如何使用 PHP 数组接收不重复的随机数

Question

由于我的网站没有上线，我无法提供 HTML。虽然我从理论编码中知道，专业人士希望能够遵循我的逻辑。

• 如我所见，请用我的代码指出如何使它工作 以下链接类似但不完全相同的场景。我很困惑如何将它应用到我的以下代码中：

Generating random numbers without repeats

我的目标 我想使用 PHP 创建以下内容：

1. 将 00 到 99 放入一个数组中。
2. 从数组中检索一个随机数。
3. 存储/使用从数组中检索到的随机数以放置在 mysql_query 中，如 number = $question 所示（此处我真的需要 ORDER BY RAND() 吗？）
4. 从数字数组列表中删除选定的随机数
5. 获取并显示随机数
6. 使用完所有号码后，会显示一条错误消息，提示刷新页面以重置号码。

下次我想要另一个随机数时，它不能复制之前从数组中选择的相同随机数。所以如果我使用上面的代码说 109 次，那么数组中只剩下 1 个数字。

代码（已编辑）：

   <?php

  //--------------------------------------------------------------------------
  // Example php script for fetching data from mysql database
  //--------------------------------------------------------------------------
  $host = "localhost";
  $user = "root";
  $pass = "";

  $databaseName = "monkeyscanfly";
  $tableName = "num_image";

  //--------------------------------------------------------------------------
  // 1) Connect to mysql database
  //--------------------------------------------------------------------------
  include 'DB.php';
  $con = mysql_connect($host,$user,$pass);
  $dbs = mysql_select_db($databaseName, $con);

    if(!isset($_SESSION)) {
        session_start();

        $_SESSSION['used'] = [];
    }

    $array = [0,1,2,3,4,5,6,7,8,9,"00","01","02","03","04","05","06","07","08","09",10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99]; 

    while(!empty($array)) {
        $array = array_diff($array, $_SESSSION['used']);

        //pick a random point from the array
        $random = array_rand($array);

        // Save the used element in session
        $_SESSION['used'][] = $array;


        //store the random question number
        $question = $array[$random];

        // Select information from database and use array to assign to the selected row.

        $query = mysql_query("SELECT number, association, image_file, skeleton, sound, colour, comments FROM num_image WHERE number = $question ORDER BY RAND() LIMIT 1");

        // Remove random number that was chosen from the array, so the next time the random number is ran, it won't be found in the array.

        unset($array[$random]);

        //fetch result to print on page

        $arrayss = mysql_fetch_row($query);

        //Echo result as json
        echo json_encode($arrayss);
    }

    if(count($array) == count($_SESSION['used'])) {
        $_SESSION['used'] = [];
    }
?>

我希望这是有道理的，我很难找到如何去做，我已经搜索了几个小时并且无法理解它。 :)

我忘了说每次我需要一个新的随机数时，这个 PHP 脚本都会被 ajax 代码重新加载。所以它必须记住这一点来存储/记住数字。如果这有意义？

Answer 1

如果我理解正确，我认为这段代码就是你要找的。在这种情况下，由于您使用的是 AJAX，我们将在会话中保存使用过的问题，例如数组。

<?php
    if(!isset($_SESSION)) {
        session_start();

        $_SESSION['used'] = ((!isset($_SESSION['used'])) ? ([]) : ($_SESSION['used']));
    }

    //--------------------------------------------------------------------------
    // 1) Connect to mysql database
    //--------------------------------------------------------------------------
    include 'DB.php';

    $con = mysql_connect($host, $user, $pass);
    $dbs = mysql_select_db($databaseName, $con);

    $array = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99];
    $array_unique = [];

    while(!empty($array_unique = array_diff($array, $_SESSION['used']))) {
        //pick a random point from the array
        $random = array_rand($array_unique, 1);

        // Save the used element in session
        $_SESSION['used'][] = $array_unique[$random];

        //store the random question number
        $question = $array_unique[$random];

        // Select information from database and use array to assign to the selected row.
        $query = mysql_query("SELECT `number`,`association`,`image_file`,`skeleton`,`sound`,`colour`,`comments` FROM ".$tableName." WHERE `number` = ".$question." LIMIT 0,1");

        //fetch result to print on page

        $row = mysql_fetch_row($query);

        //Echo result as json
        echo json_encode($row);
    }
    if(count($array_unique) == 0) {
        $_SESSION['used'] = [];
    }
?>

只需使用while 和array_rand