PHP str_replace 用数组中的随机替换替换需要？

Question

我已经研究过，需要找到最好的方法来随机地用一系列可能性来代替需求。

即：

$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$keyword = "[city]";
$values = array("Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami");

$result = str_replace("[$keyword]", $values, $text);

结果是每次出现的城市都有“数组”。我需要用 $values 中的随机值替换所有出现的城市。我想以最干净的方式做到这一点。到目前为止，我的解决方案很糟糕（递归）。什么是最好的解决方案？谢谢！

Answer 1

您可以使用preg_replace_callback 为每个匹配项执行一个函数并返回替换字符串：

$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$keyword = "[city]";
$values = array("Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami");

$result = preg_replace_callback('/' . preg_quote($keyword) . '/', 
  function() use ($values){ return $values[array_rand($values)]; }, $text);

示例$result:

欢迎来到亚特兰大。我希望达拉斯每次都是随机版本。迈阿密不应该每次都是同一个亚特兰大。

Answer 2

您可以将preg_replace_callback 与array_rand 一起使用

<?php
$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$values = array("Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami");

$result = preg_replace_callback("/\[city\]/", function($matches) use ($values) { return $values[array_rand($values)]; }, $text);

echo $result;

例如here。

Answer 3

这是另一个想法

$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$pattern = "/\[city\]/";
$values = array("Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami");

while(preg_match($pattern, $text)) {
        $text = preg_replace($pattern, $values[array_rand($values)], $text, 1);
}

echo $text;

还有一些输出：

Welcome to Orlando. I want Tampa to be a random version each time. Miami should not be the same Orlando each time.

Answer 4

您正在使用 $values 替换文本，它是一个数组，因此结果只是单词“Array”。替换应该是一个字符串。

您可以使用array_rand() 从您的数组中选择随机条目。

$result = str_replace($keyword, $values[array_rand($values)], $text);

结果是这样的：

Welcome to Atlanta. I want Atlanta to be a random version each time. Atlanta should not be the same Atlanta each time.
Welcome to Orlando. I want Orlando to be a random version each time. Orlando should not be the same Orlando each time.

如果您希望城市是随机的每一行，请查看@PaulP.R.O 的答案。

Answer 5

如果：

1. 随机选择的四个城市占位符不应在您的 3 句字符串中重复，并且
2. 你不介意改变输入数组和
3. 您将始终有足够的值来容纳所有占位符，然后：

您可以将数组作为引用变量传递到自定义函数范围。这意味着当您通过array_pop() 访问和删除值时，不可能两次遇到同一个城市。在执行替换之前，您只需 shuffle() 输入数组一次。

代码：(Demo)

$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$keyword = "[city]";
$values = ["Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami"];
shuffle($values);

echo preg_replace_callback(
         '/' . preg_quote($keyword) . '/',
         function() use(&$values) { return array_pop($values); },
         $text
     );

潜在输出：

Welcome to Detroit. I want Tampa to be a random version each time. Dallas should not be the same Orlando each time.

或

Welcome to Orlando. I want Miami to be a random version each time. Atlanta should not be the same Detroit each time.

或

Welcome to Atlanta. I want Tampa to be a random version each time. Orlando should not be the same Dallas each time.

等等

Answer 6

试试这个http://codepad.org/qp7XYHe4

<?
$text = "Welcome to [city]. I want [city] to be a random version each time. [city] should not be the same [city] each time.";

$keyword = "[city]";
$values = array("Orlando", "Dallas", "Atlanta", "Detroit", "Tampa", "Miami");

echo $result = str_replace($keyword, shuffle($values)?current($values):$values[0], $text);