如何始终获得积极的输出？答案

【问题标题】：How to always get a positive output?如何始终获得积极的输出？
【发布时间】：2014-01-04 05:16:01
【问题描述】：

这是我的代码：

import random
minimum=int(input("Enter minimum value: "))
maximum=int(input("Enter maximum value: "))
if minimum>maximum:
    temp=minimum
    minimum=maximum
    maximum=temp
howMany = int(input("How many numbers do you want to generate?"))
sum=0
n=1
while n<=howMany:
    num=random.randrange(minimum,maximum)
    sum+=num
    n+=1
    print("Your random generated number is",num)
print("Python's random average between", minimum, "and", maximum, "is", sum/howMany)
avg=minimum+maximum/2
avgTwo=sum/howMany
difference=avgTwo-avg
print("The actual average of minimum and maximum is", avg)
print("The difference from the calculated average and from the actual average is", difference)

当我计算差异时，我需要总是得到一个正数。我尝试翻转被减去的变量，但我随机收到一个负数。

【问题讨论】：

返回结果的绝对值怎么样？ abs(x) 对你有帮助吗？
abs
提示：您可以直接使用minimum, maximum = maximum, minimum交换最小值和最大值
您的代码还有第二个更微妙的错误：要查看它，请输入彼此分开的最小值和最大值；例如，“4”和“5”，并生成一大堆数字。你几乎肯定想要randrange(minimum,maximum+1)
@DanielMartin 这就是为什么我更喜欢random.randint()。我在记住函数边界方面仍然很糟糕，randint 做了我认为应该做的事！ :)

标签： python python-3.x integer

【解决方案1】：

如果是负数，只需将该值乘以 -1，那么最终结果就是正数：

difference= avgTwo-avg if avgTwo-avg > 0 else (avgTwo-avg) * -1

【讨论】：

【解决方案2】：

您可以取差值的绝对值来获得两个值之间的“距离”：

>>> abs(2 - 5)
3
>>> abs(5 - 2)
3

【讨论】：

【解决方案3】：

以下是一些改进代码的技巧：

from random import randrange   #import only what need
mini = int(input("Enter minimum value: "))
maxi = int(input("Enter maximum value: "))
if mini > maxi:
    mini, maxi = maxi, mini   #you can swap two values like this

howMany = int(raw_input("How many numbers do you want to generate?"))
total = 0  # don't use sum as variable name, it is built in function
for _ in range(howMany):  #you can use a for loop and not have increment a counter
    num = randrange(mini, maxi+1) #add 1 to maxi to get the range you want
    print("Your random generated number is ", num)
    total += num

print("Python's random average between", mini, "and", maxi, "is", total/howMany)
avg = (mini + maxi)/2  # use ()'s for proper operation order
avgTwo = total/howMany
difference = abs(avgTwo - avg)  #use absolute value to get magnitude
print("The actual average of minimum and maximum is", avg)
print("The difference from the calculated average and from the actual average is", difference)

【讨论】：