【发布时间】:2012-03-09 11:58:58
【问题描述】:
嘿,我有这段代码,当您单击第一个按钮时,它应该从 sql server 保存文件,然后在按下第二个按钮时显示它。第一个按钮似乎可以工作,但第二个按钮导致它崩溃这是我的代码
public class MainActivity extends Activity {
/** Called when the activity is first created. */
String result = "";
InputStream is = null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button saveFile = (Button) findViewById(R.id.downloadBtn);
saveFile.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
returnJson();
}
});
Button showFile = (Button) findViewById(R.id.showBtn);
showFile.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
TextView showText = (TextView) findViewById(R.id.showView);
String FILENAME = "Story_One";
String showStoryNames = "";
FileInputStream fis = null;
try {
fis = openFileInput(FILENAME);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
try {
fis.read(showStoryNames.getBytes());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
fis.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
});
//end of onCreate
}
public void returnJson(){
try{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://10.0.2.2/textures_story_list.php");
HttpResponse response = httpClient.execute(httpPost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e) {
//one.setText("error3");
}
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
}catch(Exception e) {
//one.setText("error2");
}
try{
JSONArray jArray = new JSONArray(result);
String storyNames = "";
for(int i = 0;i<jArray.length();i++){
storyNames += jArray.getJSONObject(i).getString("story_name") + "\n";
String FILENAME = "Story_One";
String string = storyNames;
FileOutputStream fos = openFileOutput(FILENAME, Context.MODE_PRIVATE);
fos.write(string.getBytes());
fos.close();
}
}
catch(JSONException e) {
//one.setText("error1");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return;
//end of returnJson()
}
//end of method body
}
我需要有人告诉我为保存到内部而编写的代码是否正确,以及按钮 2 崩溃的原因。
好的,这就是我正在运行的代码
public void returnJson(){
TextView one = (TextView) findViewById(R.id.textView1);
try{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://10.0.2.2/story_one.php");
HttpResponse response = httpClient.execute(httpPost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e) {
one.setText("error3");
}
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
}catch(Exception e) {
one.setText("error2");
}
try{
JSONArray jArray = new JSONArray(result);
String storyNames = "";
for(int i = 0;i<jArray.length();i++){
storyNames += jArray.getJSONObject(i).getString("story_name") + "\n";
}
one.setText(storyNames);
}
catch(JSONException e) {
one.setText("error1");
}
return;
//end of returnJson()
}
所以谁能告诉我我不需要什么代码,我需要什么,把它放在哪里以便能够保存story_one.php的结果,以及是否可以将它保留为json,因为我稍后会转换它正在使用 story_one 文件
【问题讨论】:
-
在崩溃时发布您的错误日志
-
什么是错误/堆栈跟踪??
-
如何发布错误日志?
-
如果您只想存储单个字符串,可以使用 SharedPreferences
标签: android json memory save internal