将 2 个 cstring 数组添加到 1 个 cstring 数组中

Question

我最近学习了 cstring 数组，想尝试一个基本的操作，将两个字符串加在一起，在一个普通的字符串中，作为 header 可以添加 string1+string2=string3。但是我尝试为 cstrings 执行此操作，当我遵循这种可能不正确的格式时出现错误。 这是代码，该代码仅用于将我的名字和姓氏打印为字符串中的 1 个名称。

#include<iostream>
#include<cstring>


using namespace std;

 int main() {
 char fname[100], lname[100], full_name[100];
 int i, j;
 i = 0;j = 0; // i is index of fname and j is index for lname
 cout << "Enter your first name: ";
 cin.getline(fname, 100);
 cout << "Enter your last name: ";
 cin.getline(lname, 100);
 for (i;fname[i] != '\0';i++) {
    full_name[i] = fname[i];
  }
  std::string(fname +" "+ lname);
  cout << "i =" << i;
  full_name[i] = ' ';
  i = i + 1;
  for (i, j;lname[j] != '\0';i++, j++) {
    full_name[i] = lname[j];
    }
    cout << "Your full name is: " << full_name << endl;
    system("pause");
    return 0;
}

Answer 1

首先从代码中删除这一行

std::string(fname +" "+ lname);

第二次你忘记在结束字符串后添加'\0' 看看这段代码：

int main() {
    char fname[100], lname[100], full_name[100];
    int i, j;
    i = 0; j = 0; // i is index of fname and j is index for lname
    cout << "Enter your first name: ";
    cin.getline(fname, 100);
    cout << "Enter your last name: ";
    cin.getline(lname, 100);
    for (i; fname[i] != '\0'; i++) {
        full_name[i] = fname[i];
    }

    cout << "i =" << i;
    full_name[i] = ' ';
    i = i + 1;
    for (i, j; lname[j] != '\0'; i++, j++) {
        full_name[i] = lname[j];
    }
    full_name[i] = '\0';
    cout << "Your full name is: " << full_name << endl;
    system("pause");
    return 0;
}