如何使用 SlickGrid 插件在每一行上创建一个删除按钮？

Question

如何使用 SlickGrid 插件在每一行上创建一个删除按钮？我需要一个可以删除整个对应行的按钮。

Answer 1

使用您的列格式化程序来完成这项工作。

var column = {id:delCol, field:'del', name:'Delete', width:250, formatter:buttonFormatter}

//Now define your buttonFormatter function
function buttonFormatter(row,cell,value,columnDef,dataContext){  
    var button = "<input class='del' type='button' id='"+ dataContext.id +"' />";
    //the id is so that you can identify the row when the particular button is clicked
    return button;
    //Now the row will display your button
}

//Now you can use jquery to hook up your delete button event
$('.del').live('click', function(){
    var me = $(this), id = me.attr('id');
    //assuming you have used a dataView to create your grid
    //also assuming that its variable name is called 'dataView'
    //use the following code to get the item to be deleted from it
    dataView.deleteItem(id);
    //This is possible because in the formatter we have assigned the row id itself as the button id;
    //now assuming your grid is called 'grid'
    grid.invalidate();        
});

Answer 2

使用 jQuery 绑定到 click 事件的另一种方法是使用 SlickGrid 的 onClick 事件。类似于（现已弃用）jQuery .live() 或现在 .on() 与委托处理程序，使用 onClick 将允许功能工作，而无需在添加、删除、显示新行等时不断重新附加处理程序。

增强吉比的例子，将$('.del').live('click', function(){...替换为以下内容：

// assuming grid is the var name containing your grid
grid.onClick.subscribe( function (e, args) {
    // if the delete column (where field was assigned 'del' in the column definition)
    if (args.grid.getColumns()[args.cell].field == 'del') {
       // perform delete
       // assume delete function uses data field id; simply pass args.row if row number is accepted for delete
       dataView.deleteItem(args.grid.getDataItem(args.row).id);
       args.grid.invalidate();
    }
});