C#如何随机化10个按钮（0-9）上的数字而不重复[重复]答案

【问题标题】：C# How to randomize the number on 10 buttons (0 - 9) without duplicates [duplicate]C#如何随机化10个按钮（0-9）上的数字而不重复[重复]
【发布时间】：2017-10-09 01:46:58
【问题描述】：

1.这就是我到目前为止所得到的

2.它应该在启动时随机化按钮上的数字。但它仍然会产生重复（而且我不想要重复）。

我为此使用 Visual Studio 2012 C#

只有在我启动程序后才应该这样做。所以它是一次性随机化

            Random rand = new Random();
            int RandomOne = rand.Next(0, 10);
            int RandomTwo = rand.Next(0, 10);
            int RandomThree = rand.Next(0, 10);
            int RandomFour = rand.Next(0, 10);
            int RandomFive = rand.Next(0, 10);
            int RandomSix = rand.Next(0, 10);
            int RandomSeven = rand.Next(0, 10);
            int RandomEight = rand.Next(0, 10);
            int RandomNine = rand.Next(0, 10);
            int RandomZero = rand.Next(0, 10);

            btnOneNgra.Text = Convert.ToString(RandomOne);


            if ((RandomTwo == RandomOne) || (RandomTwo == RandomNine) || (RandomTwo == RandomThree) || (RandomTwo == RandomFour)
                || (RandomTwo == RandomFive) || (RandomTwo == RandomSix) || (RandomTwo == RandomSeven) || (RandomTwo == RandomEight) || (RandomTwo == RandomZero))
            {
                RandomTwo = rand.Next(0, 10);
            }
            else 
            {
                btnTwoNgra.Text = Convert.ToString(RandomTwo);
            }


            if ((RandomThree == RandomOne) || (RandomThree == RandomTwo) || (RandomThree == RandomNine) || (RandomThree == RandomFour)
                || (RandomThree == RandomFive) || (RandomThree == RandomSix) || (RandomThree == RandomSeven) || (RandomThree == RandomEight) || (RandomThree == RandomZero))
            {
                RandomThree = rand.Next(0, 10);
            }
            else
            {
                btnThreeNgra.Text = Convert.ToString(RandomThree);
            }


            if ((RandomFour == RandomOne) || (RandomFour == RandomTwo) || (RandomFour == RandomThree) || (RandomFour == RandomNine)
                || (RandomFour == RandomFive) || (RandomFour == RandomSix) || (RandomFour == RandomSeven) || (RandomFour == RandomEight) || (RandomFour == RandomZero))
            {
                RandomFour = rand.Next(0, 10);
            }
            else
            {
                btnFourNgra.Text = Convert.ToString(RandomFour);
            }


            if ((RandomFive == RandomOne) || (RandomFive == RandomTwo) || (RandomFive == RandomThree) || (RandomFive == RandomFour)
                || (RandomFive == RandomNine) || (RandomFive == RandomSix) || (RandomFive == RandomSeven) || (RandomFive == RandomEight) || (RandomFive == RandomZero))
            {
                RandomFive = rand.Next(0, 10);
            }
            else
            {
                btnFiveNgra.Text = Convert.ToString(RandomFive);
            }


            if ((RandomSix == RandomOne) || (RandomSix == RandomTwo) || (RandomSix == RandomThree) || (RandomSix == RandomFour)
                || (RandomSix == RandomFive) || (RandomSix == RandomNine) || (RandomSix == RandomSeven) || (RandomSix == RandomEight) || (RandomSix == RandomZero))
            {
                RandomSix = rand.Next(0, 10);
            }
            else
            {
                btnSixNgra.Text = Convert.ToString(RandomSix);
            }


            if ((RandomSeven == RandomOne) || (RandomSeven == RandomTwo) || (RandomSeven == RandomThree) || (RandomSeven == RandomFour)
                || (RandomSeven == RandomFive) || (RandomSeven == RandomSix) || (RandomSeven == RandomNine) || (RandomSeven == RandomEight) || (RandomSeven == RandomZero))
            {
                RandomSeven = rand.Next(0, 10);
            }
            else
            {
                btnSevenNgra.Text = Convert.ToString(RandomSeven);
            }


