我怎样才能结合这个 Laravel Collection 排序？

Question

这是我目前拥有的：

    use Illuminate\Support\Collection;

    $order = ['Land', 'Planeswalker', 'Creature', 'Instant', 'Sorcery', 'Enchantment', 'Artifact'];
    $landOrder = ['Basic', ''];

    $deck = $deck->sortBy(function($card) use ($landOrder) {
        foreach ($landOrder as $index => $supertypes) {
            if (str_contains($card->supertypes, $supertypes)) {
                return $index;
            }
        }
    })->values();

    $deck = $deck->sortBy(function($card) use ($order) {
        foreach ($order as $index => $type) {
            if (str_contains($card->types, $type)) {
                return $index;
            }
        }
    })->values();

基本上我想先按 $order 排序，然后根据 $landOrder 调整顺序。

目前它按第二个执行的函数排序。我怎样才能使它对两者都进行排序？

Answer 1

我会使用sort 方法而不是sortBy。 sort 方法使用 PHP 的 uasort 函数，它可以让您更好地控制排序功能。

$deck->sort(function($a, $b) use ($order, $landOrder) {
    // get the order indexes for the two items
    $ai = array_search($a->types, $order);
    $bi = array_search($b->types, $order);

    // if the two items have the same order, drill down to the land order comparison
    if ($ai === $bi) {
        // get the land order indexes for the two items
        $aii = array_search($a->supertypes, $landOrder);
        $bii = array_search($b->supertypes, $landOrder);

        // order based on "natural order" comparison of land order indexes
        return strnatcmp($aii, $bii);
    }

    // order based on "natural order" comparison of order indexes
    return strnatcmp($ai, $bi);
})->values();

编辑

您需要更新函数以实现从$order 和$landOrder 数组中获取正确索引所需的任何逻辑。我只是将array_search() 用作一个快速简便的函数，但这假设types 和supertypes 属性的值将与数组中的条目完全匹配（即“土地”和“基本”，而不是'["Land"]' 和 '["Basic"]')。

根据您的问题的逻辑以及您的 cmets 的属性格式，您可能正在寻找类似这样的内容：

$deck->sort(function($a, $b) use ($order, $landOrder) {
    // get the order indexes for the two items
    $ai = null;
    $bi = null;
    foreach ($order as $index => $type) {
        if (str_contains($a->types, $type)) {
            $ai = $index;
        }
        if (str_contains($b->types, $type)) {
            $bi = $index;
        }
    }
    // if the type is not in the array, assign some type of value that will order like types together, but after all other proper types
    if (is_null($ai)) {
        $ai = count($order).$a->types;
    }
    if (is_null($bi)) {
        $bi = count($order).$b->types;
    }

    // if the two items have the same order, drill down to the land order comparison
    if ($ai === $bi) {
        // get the land order indexes for the two items
        $aii = null;
        $bii = null;
        foreach ($landOrder as $index => $supertype) {
            if (str_contains($a->supertypes, $supertype)) {
                $aii = $index;
            }
            if (str_contains($b->supertypes, $supertype)) {
                $bii = $index;
            }
        }
        // if the supertype is not in the array, assign some type of value that will order like supertypes together, but after all other proper supertypes
        if (is_null($aii)) {
            $aii = count($landOrder).$a->supertypes;
        }
        if (is_null($bii)) {
            $bii = count($landOrder).$b->supertypes;
        }

        // order based on "natural order" comparison of land order indexes
        return strnatcmp($aii, $bii);
    }

    // order based on "natural order" comparison of order indexes
    return strnatcmp($ai, $bi);
})->values();