for 循环神秘地没有运行答案

【问题标题】：for loop mysteriously not runningfor 循环神秘地没有运行
【发布时间】：2022-01-18 18:47:56
【问题描述】：

代码：

var m = [
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█",
  "█","█","█","█","█","█","█","█"
];

for (var i = 0; i > m.length, i++;) {
  console.log(m[i]);
}

似乎 for 循环根本没有运行，因为在 console.log 中输入任何值都不会执行任何操作。

怎么了？

（另外，console.log(m) 本身输出 U+2588 很好。）

【问题讨论】：

m 看起来像什么？给我们一个包含五六个元素的样本。
检查你的循环条件。 MDN for loop

标签： javascript arraylist

【解决方案1】：

i > m.length 应该是 i < m.length，因为您正在尝试从 0 迭代到数组的长度

它的要点是你的迭代器 (i) 应该被初始化为 0（它是），但是你正在检查它是否大于比 m 的长度，这是大概大于0；所以因为你用零值初始化 i，然后检查它是否大于 m 的长度，所以无论 m 是否有任何成员，它总是评估为 false。

【讨论】：

对不起，没用。一无所获。
@silvxrcat 那是不可能的。

【解决方案2】：

i 必须小于 m.length，并且您的 for 语句中有几个语法错误。

const m = ['a','b','c']

for (let i = 0; i < m.length; i++) {
  console.log(m[i]); // m is a list of U+2588s.
}

【讨论】：

成功了！谢谢！
@silvxrcat 和你说的一样的答案没用？