            if ((RandomEight == RandomOne) || (RandomEight == RandomTwo) || (RandomEight == RandomThree) || (RandomEight == RandomFour)
                || (RandomEight == RandomFive) || (RandomEight == RandomSix) || (RandomEight == RandomSeven) || (RandomEight == RandomNine) || (RandomEight == RandomZero))
            {
                RandomEight = rand.Next(0, 10);
            }
            else
            {
                btnEightNgra.Text = Convert.ToString(RandomEight);
            }


            if ((RandomNine == RandomOne) || (RandomNine == RandomTwo) || (RandomNine == RandomThree) || (RandomNine == RandomFour)
                || (RandomNine == RandomFive) || (RandomNine == RandomSix) || (RandomNine == RandomSeven) || (RandomNine == RandomEight) || (RandomNine == RandomZero))
            {
                RandomNine = rand.Next(0, 10);
            }
            else 
            {
                btnNineNgra.Text = Convert.ToString(RandomNine);
            }


            if ((RandomZero == RandomOne) || (RandomZero == RandomTwo) || (RandomZero == RandomThree) || (RandomZero == RandomFour)
                || (RandomZero == RandomFive) || (RandomZero == RandomSix) || (RandomZero == RandomSeven) || (RandomZero == RandomEight) || (RandomZero == RandomNine))
            {
                RandomZero = rand.Next(0, 10);
            }
            else
            {
                btnZeroNgra.Text = Convert.ToString(RandomZero);
            }

【问题讨论】：

一种解决方案可能是将数字（0-9）添加到列表中，随机播放并选择一个随机索引，删除索引处的元素。重复。编辑：也许选择下一个索引 - 不是洗牌后的随机索引。
您需要在 while 循环中执行此操作，而不是单个 if 语句。如果您检查一次然后更改它，它可能会得到与另一个相同的值。
@Achilles 这当然是更好的解决方案。
你能给我一个我应该如何做的示例代码吗？我还是个学生，需要学习
@NoahDeGraaff 如果你需要学习，我建议你去尝试一下。从 SO 复制代码不会教你任何东西。

标签： c# random unique

【解决方案1】：

这种情况的方法应该是在一个列表中创建十个数字，然后一个一个地取以避免重复，如下所示：

List<int> nums = new List<int>(Enumerable.Range(0, 10));

private int getNumber(){
    Random rand = new Random();
    int index = rand.Next(0, nums.Count);
    int num = nums[index];
    nums.RemoveAt(index);
    return num;
}

你可能需要小心，它不能被调用超过 10 次......你可能想要创建小的错误处理程序，例如：

private int getNumber(){
    if(nums.Count >= 0)
        return -1; //means not available
    Random rand = new Random();
    int index = rand.Next(0, nums.Count);
    int num = nums[index];
    nums.RemoveAt(index);
    return num;
}

【讨论】：

我推荐使用Enumerable.Range(0, 9) 来生成数字列表。这样你就可以让它动态化。
@DavidG 好主意...因为第二个元素是count 我想我应该选择0,10
我认为.ToList() 看起来更好，但这也有效:)

【解决方案2】：

也许你应该尝试使用 HashSet：

HashSet<int> numbers = new HashSet<int>();
Random randomizer = new Random();

while (numbers.Count < 10)
{
   numbers.Add(randomizer.Next(0, 10));
}

HashSet 将确保所有值都是唯一的。

【讨论】：

它也会抛出一个异常并且不会给你从 0 到 9 的所有数字而不可能运行很长时间（从概率的角度来看）
不会抛出异常
好的，是的，它不会抛出异常，但循环会运行几十次不必要的次数。
对于信息，我已经测试了几次。有时它需要不到 20 个循环，有时它需要超过 100 个。