Codecademy Python 2 石头、纸、剪刀答案

【问题标题】：Codecademy Python 2 Rock, Paper, ScissorsCodecademy Python 2 石头、纸、剪刀
【发布时间】：2020-10-01 17:38:53
【问题描述】：

我刚刚开始编码，每天都像婴儿一样成长

复习我的笔记并尝试理解/记住代码会变得很困难。

请解释一下如何处理这段代码。

from random import randint
"""This program will enable the user and computer to start a rock paper scissors game"""

options = ["ROCK", "PAPER", "SCISSORS"]

message = {"tie": "Yawn it's a tie!", "won": "Yay you won!", "lost": "Aww you lost!"}


def decide_winner(user_choice, computer_choice):
    print("You chose %s") % (user_choice)

    print("PC chose %s") % (computer_choice)

    if user_choice == computer_choice:
        print(message["tie"])  # tie

    # user - paper , pc = rock
    elif user_choice == options[1] and computer_choice == options[0]:
        print(message["won"])

    # user - scissor , pc = paper
    elif user_choice == options[2] and computer_choice == options[1]:
        print(message["won"])

    # user - rock , pc - scissors
    elif user_choice == options[0] and computer_choice == options[1]:
        print(message["won"])

    else:
        print("YOU LOSE!")


def play_RPS():
    user_choice = input("Enter Rock, Paper, Scissors: ")

    computer_choice = options[randint(0,2)]
    decide_winner(user_choice, computer_choice)

play_RPS()

【问题讨论】：

请说出你目前所了解的。

标签： python string list int

【解决方案1】：

一些注意事项 - elif user_choice == options[0] and computer_choice == options[1]: 应该是 elif user_choice == options[0] and computer_choice == options[2]: 您的 cmets 是正确的，但是您为 SCISSORS 索引了“1”而不是“2”。

Python 区分大小写，因此“ROCK”不等于“Rock”。您可能需要添加该行

user_choice = user_choice.upper() 在函数 def play_RPS(): 中传递给它之前

decide_winner(user_choice, computer_choice)

【讨论】：

【解决方案2】：

Python 2 对变量等内容使用输入，对字符串等内容使用 raw_input。

代替：

user_choice = input("Enter Rock, Paper, Scissors: ")

使用

user_choice = raw_input("Enter Rock, Paper, Scissors: ")

输入区分大小写您的选择是

options = ["ROCK", "PAPER", "SCISSORS"]

但如果一个人输入“Rock”，则表明他们输了而是改变

user_choice = raw_input("Enter Rock, Paper, Scissors: ")

到

user_choice = raw_input("Enter Rock, Paper, Scissors: ").upper()

【讨论】：

【解决方案3】：

从随机导入randint

"""这个程序将使用户和计算机开始一个石头剪刀布游戏"""

options = ["ROCK", "PAPER", "SCISSORS"]

message = {"tie": "打哈欠是平手！", "won": "是的，你赢了！", "lost": "哇，你输了！"}

best_of_three = 3

def decision_winner(user_choice, computer_choice)：

    print('You chose %s' % user_choice)

    print("PC chose %s" % computer_choice)

    if user_choice == computer_choice:

        print(message["tie"])  # tie

# user - paper , pc = rock
    elif user_choice == options[1] and computer_choice == options[0]:
        print(message["won"])
# user - scissor , pc = paper
    elif user_choice == options[2] and computer_choice == options[1]:
        print(message["won"])
        # user - rock , pc - scissors
    elif user_choice == options[0] and computer_choice == options[1]:
        print(message["won"])
    else:
        print("YOU LOSE!")

def play_RPS():

user_choice = input("Enter Rock, Paper, Scissors: ").upper()

computer_choice = options[randint(0, 2)]

decide_winner(user_choice, computer_choice)

play_RPS()

【讨论】：