
return frame;
}
private Dimension showBoardSizeDialog() {
Frame boardSizeFrame = new Frame();
int width = Integer.parseInt(JOptionPane.showInputDialog(boardSizeFrame, "Set board's width:"));
int height = Integer.parseInt(JOptionPane.showInputDialog(boardSizeFrame, "Set board's height:"));
return new Dimension(width, height);
}
private void startNewGame() {
Dimension boardSize = showBoardSizeDialog();
frame.setVisible(false);
Game game = new Game(boardSize);
game.getFrame().setVisible(true);
//Starting game loop in a new thread
game.start();
try {
game.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
frame.setVisible(true);
}
}
但在测试应用时,它会卡在游戏循环中,根本无法捕获输入。为什么?我试图调试它,但是每次启动新线程时,它都会卡在游戏循环中。 Board 本身仅在主线程结束执行时才被绘制。为什么?如果执行被卡在那里,不应该在游戏循环期间重新绘制多次吗?
此外,当单击框架的关闭按钮(红色 X 按钮)时,我已经使线程中断,因此执行可以返回到 MainMenu 并重新出现,但单击红色关闭按钮无效。
【问题讨论】:
标签: java multithreading swing input keylistener