【发布时间】：2019-02-08 10:35:25
【问题描述】：
我以对象数组的形式从后端获取响应，并将响应存储在数组列表中，我想从 ArrayList 中检索特定字段值并将其附加到列表视图。
这是我的代码：
Retrofit retrofit = builder.build();
APIService apiservice = retrofit.create(APIService.class);
Call<PostData> call = apiservice.transactiondetails(UID);
call.enqueue(new Callback<PostData>() {
@Override
public void onResponse(@NonNull Call<PostData> call, @NonNull Response<PostData> response) {
if (response.code() == 200) { // this is the case for success
if (response.isSuccessful()) {
response.body();
// ArrayList dp = new HashMap<String, Array>();
// dp = Objects.requireNonNull(response.body()).getToken1();
ArrayList dp = Objects.requireNonNull(response.body()).getToken1();
Log.d(TAG, String.valueOf(dp));
System.out.println("hash map is" + dp);
Intent i = new Intent(deyaPay.this, TransactionDetails.class);
i.putExtra("Transactiondetails",dp);
startActivity(i);
Toast.makeText(deyaPay.this, "success" + dp, Toast.LENGTH_SHORT).show();
//Toast.makeText(getApplicationContext(), dp, Toast.LENGTH_LONG).show();
}
}
and this is class for getting the response from backend:
public class PostData {
@SerializedName("Token")
@Expose
private String token;
public String getToken() {
return token;
}
public void setToken(String token) {
this.token = token;
}
@SerializedName("Details")
@Expose
private Map<String,Array> token1;
public Map<String, Array> getToken1() {
return token1;
}
public void setToken1(Map<String,Array> token1) {
this.token1 = token1;
}
}
那么如何将响应附加到列表视图，这是我来自后端的响应：
[
{
Amount = 4;
TransactionID = deyaPay;
method = "Money Sent using deyaPay";
timestamp = "2018-09-03T06:01:41.306Z";
},
{
Amount = 2;
Token = "tok_1D69olLMFuWYhKXrAqwmTprz";
TransactionID = "ch_1D69omLMFuWYhKXrYpbNEtGH";
method = "Requested by";
timestamp = "2018-09-03T04:37:40.147Z";
},
{
Amount = 5000;
TransactionID = deyaPay;
method = "Money Sent using deyaPay";
timestamp = "2018-09-03T04:01:00.565Z";
},
{
Amount = 50;
TransactionID = deyaPay;
method = "Money Sent using deyaPay";
timestamp = "2018-09-03T03:59:01.708Z";
},
{
Amount = 2;
TransactionID = deyaPay;
method = "Money Sent using deyaPay";
timestamp = "2018-09-03T03:58:26.964Z";
},
{
Amount = 1;
Token = "tok_1D68nBLMFuWYhKXrGM2AN2IF";
method = "Add Money to deyaPay account using credit card/debit card";
timestamp = "2018-09-03T03:31:58.008Z";
},
{
Amount = 5;
Token = "tok_1D68cpLMFuWYhKXrM7oc2X7j";
method = "Add Money to deyaPay account using credit card/debit card";
timestamp = "2018-09-03T03:21:16.281Z";
},
{
Amount = 2;
Token = "tok_1D5pE1LMFuWYhKXr9BMvQ1dm";
method = "Add Money to deyaPay account using credit card/debit card";
timestamp = "2018-09-02T06:38:22.188Z";
},
{
Amount = 2;
Token = "tok_1D5pCxLMFuWYhKXrJoRcbN8o";
method = "Add Money to deyaPay account using credit card/debit card";
timestamp = "2018-09-02T06:37:16.393Z";
}]
【问题讨论】：
-
不是有效的 JSON。
-
这是一个有效的 json 。你怎么说它不是有效的json？在 IOS 中可以将这些响应附加到表 View 中。但在 android 中
-
[{ "Amount": 4, "TransactionID": "deyaPay", "method": "Money Sent using deyaPay", "timestamp": "2018-09-03T06:01:41.306Z" }]这是有效且可解析的。您的回复有;和=，因此无法将其解析为对象。 -
@vijju 刚刚复制了您的回复并将其粘贴到 json.parser.online.fr 上。 ...它清楚地表明它是无效的..请检查一次
-
如果它在 IOS 中工作，他们不会将其视为
JSON可能是别的东西。