如何洗牌字符串数组

Question

如何在数组下方随机播放

String[] firstName =["a","b","c","d","e"];
String[] lastName =["p","q","r","s","t"];
String[] salary =["10","20","30","40",50"];
String[] phoneNo= ["1","2","3","4","5"];

洗牌后我需要像这样的结果

String[] firstName =["d","b","e","c","a"];
String[] lastName =["s","q","t","r","p"];
String[] salary =["40","20","50","30",10"];
String[] phoneNo= ["4","2","5","3","1"];

表示例如，如果 "a" 的索引从 firstName 更改为 4，则 "p"、"10"、"1" 的相应索引将从 0 更改为 4..

Answer 1

如果你的任务不是实现 snuffle 算法，你可以使用标准的java.util.Collections#shuffle 方法：

String[] firstName = new String[] {"a","b","c","d","e"};
List<String> strList = Arrays.asList(firstName);
Collections.shuffle(strList);
firstName = strList.toArray(new String[strList.size()]);

Answer 2

只需创建一个包含值的数组（或列表）

Integer[] arr = new Integer[firstName.length];
for (int i = 0; i < arr.length; i++) {
    arr[i] = i;
}

Collections.shuffle(Arrays.asList(arr));

然后只需创建一个新的字符串数组将值移动到

string[] newFirstName = new string[arr.length]();
for(int i=0; i < arr.length; i++)
{
    newFirstName[i] = firstName[arr[i]];
    //etc ....
}