【发布时间】:2013-12-27 21:52:31
【问题描述】:
我在“克隆”一个 InputStream 时遇到了问题。
这不起作用:
InputStream is = ClassLoader.getSystemResourceAsStream("myResource");
但这有效:
InputStream is = new BufferedInputStream(new FileInputStream("/afas.cfg"));
我的代码是:
// Create a piped input stream for one of the readers.
PipedInputStream in = new PipedInputStream();
// Create a tee-splitter for the other reader.(from apache commons io)
TeeInputStream tee = new TeeInputStream(is, new PipedOutputStream(in));
// Create the two buffered readers.
BufferedReader br1 = new BufferedReader(new InputStreamReader(tee));
BufferedReader br2 = new BufferedReader(new InputStreamReader(in));
// Do some interleaved reads from them.
System.out.println("One line from br1:");
System.out.println(br1.readLine());
System.out.println();
System.out.println("Two lines from br2:");
System.out.println(br2.readLine());
System.out.println(br2.readLine());
System.out.println();
System.out.println("One line from br1:");
System.out.println(br1.readLine());
System.out.println();
第一次调用br1.readLine() 时出现问题。它只是卡在PipedInputStream.awaitSpace() 并且处于无限循环中。
PipedStreams 是否仅适用于线程?这意味着当写入 PipedOutputStreams 时,PipedInputStream 将“唤醒”
无论如何,我必须做什么才能完成这项工作?
【问题讨论】:
-
是的,PipedStreams 需要在不同的线程中。
-
但是如果我直接通过
new FileInputStream(...) ?创建InputStream,为什么InputStream会起作用 -
您的代码看起来有点可疑。您确定按照您的意图构建所有流吗?
-
只是一个例子,类似这个java-success.blogspot.de/2013/05/…
标签: java io java-io apache-commons-io